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A few straight forward feats which the values of are given to us directly! 1. Nebula's flight speed Nebula is noted to be able to fly at over 800km/h, or 222.222222m/s. 2. Aqua's swimming speed Betterman Aqua can swim at speeds of over 600 knots, or over 1000km/h. On average, 600 knots is 308.666667m/s, though this number is showm to fluctuate slightly above 600 knots (from 604 knots, with a highest seen speed of 606 knots, or 311.753333m/s. 3. Levi's length Aqua's Psychovoice kills the monstrous super organism Levi, which is so huge it's fused with part of the sea floor. According to the official Betterman website, Levi was 2000m long (or 2km). http://www.betterman.jp/story/09.php Final Results Betterman Nebula's flight speed = >222.222m/s Betterman Aqua's observed swimming speed (low end) = 308.667m/s Betterman Aqua's observed swimming speed (high end) = 311.753m/s Levi's length = 2km

Pisa Sol reforms her true form from the Sun into a cube form. In case the show didn't make it obvious enough, the Dengeki Data Collection outright confirms she is the size of a star. (Relevant text) This will be simple enough. The Sun has a diameter of 1391400km and a mass of 1.9891e30kg. Timeframe is 4 seconds and 28 frames (obviously, the framerate is 30 frames per second). T = 1s/30 = 33.3333333ms X 28 = 0.933333332s + 4s = 4.93333333s 167 pixels = 1391400km 1 pixel = 1391400km/167 = 8331.73653km 8331.73653km X 290 = 2416203.59km T = 2416203.59km/4.93333333s = 489770998/299792458 = 1.6337002 C Alas, as this is FTL we cannot get kinetic energy from it (given the Sun was reformed, it would be star level in anycase). Final Results Pisa Sol reforms the 'Sun' = 1.634 C

J-Ark moves from Earth's orbit to the Moon in a matter of minutes, and J-Soldat and the Brave Robo Corps are completely unaffected by the acceleration. The J-Ark was moored at Orbit Base, so we'll subtract the distance from the Moon to Orbit Base for our distance travelled. The distance from the Earth to the Moon is 384,400km. But how high into orbit is Orbit Base? R = (h/2) + c^2/(8h) = (104/2) + 1672^2/(8 X 104) = 3412.07692 pixels X 2 = 6824.15384 pixels The radius of the Earth is 12756.2km. = 2*atan(6824.15384/(1641/tan(70/2))) = 2.20230527 rad = 126.18279717073224 degrees Enter that through angscaler and we have a distance of 3237km to the Earth. L = 384,400km - 3237km = 381163km It says minutes plural, so for our low end we'll use two minutes (120 seconds) and for our high end we'll use nine minutes (540 seconds). (Low end) T = 381163km/540s = 705857.407/340.29 = Mach 2074.28196 (High end) T = 381163km/120s = 3176358.33/340.29 = Mach 9334.2688...

Hey Primevals! HIKARI NI NARE! 1. GaoGaiGar vs 4 Moon Primevals GaoGaiGar with ZA POWAH transforms 4 Moons Primeval into light. (Relevant text) (Relevant text) (Relevant text) (Relevant text) So that's all the moons; Himalia, Lysithea, Adrastea and Elara. Himalia has a mass of 6,744,007,948,937,370,000kg, Adrastea has a mass of 1.91e+16kg, Lysithea has a mass of 7.77e+16kg and Elara has a mass of 7.77e+17kg. We only see one spherical moon there (out of two), so we'll go with half of Adrastea's mass in that case. M = 1.91e+16kg/2 = 9.55e15kg M = 9.55e15kg + 1.91e+16kg + 7.77e+16kg + 7.77e+17kg = 8.8335e17kg E = mc^2 = 8.8335e17 X 299792458^2 = 7.93915387e34 joules = 18.975033150095601542 yottatons 2. GaoGaiGar vs Io Primeval 4 minor moons aren't enough, we also have to take on a major Galilean Moon! In this case, the moon in question the Primeval has merged with is confirmed to be Io. (Relevant text) Io has a mass of 8.94e+22kg. E = mc^2 =...

