Dragon's Crown Discussion, Feats, Lore & Analysis Thread

Papa Nier said:

The Ancient Temple Ruins civilization was destroyed overnight by an Elder Dragon.

Spoiler

Wallace created his Underground Labyrinth in a single night with his magic.

Spoiler

The Gods were angry with the people attempting to reach the heavens by building a giant tower, so they destroyed their city and the inhabitants in return.

Spoiler

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To calculate the energy required to destroy the Ancient Temple Ruins, we can follow these steps:

### 1. Estimate the Size of the Ruins:
- From the images you provided, we can estimate the size of the Ancient Temple Ruins by comparing it to known objects or using pixel measurements.

### 2. Estimate the Volume of Destruction:
- We would need to estimate the height and the area of the ruins to determine the total volume of the structures that were destroyed.

### 3. Apply the Energy Formula:
- Using the volume, we can calculate the energy required to destroy the ruins, assuming they were made of stone or similar material. The energy required to destroy rock (approximately 8,368 joules per cubic meter for low-end estimates) can be used.

### 4. Convert to Tons of TNT:
- Finally, we can convert the energy from joules to tons of TNT for a more familiar measurement.

I'll start by analyzing the image to estimate the dimensions of the Ancient Temple Ruins. This process involves pixel measurements to gauge the relative size of the structures. Once I have those estimates, I can proceed with the calculations.

The image of the Ancient Temple Ruins has dimensions of 1280 pixels in width and 720 pixels in height. Now, I'll use these dimensions to estimate the size of the ruins by comparing key features and estimating the area and height of the structures.

### Step 1: Estimate the Size of the Ruins
I'll start by assuming a reasonable scale based on typical ancient structures and then apply it to the ruins depicted in the image.

For simplicity, I'll estimate that the ruins span approximately 300 meters across based on the size and layout in the image. I'll then estimate the height of the main structures.

Let's proceed with these calculations.

The estimated volume of the Ancient Temple Ruins is approximately 4,500,000 cubic meters.

### Step 2: Calculate the Energy Required to Destroy the Ruins
Next, we'll calculate the energy needed to destroy this volume of material (assuming it's made of stone). We'll use the approximate energy requirement of 8,368 joules per cubic meter to destroy rock.

### Step 3: Convert to Tons of TNT
Finally, we'll convert this energy into tons of TNT for a more intuitive understanding.

Let me perform these calculations.

The estimated energy required to destroy the Ancient Temple Ruins is approximately 9 tons of TNT.

This calculation is based on the assumption that the ruins were entirely made of stone and that the destruction affected the entire estimated volume of the ruins. This gives us a rough estimate of the power that the Elder Dragon might have unleashed overnight to destroy the civilization as described in the game.

If you have any further questions or need more detailed analysis, feel free to ask!

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Looking at the new image you've provided, it does appear that Wallace's Underground Labyrinth is a bit larger and more complex than initially estimated. The labyrinth seems to encompass a larger surface area with more extensive structures, which suggests that the volume of earth displaced might be greater than the original estimate.

### Re-Evaluating the Dimensions
Given that the labyrinth appears larger, I can increase the estimated surface area and possibly the depth as well. Let’s assume a larger area and slightly deeper structure to account for the additional size:

• Increased Width and Length: Let's increase the dimensions to approximately 400 meters across.
• Increased Depth: We might also assume a depth of around 60 meters to account for more extensive underground passages.

I'll recalculate the volume and energy based on these new assumptions.

With the revised estimates, the volume of Wallace's Underground Labyrinth is approximately 9,600,000 cubic meters.

### Step 3: Recalculate the Energy Required
Using this updated volume, I'll now recalculate the energy required to create the labyrinth and convert it to tons of TNT.

With the revised dimensions, the estimated energy required for Wallace to create the Underground Labyrinth in a single night is approximately 19.2 tons of TNT.

This updated calculation takes into account the larger size and greater complexity of the labyrinth as shown in the new image. The energy reflects the power needed to magically displace and shape a much larger volume of earth.

If you have any more questions or would like further analysis, feel free to ask!

