Calc Brand New Animal - Golden doggo goes awooooo

Alan's attack devastates a stadium. Take a note that the poduims are solid structures, so to get them to shift as they did would take a great amount of energy. Let's scale the size of the stadium from the stepsps. An outside step is on average 11 inches tall, or 27.94cm.
https://www.hunker.com/12377641/the-average-height-of-a-stair-step

On average, American architects have used a standard stair height of 7.5 inches. On stairs built inside, the average step length is 9 inches tall, while outside steps have an average length of 11 inches tall.

Click to expand...

22 pixels = 27.94cm
1 pixel = 27.94cm/22 = 1.27cm
1.27cm X 1009 = 1281.43cm
1.27cm X 385 = 488.95cm
1.27cm X 270 = 342.9cm
87 pixels = 1281.43cm
1 pixel = 1281.43cm/87 = 14.7290805cm
14.7290805cm X 58 = 854.286669cm
14.7290805cm X 117 = 1723.30242cm
14.7290805cm X 154 = 2268.2784cm

Volume of that area as an irregular trapezium, which we'll find by finding the area of a rectangle and a triangle.

A = lh
= 2268.2784 X 854.286669
= 1937760cm^2

H = 1281.43cm - 854.286669cm
= 427.143331cm

A = ab/2
= 2268.2784 X 427.143331/2
= 484439.996cm^2

A = 1937760 + 484439.996
= 2422200cm^2

Now we have that, to find the width of each section as well as the distance they moved.
1.27cm X 1037 = 1316.99cm
1.27cm X 794 = 1008.38cm
1.27cm X 65 = 82.55cm
1.27cm X 231 = 293.37cm

We'll find the volume of both as trapezoidal prisms.

V = Ah
= 2422200 X 1008.38
= 2442498036cm^3
= 2442.498036m^3

V = Ah
= 2422200 X 1316.99
= 3190013178cm^3
= 3190.013178m^3

There's also the seats themselves to take into acount, but given there's another podium being moved and the ground itself, it would cover that. Next up, the distance moved.

L = 488.95cm - 293.37cm
= 195.58cm

L = 342.9cm - 82.55cm
= 260.35cm

Concrete weighs about 2.4 tonnes for each cubic metre, which is 2400kg.

M = 2442.498036 X 2400kg
= 5861995.29kg

M = 3190.013178 X 2400kg
= 7656031.63kg

Now we've gotten all that out of the way, we get to the easy part; the timeframe.
Timeframe is 5 frames.

T = 1s/24
= 41.6666667ms X 5
= 0.208333333s

With all that out of the way, we can finally get to our kinetic energy!

T = 195.58cm/0.208333333s
= 9.38784002m/s

KE = (0.5)mv^2
= (0.5) X 5861995.29 X 9.38784002^2
= 258313337 joules

T = 260.35cm/0.208333333s
= 12.4968m/s

KE = (0.5)mv^2
= (0.5) X 7656031.63 X 12.4968^2
= 597821269 joules

E = 258313337 + 597821269
= 856134606 joules
= 0.20462108174 tons of TNT

Final Results
Alan devastates a stadium = > 0.205 tons of TNT

Keep in mind too there was another podium, so ultimately this would be even higher.