King J-Der destroys the Moon Primeval which trapped GGG in a Klein Space, thus freeing everyone. Though we obviously cannot get the energy to destroy the Klein Space, we can infact find the energy to destroy the moon which sustained it. Thanks the the GaoGaiGar Degenki Data Collection, we can confirm that this moon was Ganymede. (Relevent text) The moon has been distorted, but it's 'head' should still be similar in size to how it was originally (it's the only thing we have to scale off). Ganymede has a radius of 2631km (and thus a diameter of 5262km) and a mass of 1.4819e23kg. It cuts away before we can see it fully dispersed, but we can get around this by measuring the time until the Klein Space it was sustaining vanished (and Swan mentions as such). 592 pixels = 5262km 1 pixel = 5262km/592 = 8.88851351km 8.88851351km X 437 = 3884.2804km Timeframe is 4 seconds and 1 frame (with a framerate of 30 frames per second). T = 1s/30 = 33.3333333ms + 4s = 4.03333333s T =...

King J-Der destroys a Primeval (ZX-26) merged with one of Jupiters Moons. In the GaoGaiGar Denki Data Collection, this is confirmed to be Ananke. (Relevant text) Ananke has a mean radius of 14km (or a diameter of 28km) and an estimated mass of 29,973,368,661,943,900kg. The Moon is a bit odd shaped, so we'll have a low end and a high end with different radii. (Low end) 669 pixels = 28km 1pixel = 28km/669 = 0.0418535127km 0.0418535127km X 480 = 20.0896861km (High end) 293 pixels = 14km 1 pixel = 14km/293 = 0.04778157km 0.04778157km X 480 = 22.9351536km The timeframe is 5 seconds and 22 frames (with a framerate of 30 frames per second). T = 1s/30 = 33.3333333ms X 22 = 0.733333333s + 5s = 5.73333333s Now let's get our timeframe... (Low end) T = 20.0896861km/5.73333333s = 3504.01502m/s (High end) T = 22.9351536km/5.73333333s = 4000.31749m/s We can finally get our kinetic energy! (Low end) KE = (0.5)mv^2 = (0.5) X 29,973,368,661,943,900 X 3504.01502^2 =...

Pisa Sol is able to drain all of the dark matter of the current universe to refill the previous universe (using the Pas-Q Machine to regenerate it). I've been hoping to find a way to calculate this for ages, and I think I've finally found all of the things required to calculate it! There's lots of figuring out here, so hold on, and have courage! The regeneration program started when the mechanization ceased, accompanied by a visual of the Z-Master being destroyed. Now we can fit together the final pieces of the puzzle... On Christmas Day 2005(or shortly after, but we'll go with Christmas Day), GGG left to fight the Primevals and the Z-Master at Jupiter. So, from there to 2006 we have a week (or 7 days), then 2006 gives us a year (365 days), and into 2007 we have the first 7 months (January, March, May and July having 31 days, April & June having 30 days and February having 28 days). We will assume until the end of July, just to be sure. With all of that, we can now find out how...

The 11 Planetary Masters of Sol fly back to their crafts around the replica Moon in less than a second. We'll need to find the size in relation to the Moon (which has a radius of 1737.4km). Timeframe is 6 frames (with a framerate of 30 frames per second). T = 1s/30 = 33.3333333ms X 6 = 0.2s R = (h/2) + c^2/(8h) = (19/2) + 806^2/(8 X 19) = 4283.42105 pixels 4283.42105 pixels = 1737.4km 1 pixel = 1737.4km/4283.42105 = 0.405610371km 0.405610371km X 474 = 192.259316km T = 192.259316km/0.2s = 961296.58/340.29 = Mach 2824.93338 If this isn't enough, we can also get kinetic energy! The average weight of a man globally is 136.7 pounds (or 62.006077kg), which would fit with Palparepa and Pei La Cain at least. KE = (0.5)mv^2 = (0.5) X 62.006077 X 961296.58^2 = 2.86496324e13 joules = 6.8474264818355639 Final Results 11 Planetary Masters of Sol leave the replica Moon = Mach 2824.933 Kinetic energy of the 11 Planetary Masters of Sol leaving the replica...