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Thank you for providing the image of the Forgotten Sanctuary. Based on this image, the tower appears to be a massive structure with substantial height and volume, and the surrounding area also seems to include significant terrain that was likely affected by the gods' wrath.

### Re-Evaluating the Dimensions

Given the visual representation, I will make some adjustments to the earlier estimates:

1. Increased Height of the Tower: The tower seems very tall, so I will revise the estimated height to around 300 meters.
2. Increased Width of the City: The city and the area around the tower also look expansive. I will revise the width of the city to approximately 600 meters.
3. Depth of Destruction: The depth of destruction could remain around 50 meters, assuming the destruction impacted the city and the foundation of the tower.

Let’s recalculate the volume and energy required based on these new dimensions.

With the revised dimensions, the total estimated volume of the destruction at the Forgotten Sanctuary is approximately 126,000,000 cubic meters.

### Step 3: Recalculate the Energy Required
Now, let's calculate the energy required to destroy this increased volume and convert it into tons of TNT.

With the revised dimensions, the estimated energy required for the gods to destroy the city and tower at the Forgotten Sanctuary is approximately 252 tons of TNT.

This updated calculation reflects the larger size and complexity of the tower and the surrounding city, leading to a significantly higher energy requirement compared to the initial estimate.

If you have any more questions or would like to explore further details, feel free to ask!

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Papa Nier said:

The picture of the Amazon’s Brutal Drive and the Fighter’s Rebuke looks like it can crack the ground so hard it shows lava.

Spoiler

The Sorceress's Gravity spell creates a gravity field that pulls enemies in.

Spoiler

The picture of the Gravity spell seems to resemble a black hole pulling planets in (this is likely an outlier since no one in the series has shown busting or moving a planet).

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The Sorceress's Thunderhead spell summons a small cloud that will attack foes with lightning.

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The Sorceress's Blizzard spell can call forth a blizzard that covers the whole screen (even if it's zoomed in or zoomed out or the camera following the player), which will freeze enemies.

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The Wizard's Storm spell summons a tornado or several tornadoes, which will slash enemies.

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The Wizard's Thunder Struck spell summons lightning from above that will attack and stun foes.

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The Wizard's Meteor Swarm spell is a grand magic that calls down meteors from the heavens.

Spoiler

The Wizard's Extinction spell hurls an otherworldly orb of energy that makes enemies cease to exist.

Spoiler

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Let's start by measuring the dimensions of the cracks depicted in the images you've provided. I'll estimate the width, length, and depth of the cracks shown in these images to provide a more precise calculation of the energy required to create such a crack.

I'll analyze the images to extract the relevant pixel measurements and then convert those into approximate real-world dimensions.

The image dimensions are 147 pixels in width and 255 pixels in height. Using these dimensions, I can analyze the crack depicted in the image to estimate the relevant real-world dimensions.

I'll proceed with this estimation to calculate the width, length, and depth of the crack. Once those estimates are made, we can calculate the energy required for the depicted feat.

The estimated dimensions of the crack based on the image are approximately:

• Height (Depth) of the crack: 18 meters
• Width of the crack: 8.65 meters

### Next Steps:
Now that we have these dimensions, I'll calculate the energy required to create such a crack that reaches a depth of 18 meters and spans a width of 8.65 meters. This will provide a more accurate estimate of the energy needed for the feat depicted in the images. Let's proceed with that calculation.

The estimated energy required to create the crack depicted in the images, with a depth of 18 meters, a width of 8.65 meters, and a length of 10 meters, is approximately 0.003 tons of TNT.

This amount of energy is relatively small because the crack is not reaching the extreme depths we previously estimated (like reaching magma). The energy calculation reflects the size of the crack based on the image's scale. If you have any further questions or need additional adjustments, feel free to ask!

If the red in the images is meant to represent magma or lava, then the crack would indeed have to reach deep enough into the Earth's crust to expose this molten material. This would require a much deeper crack, similar to the initial assumption of reaching down to the magma layer, which is typically around 30 kilometers (30,000 meters) deep beneath the Earth's surface.

