Willy suggested this some months ago. The basic idea is that the Original Life Fiber was able to survive the explosions of planets all around the universe.
Astral got the cockpit of this ship thing to be almost 10m.
Gonna calc the surface area in parts.
Large Sphere
(9.68/6.4)302=456.775m
A=4*pi*r^2
A=4*pi*(456.775/2)^2
A=655472.57m^2
Small Sphere
(9.68/6.4)143.2=216.59m
A=4*pi*(216.59/2)^2
A=147376m^2
I know there would technically be less surface area to account for with these because they connect, but fuck accounting for that. I figure the giant-ass spikes on the back will make up for it
worries
Cone
(9.68/6.4)81.5=123.27m
(9.68/6.4)46.325=70m
A=pi*r(r+sqrt(h^2+r^2))
A=pi*(70/2)((70/2)+sqrt((123.27/2)^2+(70/2)^2))
A=11642m^2
Now I have to subtract the base.
11642-(pi*(70/2)^2)=7793.55m^2
Cylinder (minus bases)
(9.68/6.4)50.22=76m
(9.68/6.4)33.734=51m
A=2*pi*r*h
A=2*pi*(51/2)*(76/2)
A=6088.4m^2
Now add them all up and divide by two (I figure the half of the surface area facing the planet would be affected by the energy?).
Atotal=(655472.57+147376+11642+6088.4)/2
Atotal=410289.485m^2
Assuming an Earth-like planet (not much of a stretch, considering the same process was initiated on Earth)...
Surface area of Earth is 5.101e+14m^2. I can adjust for that if anyone wants to offer the altitude of Coversworries
GBE of Earth is 2.487e+32 J.
(410289.485/5.101e+14)2.487e+32=200037237638698294452068.22J
or about 47 teratons.
Er...right?
Again, that's theoretical. I dunno how anyone wants to argue that the Original Life Fiber's surface area was exactly the same then as it is during the series. Unless I understood the origin story incorrectly, which is entirely viable considering I didn't pay a lick of attention to it.
Also, a low end would mean using half of the large sphere's surface area. that yield about 38 teratons.
Astral got the cockpit of this ship thing to be almost 10m.
Gonna calc the surface area in parts.
Large Sphere
(9.68/6.4)302=456.775m
A=4*pi*r^2
A=4*pi*(456.775/2)^2
A=655472.57m^2
Small Sphere
(9.68/6.4)143.2=216.59m
A=4*pi*(216.59/2)^2
A=147376m^2
I know there would technically be less surface area to account for with these because they connect, but fuck accounting for that. I figure the giant-ass spikes on the back will make up for it
worriesCone
(9.68/6.4)81.5=123.27m
(9.68/6.4)46.325=70m
A=pi*r(r+sqrt(h^2+r^2))
A=pi*(70/2)((70/2)+sqrt((123.27/2)^2+(70/2)^2))
A=11642m^2
Now I have to subtract the base.
11642-(pi*(70/2)^2)=7793.55m^2
Cylinder (minus bases)
(9.68/6.4)50.22=76m
(9.68/6.4)33.734=51m
A=2*pi*r*h
A=2*pi*(51/2)*(76/2)
A=6088.4m^2
Now add them all up and divide by two (I figure the half of the surface area facing the planet would be affected by the energy?).
Atotal=(655472.57+147376+11642+6088.4)/2
Atotal=410289.485m^2
Assuming an Earth-like planet (not much of a stretch, considering the same process was initiated on Earth)...
Surface area of Earth is 5.101e+14m^2. I can adjust for that if anyone wants to offer the altitude of Covers
worriesGBE of Earth is 2.487e+32 J.
(410289.485/5.101e+14)2.487e+32=200037237638698294452068.22J
or about 47 teratons.
Er...right?
Again, that's theoretical. I dunno how anyone wants to argue that the Original Life Fiber's surface area was exactly the same then as it is during the series. Unless I understood the origin story incorrectly, which is entirely viable considering I didn't pay a lick of attention to it.
Also, a low end would mean using half of the large sphere's surface area. that yield about 38 teratons.