Replica Goldymarg sacrifices himself, taking out all the replica Repair Tools and replica Orbit Base. Orbit Base has a mass of 720,500 tons (720500000kg), and an operative weight of 982,200 tons (982200000kg), which will serve as our low end and our high end. (Low end) E = mc^2 = 720500000 X 299792458^2 = 6.47553106e25 joules = 15.47689067877629121 petatons E = mc^2 = 982200000 X 299792458^2 = 8.82757337e25 joules = 21.098406716061187893 petatons Final Results Replica Goldymarg's sacrifice (low end) = >15.479 petatons Replica Goldymarg's sacrifice (high end) = >21.098 petatons

Pillnus strikes Renais with enough force to send her flying into the river and create a huge explosion of water. I've been wanting to calc this feat for ages, but wasn't sure of a proper way to scale it. Thankfully, on my rewatch I found a very good way to scale (from GaoFighGar to the bridge to the explosion). GaoFighGar is 32.0m tall. 309 pixels = 32m 1 pixel = 32m/209 = 0.153110048m 0.153110048m X 66 = 10.1052632m 219 pixels = 10.1052632m 1 pixel = 10.1052632m/219 = 0.0461427543m Timeframe is 1 second and 3 frames (with a framerate of 30 frames per second). T = 1s/30 = 33.3333333ms X 3 = 99.9999999ms + 1s = 1.1s 0.0461427543m X 179 = 8.25955302m 8.25955302m/2 = 4.12977651m 0.0461427543m X 377 = 17.3958184m 17.3958184m/2 = 8.6979092m 0.0461427543m X 508 = 23.4405192m Volume as a conical frustrum. V = (1/3)π(r^2+rR+R^2)h = (1/3) X π X (4.12977651^2 + 4.12977651 X 8.6979092 + 8.6979092^2) X 23.4405192 =3157.43977m^3 Weight of water is 1000kg/m^3. M =...

A simple enough calc. Z-Masters form is utterly colossal, being a good portion of the size of Jupiter. We have a direct scale to Jupiter, so let's go right for it! Jupiter has a diameter of 139,822km. 1070 pixels = 139,822km 1 pixel = 139,822km/1070 = 130.674766km 177 X 130.674766km = 23129.4336km 737 X 130.674766km = 96307.3025km Final Results Z-Masters height = 23129.434km Z-Masters wingspan = 96307.303km

Goldymarg flies up to GaoGaiGar in space to destroy ZX-05 all the way to the ground. Previously I calculated the height of ZX-05 to be 5666.9km tall. Timeframe is 20 seconds. T = 5666.9km/20s = 283345/340.29 = Mach 832.657439 Goldymarg is a heavy boy, weighing 625 tons (or 625000kg). So on top of the speed, we can also find the kinetic energy. KE = (0.5)mv^2 = (0.5) X 625000 X 283345^2 = 2.50888716e16 joules = 5.9963842256214148208 megatons Final Results Goldymarg flies into space (speed) = Mach 832.657 Goldymarg flies into space (energy) = 5.996 megatons

