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Calc Re: Tott Doneeta fights a Heat Storm (Star Wars)

Calculations
Reevaluationg @ChaosTheory123 's Tott Doneeta's Heat Storm feat by request of @Kaaant , given a height has been given to the Heat Storm. Unfortunately, his comic scans are unavailable (they too seem to have been lost in the great PostImage crash). From what he's said, Tott Doneeta temporarily holds back a Heat Storm. Fortunately, we can see his scaling, and the below...
The twisting gyres of super-heated air reach hundreds of kilometers in height. The pillars push an explosive blast of hot air below them.
Heat storms travel at an astonishing speed across the landscape, and become even more letha if one funnelled into steep-sided valleys.
These heat storms reach hundreds of kilometers in height. To quote CT123 on it's diameter...
So that's 161,000m in diameter, or 80500m in radius. There's a few hundred km in there, so we'll go with a low end of 200km (200,000m) and a high end of 900km (900,000m). Using the mass given by Chaos once more.
Next for the speed of the winds. Thank you based Chaos for doing all the hard work for me.
Ok, so what do we know about Heat Storms?

Heat Storm Temperature = 300 C

Heat Storm Wind/Travel Speed (seems fair given outrunning the thing in a universe with landspeeders is still considered folly) = 500 km/h or 138.889 m/s
Volume as a cylinder.

(Low end)
V = πr^2h
= π X 80500^2 X 200000
= 4.07166116e15m^3

M = 4.07166116e15 X 0.616kg
= 2.50814327e15kg

KE = (0.5)mv^2
= (0.5) X 2.50814327e15 X 138.889^2
= 2.41912354e19 joules
= 5.7818440248565963202 gigatons

(High end)
V = πr^2h
= π X 80500^2 X 900000
= 1.83224752e16m^3

M = 1.83224752e16 X 0.616kg
= 1.12866447e16kg

KE = (0.5)mv^2
= (0.5) X 1.12866447e16 X 138.889^2
= 1.08860559e20 joules
= 26.018298040152963324 gigatons

Final Results
Tott Doneeta fights a Heat Storm (low end) = 5.7818 gigatons
Tott Doneeta fights a Heat Storm (high end) = 26.018 gigatons

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