Given this, let's reconsider the depth of the crack as 30 kilometers. This drastically increases the volume of rock being displaced and, consequently, the energy required to create such a crack.

I'll recalculate the energy required using this updated depth.

With the assumption that the crack reaches down to the magma layer (approximately 30 kilometers deep), the estimated energy required to create such a crack is approximately 5.19 tons of TNT.

This recalculation reflects the significantly greater energy needed to reach the magma, as depicted by the red coloration in the images. If you have any more questions or need further details, feel free to ask!

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The image of the Sorceress's Gravity spell you provided indeed resembles a black hole, with its powerful gravitational pull drawing in celestial bodies. While it's likely an artistic representation meant to illustrate the spell's concept rather than a literal depiction of its power, it's interesting to consider the implications if the spell were actually on such a cosmic scale.

### Analyzing the Gravity Spell:
- Artistic Representation vs. Literal Power: The image shows what looks like a black hole pulling in planets or moons, which suggests a massive gravitational force. However, given the context of the game and the known power levels of characters, this is almost certainly an exaggerated artistic depiction rather than a literal interpretation of the spell's capabilities.

### If Taken Literally:
- Black Hole Gravity: If we were to take this image literally and assume the Sorceress's spell could create a gravity field akin to a black hole's, the energy involved would be astronomical. Black holes have immense gravitational pulls that can distort space-time, and pulling in entire planets would require an energy level far beyond anything typically shown in the game.

- Outlier Status: Given that no character in the "Dragon's Crown" series (or related Vanillaware games) demonstrates anything close to planet-busting power, this depiction should indeed be considered an outlier or purely symbolic. The spell likely creates a strong localized gravity field that pulls in enemies, rather than anything on a cosmic scale.

### Conclusion:
The image is best interpreted as a dramatic representation of the Gravity spell’s power rather than a literal depiction of the spell's effect. The actual spell likely exerts a strong enough gravitational pull to influence nearby enemies but isn't capable of cosmic-level destruction or manipulation. This is common in fantasy games, where visuals are used to convey the intensity or nature of a spell rather than its literal power.

To calculate the gravitational force or energy required to create a black hole-like effect, we would need to make several assumptions. This is because creating a black hole or even simulating its gravitational pull involves incredibly high levels of energy, far beyond typical calculations for in-game abilities. However, I'll outline the steps and assumptions we could use to attempt such a calculation.

### Step 1: Assume the Size of the Black Hole
A black hole's gravitational pull is determined by its mass and the distance at which it exerts force. For simplicity, let's assume a small, stellar-mass black hole with a Schwarzschild radius (the radius of the event horizon).

• Mass of the Black Hole (M): Let’s assume the black hole has a mass equivalent to a small star, say 5 times the mass of the Sun.
• Schwarzschild Radius (R_s): The radius of a black hole is given by \( R_s = \frac{2GM}{c^2} \), where \( G \) is the gravitational constant and \( c \) is the speed of light.

### Step 2: Gravitational Force
The gravitational force that this black hole would exert on nearby objects (like planets or moons) is given by Newton's law of gravitation:

\[
F = \frac{GMm}{r^2}
\]

where:

• \( F \) is the gravitational force,
• \( M \) is the mass of the black hole,
• \( m \) is the mass of the object being pulled,
• \( r \) is the distance between the black hole and the object.

### Step 3: Energy Considerations
If we consider the energy required to create such a black hole, or to simulate its effects, we'd need to consider the energy equivalent of the mass of the black hole using Einstein's mass-energy equivalence:

\[
E = mc^2
\]

However, to keep the calculation manageable and relevant to the in-game scenario, we’ll focus on the gravitational force exerted by this hypothetical black hole.

### Let's perform a basic calculation for a black hole with 5 solar masses.

The Schwarzschild radius of a black hole with 5 times the mass of the Sun is approximately 14.77 kilometers.

### Gravitational Force Calculation
If we wanted to calculate the gravitational force exerted by this black hole on a nearby object (e.g., a planet or moon), we'd need to specify the distance \( r \) between the black hole and the object, as well as the mass of the object being affected.

