1.Emerald Splash
requested by brightsteel (bartimaeus sequence)
3 feets=0.914 meters
shapping it like a cylinder
600479.9812772305 cc
i will use both pulverization(214j/cc) and vaporization(25700j/cc) of rock since there is flames involved
E(LE)=600479.9812772305 x 214
E(HE) 600479.9812772305 x 25700
E(LE)=128 502 716 joules
E(HE)=1.54323355e+10 joules
2.Faildramon is way better than you (digimon 02 )
requested by...let's say jag i guess ?
this fits really well with failldramon who gets scalled to country level shit from much weaker character and would establish a really welcome boost for FM tier characters (even more because diaboromon no sold giga death)
3.For such a little body she sure as hell eats (C)
requested by TheBlueDash
4.What a mess (gantz)
because someone asked me about x guns power
how is this a feat again (rwby)
requested by jamrock
requested by brightsteel (bartimaeus sequence)
i'll assume diameter=deepth which is fine given this guy is sitting inside the crater
3 feets=0.914 meters
shapping it like a cylinder
600479.9812772305 cc
i will use both pulverization(214j/cc) and vaporization(25700j/cc) of rock since there is flames involved
E(LE)=600479.9812772305 x 214
E(HE) 600479.9812772305 x 25700
E(LE)=128 502 716 joules
E(HE)=1.54323355e+10 joules
2.Faildramon is way better than you (digimon 02 )
requested by...let's say jag i guess ?
on his transformation sequence imperiadramon uses his mega crusher
[YOUTUBE]0ns0Ed_klGc[/YOUTUBE]
here is mega crusher note
this is further backed up by the fact imperialdramon has a positronic laser which is antimatter and the lore specifically mentions antimatter annihilating stuff
although the fact it is just a tranformation sequence makes it doubtful if i ever find another scene with something similar to backup i may go with this one
now let's get to the feat
castle window is 6 px (1.5 m)
castle wall diameter=185.93 px (46.4825 m)
claste wall thickness 8 px (2m)
castle wall height is 60 px (15px)
castle building height is 110.819 px (27.70 m)
castle main building diameter is 44.94 px (11.235 m)
now i will shape the castle wall as a circular crown
area of a circular crown is radius of wall x pi - empty radius
we know the radius of the wall is half its diameter
making it 23.24125 m
the wall thickness is 2 meters
which means the empty radius is 21.24125
A=(23.24125 x pi) - (21.24125 x pi)
A=6.28318 m^2
now for volume we just multiply by height of wall
V=6.28318 x 15
V=94.2477 m^3
now for the main building i will shape it like like a cylinder
making its volume 2746.1 m^3
i will multiply by 5 since there are many other towers within the castle
but i also need to account for hollowness mulplying by 0.2
so instead i will just not account for it
making the total volume= 2746.1 + 94.2477= 2840.3477 m^3
concrete density is 2400 kg/m^3
M=2840.3477 x 2400
M=6816834.48 kg
tree height is 73 px (18.25 m)
tree diameter is 5px (1.25 m)
here we have an area of 400 x 578 px
100 x 144.= 14450 m^2
let's say there is 50 trees or so
meaning the density of tree population is 1 per 289 m^2
keep in mind this is most definitely a low end due to existing a castle here
now how big was the explosion range
nothing too significant but i guess it is worthy to do the comparation
2*atan(tan(70/2 deg))*(570/367)=108.719346 deg for pov 2*atan(20/(570/tan((108.719346deg)/2)))=5.60331996 deg
186.46 meters
i was going to take faildramon into account but i realised the sphere went after his position in panel
i was going to do angsizing but i realized this is an omnidirectional sphere and thus actual scalling is far superior
sphere diameteris 570px (520.125 m)
tree is 20px (18.25 m)
surface area is pir^2
SA=212473.777416 m^2
ratio is 1 tree per 289m^2
which gives me 735 trees
tree volume will be a cylinder
making it 22.39611950313036 m^3
now we multiply by number of trees
735 x 22.39611950313036
16461.1478348 m^3
the density of a pine red is around 500 kg/m^3
Mass= 16461.1478348 x 500
Mass=8230573.9174kg
total mass=6816834.48 + 8230573.9174
TM=15047408.3974 kg
E=mc^2
E=1.35239362 ? 10^24 joules
i will do one more approach regardless
the mega crusher was still annhilating trees at the edge of the explosion the surface area of those trees is 153.15264186250243 m^2
making a ratio between explosion surface area and tree surface area i get
212473.777416/153.15264186250243=1387.3334 times boost
the annhlation of a single tree is
E=22.39611950313036 x 500 x c^2
E=1.00643142 ? 10^21
