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The Calc Request Thread

I'm wondering, can the 20% gun devil's speed be called from CSM chapter 75-76?

Here's the abridged version of events.

(http://imgur.com/a/IgsSZrl)

The entire 'fight' takes 12 seconds with Gun devil appearing at the coast and after 2 seconds reaches 500 kilometers from Makima's position, keeps moving forward 2 more seconds before stopping, and shooting, the bullets reach Makima's position in less than a single second (pg 4 you can see the bullets hitting the ocean behind makima.) Makima prepares her ability before one of the bullets pierce her brain and in 2 seconds attacks.

Is it possible to calc the Gun devil's speed and bullet speed in these pages? Only problem is I forgot where they are currently. This should be the Tokyo office Iirc.
 
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Well, we have a couple of data, first the total distance is 500km, in 2 seconds he moved an unknown distance and his shots took 1 second to reach Makima.

It is impossible to get the individual speed of the movement, nor the individual speed of the shots, but if it is assumed that his movement speed is similar to that of his shots, we could say that he covered 500 km in 3 seconds.

that would be like mach ~486
 
A question about doing calculations.

Can we use the ImageMeter app? This app allows measuring the size within images easier than doing it with pixels and also has a property to count objects within the image.
 
So I'm wondering if these two speedfeats from JJK can be calced.

First is three-finger Sukuna blitzing Megumi during the cursed womb arc.



Sukuna here moves so fast that Megumi couldn't see him exit and get behind him despite looking straight at where Sukuna exits.

Second is fifteen-finger Sukuna traveling from where he fights Jogo to Mahoraga.

Scans

(http://imgur.com/a/2WEvxQh)
Megumi summons Mahoraga at around 11:05. Megumi gets oneshot before 11:07 when Sukuna senses Mahoraga and travels fast enough to save Haruta (blonde ponytail hair dude) from Mahoraga.

Here's a map Gege made detailing the positions of all the fights taking place.




Here's a google map of the same area for reference.




Here is me very badly trying to scale Gege's map to google's.



shits off center and very much not in scale but its the best I can do rn. Should give a somewhat close visual to where Sukuna fought Mahoraga. hopefully someone else could do better.
 
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Did we ever have or had any members here who ever calced the original Inuyasha manga?
 
Did we ever have or had any members here who ever calced the original Inuyasha manga?




 
just wanted to try my hand at calcing this, not sure what it could be used for though.

Thanks @ChaosTheory123 for giving me some numbers to work with.





So based on this

6 months is equal to 15,780,000 Seconds

The human brain can process 11,000,000 bits of info every second. .

So 15,780,000 * 11,000,000 = 1.7358e+14 or 21.6975 terabytes of information in total.

And this is done in 0.2 seconds so...

21.6975/2= 10.84875 terabytes every 0.1 seconds.

and

108.4875 terabytes every second

btw apparently the max memory of the brain is 2.5 petabytes https://www.medanta.org/patient-education-blog/what-is-the-memory-capacity-of-a-human-brain#:~:text=As mentioned in an article,2.5 million gigabytes of memory.

and 1 petabyte is equal to = 1024 terabytes.

so 2,500,000/108.4875= 23044.129508 seconds to overload the human brain's memory.

or around 6.4 hours.


Completely forgot to convert

2500/108.4875= 23.044129508

so around 23 seconds to overload the brain.

someone should probably check my math cause I think I did something wrong but idk where, math is my worst subject.

EDIT: Completely forgot to convert from gigabytes to petabytes.
 
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there’s a feat where a character created so much ice, the sheer mass of it all tipped the entire Earth off it’s axis to the degree where the north and South Pole shifted to the equator

No timeframe was given and it was only explained in narration. Is there a way to calc that? Like how much force or weight would be needed to shift the entire planet?
 
I got some values here but I don’t really know enough about Angsizing to know how far the Space Shuttle is from The Earth to gauge the distance to know how impressive this feat is

So… outsourcing this to people who can :doge
 
How fast would you have to be to travel from the nearest galaxy of the Milky Way to the earth in 2 minutes~ish?
 
How fast would you have to be to travel from the nearest galaxy of the Milky Way to the earth in 2 minutes~ish?

At approximately 2.5 million light-years away

D= 2.3651826e+22 mts

T= 120 seg

Speed: 2.3651826e+22/120= 1.9709855e+20 m/s or 657,449,994,956.17736816 c
 
I see, that's pretty fast. Would apply to the X-Men's ship from the TAS show. Tldr there's a scene in the final episode where Xavier calls out the Shi'ar and their spaceship takes about 1:40 min to reach the earth.
 
