A bunch of Pokes attack a fake Kyogre made of sea water and it explodes over the Battle Frontier.
http://www.narutoforums.com/blog.php?b=19614
Modbat has this Kyogre at 68,211,324,181,269,157.8 kg.
Spoiler:
A single floor in the Battle Tower in this scan is about 1 px, which is equal to 262.18m according to Kaiser.
(262.18/11)94=2240.4473m
Projectile motion in the y direction is the same thing as free-fall, so...
h=.5gt^2
2240.4473=.5(9.8)t^2
4480.8946=(9.8)t^2
457.234=t^2
t=21.383s
Now we find the final velocity of the free-fall to get the initial velocity of the actual feat.
vfinal=a*t
v=9.8*21.383
v=209.5534m/s
Now to get KE.
KE=.5mv^2
KE=.5(68211324181269157.8)209.5534^2
KE=1497669233374829230184.72J
or about 358 gigatons.
Credit to Totally not a cat for bringing this feat to my attention, as well as to KaiserWombat for actually doing all the tedious scaling.
http://www.narutoforums.com/blog.php?b=19614
Modbat has this Kyogre at 68,211,324,181,269,157.8 kg.
Spoiler:
A single floor in the Battle Tower in this scan is about 1 px, which is equal to 262.18m according to Kaiser.
(262.18/11)94=2240.4473m
Projectile motion in the y direction is the same thing as free-fall, so...
h=.5gt^2
2240.4473=.5(9.8)t^2
4480.8946=(9.8)t^2
457.234=t^2
t=21.383s
Now we find the final velocity of the free-fall to get the initial velocity of the actual feat.
vfinal=a*t
v=9.8*21.383
v=209.5534m/s
Now to get KE.
KE=.5mv^2
KE=.5(68211324181269157.8)209.5534^2
KE=1497669233374829230184.72J
or about 358 gigatons.
Credit to Totally not a cat for bringing this feat to my attention, as well as to KaiserWombat for actually doing all the tedious scaling.