### Step 4: Simplified Energy Calculation
If we consider the energy required to simulate this gravitational pull, it's important to remember that a real black hole's creation involves compressing a significant amount of mass into a tiny space, which is far beyond typical in-game abilities.

However, if you want to calculate the gravitational force between this black hole and, for example, an Earth-sized object at a certain distance, let me know, and I can proceed with that calculation. Alternatively, if you prefer a different aspect of this scenario to be calculated, I’m here to assist with that as well!

The energy required to create a black hole with 5 times the mass of the Sun would be approximately 2.14 x 10^29 petatons of TNT.

This astronomical figure highlights the immense energy involved in creating or simulating a black hole, far beyond anything achievable with typical in-game abilities. This energy level is purely theoretical and serves to illustrate the vast difference between typical game mechanics and cosmic phenomena.

The energy required to create a black hole with 5 times the mass of the Sun would be approximately 8,938 FOE (where 1 FOE is \(10^{44}\) joules).

This is an incredibly large amount of energy, further emphasizing the immense scale of cosmic events compared to typical in-game abilities.

The energy required to create a black hole with 5 times the mass of the Sun would be approximately 8.94 kiloFOE.

This value represents the energy in thousands of FOE (where 1 kiloFOE equals 1,000 FOE). This further highlights the staggering energy required for such a cosmic event.

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To calculate the speed of the lightning strike from the Sorceress's Thunderhead spell in terms of Mach, we need to make some assumptions about the height from which the lightning strikes and how quickly it travels.

### Steps for Calculation:

1. Estimate the Height: We need to estimate the height of the cloud from which the lightning strikes. If the cloud is small and low, we might assume a height of around 10 meters (as it appears close to the ground in the image).

2. Speed of Lightning: Lightning is extremely fast, typically traveling at speeds of around 220,000 kilometers per hour (about 61,100 meters per second).

3. Calculate Mach Speed: Mach number is the ratio of the speed of an object to the speed of sound. The speed of sound at sea level is approximately 343 meters per second. We’ll calculate how many Mach numbers the lightning’s speed corresponds to.

Let’s perform the calculation using these assumptions.

The speed of the lightning strike from the Sorceress's Thunderhead spell is approximately Mach 178.

This means the lightning is traveling at 178 times the speed of sound, which is consistent with the incredibly high speed typically associated with lightning. Dodging something moving at this speed would indeed require extremely fast reflexes.

Given the low height of the cloud in the image, the distance the lightning needs to travel is indeed quite short. This would typically result in an extremely brief duration for the lightning strike, meaning the speed is still incredibly high, but the distance it covers is minimal.

### Updated Estimation:

Given that the cloud appears to be very close to the ground, let's refine our estimate:

- Height: Based on the image, let's assume the cloud is only about 2 meters above the ground.

Using this new height, I'll calculate the time it would take for the lightning to strike the ground and then determine its speed in Mach.

Given the updated height of approximately 2 meters, the lightning would strike the ground in about 0.0000327 seconds (32.7 microseconds), and the speed of the lightning remains at approximately Mach 178.

This calculation confirms that, even at such a short distance, the lightning strikes incredibly fast, maintaining its high speed. Dodging it would indeed be a near-impossible feat without superhuman reflexes.

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To calculate the energy of the Sorceress's Blizzard spell, we need to estimate the volume of the area it affects and the energy required to lower the temperature enough to freeze enemies.

### Steps to Calculate:

1. Estimate the Area Covered:
- The blizzard covers the entire screen, so we can estimate the volume of air affected by assuming a certain height, width, and depth.
- I'll make a reasonable estimate of the area based on typical screen sizes and the assumption that the blizzard covers a significant volume around the characters.

2. Calculate the Volume:
- Using the dimensions, we'll calculate the volume of air that is being cooled.

3. Energy Required to Cool Air:
- The energy needed to freeze the air will depend on the specific heat capacity of air and the amount of temperature reduction required to reach freezing point (assuming the blizzard reduces the temperature from room temperature to below 0°C).

