Calc Maliki - Extreme video games

(http://imgur.com/UDF6GGQ)
John and Fang play retro games, resulting in a huge pillar of light which lances into space. Take note if you look closely before the beam of light appears, you can see there was a cloud that got parted.
So um...time for calcing!
The radius of the Earth is 6371km.

R = (h/2) + c^2/(8h)
= (82/2) + 544^2/(8 X 82)
= 492.121951 pixels

492.121951 pixels = 6371km
1 pixel = 6371km/492.121951 = 12.9459781km (12945.9781m)
12945.9781m X 82 = 1061570.2m
1061570.2m/2 = 530785.1m
12945.9781m X 16 = 207135.65m
12945.9781m X 10 = 129459.781m
207135.65m + 129459.781m = 336595.431m

To account for the hollow parts, we'll calc three cylinders, and subtract the volume of the second from the first, before adding the third. A nimbostratus cloud usually has a thickness of 2000m.

V = πr^2h
= π X 530785.1^2 X 2000
= 1.77017953e15m^3

V = πr^2h
= π X 336595.431^2 X 2000
= 7.11862805e14m^3

V = πr^2h
= π X 207135.65^2 X 2000
= 2.69581181e14m^3

V = 1.77017953e15 - 7.11862805e14
= 1.05831672e15 + 2.69581181e14
= 1.3278979e15m^3

Density of a cloud is 1.003kg/m^3.

M = 1.3278979e15 X 1.003
= 1.33188159e15kg

We now have the dimensions for our clouds for our low end. Before we get the high end, let's get the timeframe for the beam of light.
Timeframe is 5 frames.

T = 1s/24
= 41.6666667ms X 5
= 0.208333333s

12945.9781m X 316 = 4090929.08m
12945.9781m X 7 = 90621.8467m

T = 4090929.08m/0.208333333s
= 19636459.6/340.29
= Mach 57705.0739

Let's also go for a high end for the cloud height shown there.

V = πr^2h
= π X 530785.1^2 X 90621.8467
= 8.0208469e16m^3

V = πr^2h
= π X 336595.431^2 X 90621.8467
= 7.11862805e14m^3

V = πr^2h
= π X 207135.65^2 X 90621.8467
= 2.69581181e14m^3

V = 8.0208469e16 - 3.2255161e16
= 4.7953308e16 + 1.22149722e16
= 6.01682802e16m^3

M = 6.01682802e16 X 1.003kg
= 6.0348785e16kg

With both our high end and our low end, let's find the timeframe of the cloud being parted.
Timeframe is 11 frames.

T = 41.6666667ms X 11
= 0.458333334s

12945.9781m X 162 = 2097248.45m
2097248.45m/2 = 1048624.23m

T = 1048624.23m/0.458333334s
= 2287907.41m/s

Let's finally get our kinetic energy!

(Low end)
KE = (0.5)mv^2
= (0.5) X 1.33188159e15 X 2287907.41^2
= 3.48588062e27 joules
= 833.14546367112802727 petatons

(High end)
KE = (0.5)mv^2
= (0.5) X 6.0348785e16 X 2287907.41^2
= 1.57948471e29 joules
= 37.750590583173994673 exatons

Final Results
Retro games energy beam (speed) = Mach 57705.074
Retro games energy beam (energy - low end) = 833.145 petatons
Retro games energy beam (energy - high end) = 37.751 exatons