TE=1387.3334 x 1.00643142 ? 10^21
TE=1.3962559e+24 joules
giga crusher is stated to have 10 times its potency
[YOUTUBE]0ns0Ed_klGc[/YOUTUBE]
here is mega crusher note
so basically anything that is hit by this attack gets annhililated
this is further backed up by the fact imperialdramon has a positronic laser which is antimatter and the lore specifically mentions antimatter annihilating stuff
although the fact it is just a tranformation sequence makes it doubtful if i ever find another scene with something similar to backup i may go with this one
now let's get to the feat
castle window is 6 px (1.5 m)
castle wall diameter=185.93 px (46.4825 m)
claste wall thickness 8 px (2m)
castle wall height is 60 px (15px)
castle building height is 110.819 px (27.70 m)
castle main building diameter is 44.94 px (11.235 m)
now i will shape the castle wall as a circular crown
area of a circular crown is radius of wall x pi - empty radius
we know the radius of the wall is half its diameter
making it 23.24125 m
the wall thickness is 2 meters
which means the empty radius is 21.24125
A=(23.24125 x pi) - (21.24125 x pi)
A=6.28318 m^2
now for volume we just multiply by height of wall
V=6.28318 x 15
V=94.2477 m^3
now for the main building i will shape it like like a cylinder
making its volume 2746.1 m^3
i will multiply by 5 since there are many other towers within the castle
but i also need to account for hollowness mulplying by 0.2
so instead i will just not account for it
making the total volume= 2746.1 + 94.2477= 2840.3477 m^3
concrete density is 2400 kg/m^3
M=2840.3477 x 2400
M=6816834.48 kg
tree height is 73 px (18.25 m)
tree diameter is 5px (1.25 m)
here we have an area of 400 x 578 px
100 x 144.= 14450 m^2
let's say there is 50 trees or so
meaning the density of tree population is 1 per 289 m^2
keep in mind this is most definitely a low end due to existing a castle here
now how big was the explosion range
2*atan(tan(70/2 deg))*(570/367)=108.719346 deg for pov 2*atan(20/(570/tan((108.719346deg)/2)))=5.60331996 deg
186.46 meters
i was going to take faildramon into account but i realised the sphere went after his position in panel
i was going to do angsizing but i realized this is an omnidirectional sphere and thus actual scalling is far superior
sphere diameteris 570px (520.125 m)
tree is 20px (18.25 m)
surface area is pir^2
SA=212473.777416 m^2
ratio is 1 tree per 289m^2
which gives me 735 trees
tree volume will be a cylinder
making it 22.39611950313036 m^3
now we multiply by number of trees
735 x 22.39611950313036
16461.1478348 m^3
the density of a pine red is around 500 kg/m^3
Mass= 16461.1478348 x 500
Mass=8230573.9174kg
total mass=6816834.48 + 8230573.9174
TM=15047408.3974 kg
E=mc^2
E=1.35239362 ? 10^24 joules
i will do one more approach regardless
the mega crusher was still annhilating trees at the edge of the explosion the surface area of those trees is 153.15264186250243 m^2
making a ratio between explosion surface area and tree surface area i get
212473.777416/153.15264186250243=1387.3334 times boost
the annhlation of a single tree is
E=22.39611950313036 x 500 x c^2
E=1.00643142 ? 10^21
TE=1387.3334 x 1.00643142 ? 10^21
TE=1.3962559e+24 joules
giga crusher is stated to have 10 times its potency
the consistency in the results is terryfying tbh :psyduck
this fits really well with failldramon who gets scalled to country level shit from much weaker character and would establish a really welcome boost for FM tier characters (even more because diaboromon no sold giga death)
3.For such a little body she sure as hell eats (C)
requested by TheBlueDash
[YOUTUBE]_vd0RVDYnuI[/YOUTUBE]
Q cannibalize some fucker and the ground around her
Q is 1.66m(80.65 px)
crater diameter is 548px (11.279 m)
we can't see the end of crater so d/4 is fair enough really
Crater deepth=11.279/4=2.819m
implugging as a cylinder
crater volume=281.6606327237458 m^3
now using rock pulverization (214j/cc) i get
E=281660632.7237458 x 214
E=60275375402.9 joules
Q cannibalize some fucker and the ground around her
Q is 1.66m(80.65 px)
crater diameter is 548px (11.279 m)
we can't see the end of crater so d/4 is fair enough really
Crater deepth=11.279/4=2.819m
implugging as a cylinder
crater volume=281.6606327237458 m^3
now using rock pulverization (214j/cc) i get
E=281660632.7237458 x 214
E=60275375402.9 joules
so city block level just like i suspected
4.What a mess (gantz)
because someone asked me about x guns power
kei fucks up a giant alien (cant be bothered to look for english scans)