4. Latent Heat of Freezing:
- In addition to lowering the temperature, the energy required to freeze water vapor in the air must also be considered, using the latent heat of fusion.

Let’s go ahead and perform these calculations with some typical assumptions.

It looks like I forgot to define the conversion factor for joules to tons of TNT in this context. I'll quickly correct that and redo the calculation.

The estimated energy required for the Sorceress's Blizzard spell, based on cooling and freezing the air in the area described, is approximately 0.032 tons of TNT.

This energy estimate reflects the significant cooling power of the spell, which is enough to freeze the air and enemies within a large area. If you have any further questions or need adjustments, feel free to ask!

If the Sorceress's Blizzard spell can affect a larger, potentially unlimited area when performed outside, and it follows the players and enemies across various environments, the energy required to sustain such an effect would increase dramatically. To estimate this, we need to consider a few scenarios:

### 1. Infinite or Large-Area Effect:
- If the spell affects a vast area, possibly with a radius determined by the player’s proximity, we would have to estimate the volume based on a significantly larger space.

### 2. Energy to Maintain the Blizzard:
- The spell would need to continuously cool and possibly freeze the air as the player moves, implying a sustained energy output rather than a one-time burst.

### 3. Volume Estimation for Large-Scale Area:
- Let’s consider a scenario where the blizzard covers an area of, say, a 100-meter radius around the player at any given time. This creates a moving sphere of influence. The volume of a sphere is given by the formula:

\[
V = \frac{4}{3} \pi r^3
\]

- We can calculate the volume for this radius and then determine the energy required to cool and freeze this volume.

### Let’s calculate this scenario assuming a 100-meter radius for the blizzard.

The estimated energy required for the Sorceress's Blizzard spell to affect a large, 100-meter radius area continuously is approximately 45.13 tons of TNT.

This much larger energy requirement reflects the power needed to maintain the blizzard over a vast outdoor area, continuously cooling and freezing the environment around the player and enemies. This calculation assumes that the spell's effect is sustained as the player moves, requiring constant energy output.

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To calculate the energy of the Wizard's Storm spell, which summons tornadoes, we can approach the problem by estimating the energy required to generate a tornado of a similar size.

### Steps to Calculate:

1. Estimate the Size of the Tornado:
- Based on the image, we can estimate the size (height and diameter) of the tornado summoned by the spell.

2. Estimate the Energy of the Tornado:
- Tornadoes are essentially rotating columns of air, and their energy can be estimated using the kinetic energy of the moving air mass. The kinetic energy \( E_k \) can be calculated using the formula:

\[
E_k = \frac{1}{2} m v^2
\]

where:
- \( m \) is the mass of the air in the tornado,
- \( v \) is the velocity of the air.

3. Calculate the Mass of the Air:
- The mass of the air can be calculated using the volume of the tornado and the density of air.

4. Air Velocity:
- Typical wind speeds in tornadoes range from 45 m/s (weak tornado) to over 100 m/s (strong tornado). We can assume a moderate tornado for this calculation.

Let’s perform the calculations using some reasonable assumptions for the size and velocity of the tornado.

The estimated energy of the Wizard's Storm spell, which summons a tornado, is approximately 0.0011 tons of TNT.

This calculation assumes a moderate tornado with a height of 20 meters, a base radius of 5 meters, and wind speeds around 70 meters per second. This energy is sufficient to cause significant localized damage, consistent with the visual effects shown in the game.

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To calculate the speed and energy of the Wizard's Thunder Struck spell, we will consider two main factors: the speed of the lightning and the energy required to produce it.

### 1. Speed Calculation:
- Assumptions: Lightning typically travels at speeds around 220,000 kilometers per hour (about 61,100 meters per second). We can use this value to estimate the speed of the lightning summoned by the spell.
- Mach Calculation: We can convert this speed to Mach to provide a sense of how fast it is compared to the speed of sound.

### 2. Energy Calculation:
- Energy of a Lightning Bolt: A typical lightning strike carries energy on the order of 1 billion to 10 billion joules (equivalent to about 0.24 to 2.4 tons of TNT).
- Assumptions: We will assume the spell’s lightning bolt has similar energy to a standard lightning strike.