For practical purposes, I will assume that this planet is the size of Earth, and the same amount of air, gravity, water, etc.

In addition to the fact that I am not good at measuring the size of planets without some reference, there are also no measurements to know how much water there is in that planet.

First calc the global earthquake and tsunamis:

Low End:

Generally, a magnitude 10 earthquake should already be felt on the planet, so this would be the minimum interpretation
https://www.wolframalpha.com/input?i=Richter+scale+magnitude+calculator&assumption={"FS"}+->+{{"RichterScaleMagnitudeToEnergy",+"EJ"},+{"RichterScaleMagnitudeToEnergy",+"R"}}&assumption={"F",+"RichterScaleMagnitudeToEnergy",+"R"}+->"10"&assumption="FSelect"+->+{{"RichterScaleMagnitudeToEnergy"},+"dflt"}&lang=es

Earthquake energy (low end): 6.3e19 J

High End:


Magnitud is 4.5 or more

The circumference of a planet like The Earth is 40,000,000 mts so the distance of epicenter is the half

D= 20,000,000 mts or 12,454 miles


5000mm for magnitude 4.5.



Time frame is: 12,454/5.7 = 2184.9 s

M = log(base10)5000 + 3(log(base10)[8*2184.9]) - 2.92

M= 13.5


Earthquake energy (high end): 1.1220184543019634355910389e+25 J


Wind speed: 42 m/s

The total mass of Earth’s atmosphere is about 5.5 quadrillion tons, or roughly one millionth of Earth’s mass

Atmosphere mass: 5.5e+18 kg

KE: 4.85e+21 J

Now the clouds mass.


Cloud Thickness (Low End) = 2,000 meters

Cloud Thickness (High End) = 8,000 meters

Cloud radius= 20,000,000 mts


Volume (low end)= 2513274122871834590.77 m³

Volume (high end)= 10053096491487338363.08 m³


Density= 1-3 g/m³

Cloud mass (low end)= 2.5132741228718E+15 kg

Cloud mass (mid end)= 7.5398223686155E+15 kg

Cloud mass (mid high end)= 1.0053096491487E+16 kg

Cloud mass (high End)= 3.0159289474462E+16 kg

I'm going to use the formula that @ChaosTheory123 made a while ago to speed up the calculations
Now to get the Latent Heat for condensation of water in clouds

Average Atmospheric Temperature = 15 C

Specific Latent Heat Water in Cloud = (2500.8 - 2.36(15) + 0.0016(15)^2 - 0.00006(15)^3) * 1,000 = 2,465,557.5 joules/kg

Cloud storm energy (low end): 6.1966219e+21 J

Cloud storm energy (mid end): 1.8589866e+22 J

Cloud storm energy (mid high end): 2.4786487e+22 J

Cloud storm energy (high end): 7.4359462e+22 J


Storm's weather manipulation: 6.3e19 J + 6.1966219e+21 J + 4.85e+21 J = 1.1109622e+22 J or 2.6 Teratons

Storm's weather manipulation: 6.3e19 J + 1.8589866e+22 J + 4.85e+21 J = 2.3502866e+22 J or 5.6 Teratons


Storm's weather manipulation: 6.3e19 J + 2.4786487e+22 J + 4.85e+21 J = 2.9699487e+22 J or 7 Teratons


Storm's weather manipulation: 6.3e19 J + 7.4359462e+22 J + 4.85e+21 J = 7.9272462e+22 J or 18.9 Teratons


Storm's weather manipulation: 1.1220184543019634355910389e+25 J + 6.1966219e+21 J + 4.85e+21 J = 1.123e+25J or 2.6 Petatons



Storm's weather manipulation: 1.1220184543019634355910389e+25 J + 1.8589866e+22 J + 4.85e+21 J = 1.124e+25J or 2.6 Petatons



Storm's weather manipulation: 1.1220184543019634355910389e+25 J + 2.4786487e+22 J + 4.85e+21 J = 1.125e+25J or 2.6 Petatons



Storm's weather manipulation: 1.1220184543019634355910389e+25 J + 7.4359462e+22 J + 4.85e+21 J = 1.129e+25J or 2.6 Petatons


Results

Storm's weather manipulation (low end): 2.6 Teratons of TNT

Storm's weather manipulation (low mid end): 5.6 Teratons of TNT

Storm's weather manipulation (mid end): 7 Teratons of TNT

Storm's weather manipulation (mid high end): 18.9 Teratons of TNT

Storm's weather manipulation (high end): 2.6 Petatons of TNT
 
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Thank you!
 
So if i got it right, the earthquakes are either island level via Richter scale or continent via Chaos' formula, while the storms are country to small continental?