Gai smashes Pizza into the exterior of Pasdars lair with enough force to destroy the outer shell. We'll scale the beams width to Gai's width (this is the best we have, and from the looks of it, the beam is actually thicker than Gai). Gai is 200cm tall. 1068 pixels = 200cm (2m) 1 pixel = 2m/1068 = 0.00187265918m 0.00187265918m X 388 = 0.726591762m 17 pixels = 0.726591762m 1 pixel = 0.726591762m/17 = 0.0427406919m 0.0427406919m X 176 = 7.52236177m 0.0427406919m X 296 = 12.6512448m That's our thickness, but the area is filled with holes, making the scaling just a bit tricky... 214 pixels = 12.6512448m 1 pixel = 12.6512448m/214 = 0.0591179664m 0.0591179664m X 2188 = 129.35011m 0.0591179664m X 1637 = 96.776111m 0.0591179664m X 358 = 21.164232m 21.164232m/2 = 10.582116m 0.0591179664m X 1008 = 59.5909101m 59.5909101m/2 = 29.7954551m 0.0591179664m X 1038 = 61.3644491m 61.3644491m/2 = 30.6822246m 0.0591179664m X 710 = 41.9737561m 0.0591179664m X 282 = 16.6712665m 0.0591179664m X 106 =...

Something I noticed in my rewatch...Eraserhead very explicity turns an explosion (or at least the physical part of the explosion, such as the fast moving matter) into photons (similar to how Goldion Hammer turns its target into light). There are several examples of this power being used, but one of the more noticable examples was against EI-06, who contained 100,000s of tons of oil. When this oil exploded, ChoRyuJin used the Eraserhead to turn the explosion into photons and sent it harmlessly into space. As several implies more than a couple, for a low end we'll use 300,000 tons (300,000,000kg) and for a high end we'll use 900,000 tons (900,000,000kg). (Low end) E = mc^2 = 300,000,000 X 299792458^2 = 2.69626554e25 joules = 6.4442293021032508449 petatons (High end) E = mc^2 = 900,000,000 X 299792458^2 = 8.08879661e25 joules = 19.33268788240917857 petatons Final Results Eraserhead nullifies EI-06 exploding (low end) = 6.444 petatons Eraserhead...

Volfogg is repeatedly shown to be a fast boy, often moving in a blur. Keep in mind too, he's also a huge robot, so him doing this would yield a large amount of energy too. Firstly, we need Volfoggs dimensions, which we are supplied with! Volfogg is 10.7m tall and has a dry weight of 9.5 tons (or 9500kg) and a total weight of 13.5 tons (or 13500kg). 1044 pixels = 10.7m 1 pixel = 10.7m/1044 = 0.0102490421m 0.0102490421m X 456 = 4.6735632m 0.0102490421m X 90 = 0.922413789m With that done, let's get underway! 1. Volfogg lands behind Leo Volfogg appears behind Leo in a blur. Timeframe is 4 frames (with a framerate of 30 frames per second). T = 1s/30 = 33.3333333ms X 4 = 0.133333333s 50 pixels = 0.922413789m 1 pixel = 0.922413789m/50 = 0.0184482758m 0.0184482758m X 446 = 8.22793101m T = 8.22793101m/0.133333333s = 61.7094827m/s Otherwise 222.154138km/h. As said above, Volfogg is a big boy, so let's get KE for him too. (Low end) KE = (0.5)mv^2 = (0.5) X 9500 X...

ChoRyuJin hauls GaoGaiGar out of the deep sea, of a depth of 10,000m (or 10km). http://www.gaogaigar.net/TV/story/10.html Firstly, ChoRyuJins hooks reach 10,000m deep at astoundingly fast speeds, finding and rescuing his fellow Braves in just a few seconds. Timeframe is 4 seconds and 2 frames (with a framerate of 30 frames per second). T = 1s/30 = 33.3333333ms X 2 = 66.6666666ms + 4s = 4.06666667s T = 10,000m/4.06666667s = 2459.01639/340.29 = Mach 7.22623759 It takes longer hauling GaoGaiGar up as it's a heavy machine, but even that is done in short time. Timeframe is 27 seconds and 11 frames. T = 33.3333333ms X 11 = 0.366666666s + 27s =27.3666667s T = 10,000m/27.3666667s = 365.408039/340.29 = Mach 1.07381363 Of course, being a huge heavy machine, GaoGaiGar would weigh quite a bit. And it does, having a mass of 264.2 tons (or 264200kg)! KE = (0.5)mv^2 = (0.5) X 264200 X 365.408039^2 = 1.76383929e10 joules = 4.2156770793499...