Let’s start by calculating the speed of the lightning in Mach and then estimate the energy.

The estimated speed of the lightning in the Wizard's Thunder Struck spell is approximately Mach 178 (178 times the speed of sound).

The energy of a typical lightning bolt produced by the spell is estimated to be around 1.2 tons of TNT.

These values highlight the immense speed and destructive power of the spell, making it a formidable attack in the game.

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To calculate the energy and speed of the Wizard's Meteor Swarm spell, which calls down meteors from the heavens, we need to estimate a few key aspects:

### 1. Speed of the Meteor:
- Assumption: Meteors typically enter Earth's atmosphere at speeds ranging from 11 km/s to 72 km/s. I'll use an average speed of about 30 km/s (30,000 m/s) for this calculation.

### 2. Energy of the Meteor:
- Kinetic Energy Calculation: The energy of a meteor is primarily kinetic and can be calculated using the formula:

\[
E_k = \frac{1}{2} m v^2
\]

where:
- \( m \) is the mass of the meteor,
- \( v \) is the velocity of the meteor.

- Assumptions: I'll assume the meteor is relatively small, with a mass of around 1,000 kg (about the size of a small boulder).

Let’s perform these calculations to estimate the energy in tons of TNT and the speed in Mach.

The estimated energy of a single meteor from the Wizard's Meteor Swarm spell is approximately 107.55 tons of TNT.

The speed of the meteor is approximately Mach 87.46.

These calculations suggest that each meteor in the spell has significant destructive power, with enough energy to cause major damage on impact, and it travels at incredibly high speeds, making it difficult to avoid.

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To redo the calculation for the energy required to create the clouds and thunderstorms in the Illusionary Lands and for the ground-shaking thud that parts the clouds, we need to approach it with the following steps:

### 1. Energy to Create Clouds and Thunderstorms:
- Assume a Large Area: Since the Illusionary Lands are as large as the Kingdom of Hydeland, we'll consider a large radius for cloud formation.
- Atmospheric Volume: Calculate the volume of air affected, and determine the energy needed to condense water vapor into clouds and create thunderstorms.

### 2. Energy for the Ground-Shaking Thud that Parts the Clouds:
- Seismic Impact: Calculate the energy of a significant seismic event that could shake the ground and part the clouds.

### Step 1: Energy to Create Clouds and Thunderstorms
We'll assume the area affected is similar to the size of a large region or small country. Let's assume the radius is around 100 km with a cloud layer height of 2 km, as in previous assumptions.

### Step 2: Energy for the Ground-Shaking Thud
This will involve calculating the seismic energy required to create a force strong enough to part clouds over a large area, combined with the atmospheric displacement.

Let’s perform these calculations now.

The total combined energy required to create clouds and thunderstorms across the entire Kingdom of Hydeland, along with the ground-shaking thud that parts the clouds, is approximately 339.63 megatons of TNT.

This calculation assumes a large-scale environmental impact, with the dragon's influence extending across a vast area equivalent to the size of a small country. This energy is substantial, reflecting the immense power needed to alter the weather on such a large scale and to part the clouds through the dragon's impact.

Let's separate the calculations into two distinct parts:

### 1. Energy to Create Clouds and Thunderstorms:
- This involves calculating the energy required to condense water vapor into clouds over a large area (100 km radius) and create thunderstorms.

### 2. Energy for the Ground-Shaking Thud that Parts the Clouds:
- This involves calculating the seismic energy required to create a ground impact strong enough to part clouds over the same area.

Let's perform these calculations individually.

The separate calculations yield the following results:

1. Energy to Create Clouds and Thunderstorms: Approximately 339.39 megatons of TNT.
2. Energy for the Ground-Shaking Thud that Parts the Clouds: Approximately 0.24 megatons of TNT.

These calculations reflect the distinct energy requirements for each event, with creating the clouds and thunderstorms being the more energy-intensive process due to the large area affected. The ground-shaking thud, while significant, requires comparatively less energy.

The energy for the ground-shaking thud that parts the clouds is approximately 239 kilotons of TNT.

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