random human is 62px (1.7 m)
the alien is 576.0229 px tall (15.7941 m)
alien cut leg is 259.4229 px (7.113m)
alien cut leg width is 48.877px (1.34 m)
height of the crush is 406px (11.132 m)
now let's use square law to get the alien volume and surface area
human volume is 65913.4cc according to bang's blog
V2=(H2/H1)^3*V1
V2=(15.7941/1.7)^3*65913.4
V2=52858106.3564 cc
Surface area of a man is 1.9 m^2
A2=(15.7941/1.7)^2 x 1.9
A2=164 m^2
now we need to see how much of the alien body was destroyed
the volume of the remaining leg is a cylinder with 15.699 m^3 and 49.6833 m^2 for area
meaning the destroyed volume is 52858106.3564 -15699000
DV= 37159106.3564 cc
human pulverization is 12.9 j/cc
E=37159106.3564 x 12.9
E=479352471.998 joules
now let's see how big the crater is
i will ask you to ignore the leg because the leg in this panel is almost as big as the alien itself
crater diamter is 214px (14.45m)
now we need the surface area of the cylinder made by the attack
height is 11.132 m
making surface area=833.334 m^2
alien destroyed surface area is 164-49.6833=114.3167 m^2
Ratio is=833.334 /114.3167
Ratio=7.289696 times
TE=479352471.998 x 7.289696
TE=3494333797.71 joules
random human is 62px (1.7 m)
the alien is 576.0229 px tall (15.7941 m)
alien cut leg is 259.4229 px (7.113m)
alien cut leg width is 48.877px (1.34 m)
height of the crush is 406px (11.132 m)
now let's use square law to get the alien volume and surface area
human volume is 65913.4cc according to bang's blog
V2=(H2/H1)^3*V1
V2=(15.7941/1.7)^3*65913.4
V2=52858106.3564 cc
Surface area of a man is 1.9 m^2
A2=(15.7941/1.7)^2 x 1.9
A2=164 m^2
now we need to see how much of the alien body was destroyed
the volume of the remaining leg is a cylinder with 15.699 m^3 and 49.6833 m^2 for area
meaning the destroyed volume is 52858106.3564 -15699000
DV= 37159106.3564 cc
human pulverization is 12.9 j/cc
E=37159106.3564 x 12.9
E=479352471.998 joules
now let's see how big the crater is
i will ask you to ignore the leg because the leg in this panel is almost as big as the alien itself
crater diamter is 214px (14.45m)
now we need the surface area of the cylinder made by the attack
height is 11.132 m
making surface area=833.334 m^2
alien destroyed surface area is 164-49.6833=114.3167 m^2
Ratio is=833.334 /114.3167
Ratio=7.289696 times
TE=479352471.998 x 7.289696
TE=3494333797.71 joules
so still building level
how is this a feat again (rwby)
requested by jamrock
apparently rwby moon was destroyed in the past and people want to know the energy needed to do so
we dont know how, who nor when but people want to know how much energy this needs
so...ok i guess ?
http://www.narutoforums.com/blog.php?b=25377
distance between intersections=382.12 px (2130794.35 m)
moon radius=311.5 px (1737000 m)
explosion radius=260 px (1449823.435 m)
DBI=9169077.3072 m
ER=6357715 m
EXR=5563000.625 m
V=pi*(1737000 + 1449823.435 - 2130794.35 )^2 *(2130794.35 ^2 + 2*1449823.435 *2130794.35 - 3*1449823.435 ^2 + 2*1737000 *2130794.35 + 6* 1737000 *1449823.435 - 3*1737000 ^2)/(12*2130794.35 )
V=2.4490398e+18 m^3
now i will use rock fragmentation 8 j/cc
E=2.4490398e+24 x 8
E=1.9592318e+25 joules
let's try something else
which means volume is 15556270962017784 m^3
height is 551144.803 meters
densityy of moon is 3346 kg/m^3
gravity in the moon is 1,622 m/s?
PE= MGH
PE= 3346 x 15556270962017784 x 551144.803 x 1.622
PE=4.6531602e+25 joules
we have 3 of similar size on a similar situation so i may as well multiply this by 3
oh well
we dont know how, who nor when but people want to know how much energy this needs
so...ok i guess ?
http://www.narutoforums.com/blog.php?b=25377
distance between intersections=382.12 px (2130794.35 m)
moon radius=311.5 px (1737000 m)
explosion radius=260 px (1449823.435 m)
DBI=9169077.3072 m
ER=6357715 m
EXR=5563000.625 m
V=pi*(1737000 + 1449823.435 - 2130794.35 )^2 *(2130794.35 ^2 + 2*1449823.435 *2130794.35 - 3*1449823.435 ^2 + 2*1737000 *2130794.35 + 6* 1737000 *1449823.435 - 3*1737000 ^2)/(12*2130794.35 )
V=2.4490398e+18 m^3
now i will use rock fragmentation 8 j/cc
E=2.4490398e+24 x 8
E=1.9592318e+25 joules
let's try something else
which means volume is 15556270962017784 m^3
height is 551144.803 meters
densityy of moon is 3346 kg/m^3
gravity in the moon is 1,622 m/s?
PE= MGH
PE= 3346 x 15556270962017784 x 551144.803 x 1.622
PE=4.6531602e+25 joules
we have 3 of similar size on a similar situation so i may as well multiply this by 3
oh well