Hyper Mode Gai blitzes Pizza repeatedly at great speeds. Gai is 200cm tall. 226 pixels = 200cm (2m) 1 pixel = 2m/226 = 0.00884955752m Timeframe is 6 frames (with a framerate of 30 frames per second). 0.00884955752m X 907 = 8.02654867m T = 1s/30 = 33.3333333ms X 6 = 0.2s T = 8.02654867m/0.2s = 40.1327433m/s Final Results Hyper Gai blitzes Pizza = 40.133m/s As subsonic feats can often be misleading in how impressive they are, that is over 144km/h.

For a long time, I've been uncertain as to how to calculate the power of the Dividing Driver, as it's abilities to part land and water is very explicitly done via warping dimensional space (there have even been times it's been used on enemy zonders), so I'm not sure if KE of the landmass parted is applicable. However, there may just be a quantifiable way to calc it, which goes beyond the area that gets parted. According to both Leo Shishioh and Pasdar, the space-warping energy of the Dividing Driver is comparable to a blackhole in space. But how to calc this? Where there's a will knife there's a way. As it turns out, blackholes rotate incredibly fast, at speeds of over 90% the speed of light. https://bigthink.com/starts-with-a-bang/black-holes-spin/ https://www.space.com/supermassive-black-hole-spinning-very-slowly https://phys.org/news/2014-02-fast-black-holes.html So that's around 90% the speed of light or more for normal blackholes (with NGC 1365 spinning at 84% C)...

EI-06's destruction would wipe out everything in a 20km radius. Play around with the nuke calculator, and we get a yield of 21.74 megatons for airblast (widespread destruction). However, we also see a fireball expanding in the simulation (which shows it growing to over 20km). For a fireball radius (ground contact airburst) of 20km, we have a yield of 4390 megatons (or 4.390 gigatons). Final Results EI-06's explosion (low end) = 21.74 megatons EI-06's explosion (high end) = 4.39 gigatons The Dividing Driver field would have been able to contain this explosion, but in order to attack EI-06 and remove its zonder core, GaoGaiGar would have to lower it's defensive barriers and leave it exposed, which would mean that with it's impact barriers up it could most likely withstand an explosion like this (it was all part of the zonders plan to trap GaoGaiGar into a situation where it was forced to be hit by an explosion without its barriers at point blank). Thankfully, ChoRyuJinn uses...

Mamoru flies away at ridiculous speeds. Unfortunately, Mamoru has no explicit height, but Gai does, and we can scale off him. Gai is 200cm tall. 522 pixels = 200cm 1 pixel = 200cm/522 = 0.383141762cm 0.383141762cm X 232 = 88.8888888cm (0.888888888m) 0.383141762cm X 32 = 12.2605364cm 7 pixels = 0.888888888m 1 pixel = 0.888888888m/7 = 0.126984127m Timeframe is 1 frame (with a framerate of 30 frames a second). T = 1s/30 = 33.3333333ms 0.126984127m X 209 = 26.5396825m T = 26.5396825m/33.3333333ms = 796.190476/340.29 = Mach 2.33974103 That's not the only time Mamoru even flies away; the very next episode he does it again! 9 pixels = 0.888888888m 1 pixel = 0.888888888m/9 = 0.098765432m Timeframe is 2 frames. T = 33.3333333ms X 2 = 66.6666666ms 0.098765432m X 129 = 12.7407407m T = 12.7407407m/66.6666666ms = 191.111111m/s Final Results Mamoru flies away the first time = Mach 2.34 Mamoru flies away the second time = 191.111m/s