Exactly as the title says, it could range from small shit to large shit, I just want to know the basics since I just saw a feat like that performed in my recent watching of Superman The Animated Series and it made me curious. 
How much force does it take to throw shit into outer space?
- Thread starter NostalgiaFan
- Start date
At minimum without any force to continue pushing it would need to be thrown at escape velocity (which on Earth is 11.186 km/s). Just add the mass in and you have the energy.
From just this random calc I found online it said 32.6122449 speed of sound which hits Mach 0.02896. So somewhere Supersonic? Thing is when you say "without any force to continue pushing it" do you mean it just gets out of the atmosphere? because the scene I am talking about has Superman throw an object bigger than his hands into space with no sign it was stopping.
I can show a video where I found the episode and show you what I mean. just go to the episode "a little piece of home" and get to 20:35 to see where it is. Best to go to the site itself since I am having issues linking the episode itself.
Oh thanks I was trying to find that specific clip but was having trouble doing so.
kinda confused on your numbers here, 32x the speed of sound is mach 32, lower end hypersonic speec
I was just looking for what Mach it would be and for some reason the site I used had it at barely Mach 1. Guess I need to find better sources to tell me next time.
MotherFcker Ultimate
Illustrious
mach IS the speed of sound mach 1 is one times the speed of sound, mach 32 is 32 times sound
Fucking weird how the site I used acted like it would barely be Mach 1. Goes to show how unreliable and retarded most sites are.
Without any force continuing to push it refers to something like propulsion or a sky lift or something along those lines.
To find mach you can divide by the speed of sound (340.29m/s).
Given it's a timeframe of just a few seconds then in that case it would certainly be massively hypersonic. To do a rough calc...
Timeframe is roughly 1 second. TO find the distance, we'll angscale off the Earth by finding the Earths radius.
R = (h/2) + c^2/(8h)
= (204/2) + 1018^2/(8 X 204)
= 737.002451 pixels
That's for the radius of the Earth, so we'll double it for the diameter of the Earth, that being 1474.0049 pixels.
= 2*atan(972/(737.002451/tan(70/2)))
= 1.1170452 rad
= 64.00197548550571 degrees
The diameter of the Earth (at the equator) is 12,756km. Then we use an angscaling calculator (usually I use this one) to get a result of 1.0207e+4km (which is 10207km). To get the speed, I divide by the speed of sound at sea level (340.29m/s.
T = 10000km/1s
= 10000000/340.29
= Mach 29386.6996
To assume a mass just this once, I'm going to assume it weighs 0.1kg
M = (0.5)mv^2
= (0.5) X 0.1 X 10000000^2
= 5.0e12 joules
= 1.195028680688337 kilotons
Also...
If you're using a calculator don't forget to use m/s and not km/s because it will read it as m/s.
Damn thanks this is what I wanted.Without any force continuing to push it refers to something like propulsion or a sky lift or something along those lines.
To find mach you can divide by the speed of sound (340.29m/s).
Given it's a timeframe of just a few seconds then in that case it would certainly be massively hypersonic. To do a rough calc...
Of course this is a rough calc, but it gives you an indicator of the strength required, but the feat is going to be more or less around that level. If you don't have a timeframe, go with the minimum of 11.186km/s (or 11186m/s), which again assuming 0.1kg) gives us 6256329.8 joules.
Timeframe is roughly 1 second. TO find the distance, we'll angscale off the Earth by finding the Earths radius.
R = (h/2) + c^2/(8h)
= (204/2) + 1018^2/(8 X 204)
= 737.002451 pixels
That's for the radius of the Earth, so we'll double it for the diameter of the Earth, that being 1474.0049 pixels.
= 2*atan(972/(737.002451/tan(70/2)))
= 1.1170452 rad
= 64.00197548550571 degrees
The diameter of the Earth (at the equator) is 12,756km. Then we use an angscaling calculator (usually I use this one) to get a result of 1.0207e+4km (which is 10207km). To get the speed, I divide by the speed of sound at sea level (340.29m/s.
T = 10000km/1s
= 10000000/340.29
= Mach 29386.6996
To assume a mass just this once, I'm going to assume it weighs 0.1kg
M = (0.5)mv^2
= (0.5) X 0.1 X 10000000^2
= 5.0e12 joules
= 1.195028680688337 kilotons
Also...
If you're using a calculator don't forget to use m/s and not km/s because it will read it as m/s.
For some reason I thought of Omni-Man and Invincible playing baseball when I read the title