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Calc Promare - Lio melts the frozen lake

Calculations

Lio (in his black form) evaporates the Frozen Lake just by coming in contact with it. The average height of an American man is 5 feet 9 inches, or 1.7526m.
13 pixels = 1.7526m
1 pixel = 1.7526m/13 = 0.134815385m
0.134815385m X 2880 = 388.268309m
388.268309m/2 = 194.134154m

Next up is the depth. Due to the cracks that appear from the melting, we can ascertain the ice goes all the way down.
2829 pixels = 388.268309m
1 pixel = 388.268309m/2829 = 0.137245779m
0.137245779m X 385 = 52.8396249m

The scaling's not entirely perfect, but that's the best I could get with the shots available, and keep in mind that there's also Deus Promith's lab at the bottom. Volume as a spherical cap.

V = π/3H^2(3R = H)
= π/3 X 52.8396249^2(3 X 194.134154 - 52.8396249)
= 1548337.28m^3

Ice weighs 919kg/m^3.

M = 1548337.28 X 919
= 1.42292196e9kg

It takes 333.55 kilojoules to melt 1kg of ice.

E = 1.42292196e9 X 333.55
= 474615619758 kilojoules
= 4.7461562e14 joules

But the ice doesn't just melt; it evaporates, so let's also add the energy to vaporize the water (more information on which can be found here).

E = 1.42292196e9 X 2.26 X 10^6
= 3.21580363e15

Finally, to add the two together to get our final results.

E = 4.7461562e14 + 3.21580363e15
= 3.69041925e15 joules
= 882.0313695028680741 kilotons

Final Results
Lio melts the frozen lake = 882.031 kilotons

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