Reevaluationg @ChaosTheory123 's Tott Doneeta's Heat Storm feat by request of @Kaaant , given a height has been given to the Heat Storm. Unfortunately, his comic scans are unavailable (they too seem to have been lost in the great PostImage crash). From what he's said, Tott Doneeta temporarily holds back a Heat Storm. Fortunately, we can see his scaling, and the below...
(Low end)
V = πr^2h
= π X 80500^2 X 200000
= 4.07166116e15m^3
M = 4.07166116e15 X 0.616kg
= 2.50814327e15kg
KE = (0.5)mv^2
= (0.5) X 2.50814327e15 X 138.889^2
= 2.41912354e19 joules
= 5.7818440248565963202 gigatons
(High end)
V = πr^2h
= π X 80500^2 X 900000
= 1.83224752e16m^3
M = 1.83224752e16 X 0.616kg
= 1.12866447e16kg
KE = (0.5)mv^2
= (0.5) X 1.12866447e16 X 138.889^2
= 1.08860559e20 joules
= 26.018298040152963324 gigatons
Final Results
Tott Doneeta fights a Heat Storm (low end) = 5.7818 gigatons
Tott Doneeta fights a Heat Storm (high end) = 26.018 gigatons
These heat storms reach hundreds of kilometers in height. To quote CT123 on it's diameter...
So that's 161,000m in diameter, or 80500m in radius. There's a few hundred km in there, so we'll go with a low end of 200km (200,000m) and a high end of 900km (900,000m). Using the mass given by Chaos once more.
Next for the speed of the winds. Thank you based Chaos for doing all the hard work for me.
Volume as a cylinder.
(Low end)
V = πr^2h
= π X 80500^2 X 200000
= 4.07166116e15m^3
M = 4.07166116e15 X 0.616kg
= 2.50814327e15kg
KE = (0.5)mv^2
= (0.5) X 2.50814327e15 X 138.889^2
= 2.41912354e19 joules
= 5.7818440248565963202 gigatons
(High end)
V = πr^2h
= π X 80500^2 X 900000
= 1.83224752e16m^3
M = 1.83224752e16 X 0.616kg
= 1.12866447e16kg
KE = (0.5)mv^2
= (0.5) X 1.12866447e16 X 138.889^2
= 1.08860559e20 joules
= 26.018298040152963324 gigatons
Final Results
Tott Doneeta fights a Heat Storm (low end) = 5.7818 gigatons
Tott Doneeta fights a Heat Storm (high end) = 26.018 gigatons