Spoilers for Godzilla vs Kong, so precede at your own caution if you've yet to see the movie.
1. Gravitational inversion of the Earth
To travel to the core of the planet requires withstanding the gravitational inversion of the entire planet. Meaning? You'd have to survive the gravity of an entire planet to survive entering the core. Legendary Kong as of Godzilla vs Kong is 102m tall. The mass of the Earth is 5.97200e24kg.
H = 102m/2
= 51m
We'll caalculate the energy with GPE. Why? It's the force of pressure and mass Kong has to endure. The acceleration of gravity at the inner core is 4.3 m/s^2
GPE = 5.97200e24 X 51 X 4.3
= 1.3096596e27 joules
= 313.01615678776289542 petatons
That's not all; the Hollw Earth Aerial Vechiles also survive the journey to the core. How durable would they be? At a low end estimate, we'll put their height at 2m.
GPE = 5.97200e24 X 2 X 4.3
= 5.13592e25 joules
= 12.275143403441683532 petatons
Kong crushes one of the HOAVs with one hand, and another is destroyed by the snake monsters. They even comment on how they don't think the Hollow Earth inversion is a threat to Kong. Which brings us to our next feat...
2. Travelling to the Earth's core.
Kong and the HOAVs are launched over 2000km in 2 seconds.
T = 2000km/2s
= 1000000/340.29
= Mach 2938.66996
Kong's mass as of Godzilla vs Kong is unknown, but he is much bigger and heavier than he was in Skull Island, where he weighed 158 tons (or 158,000kg). This is a ridiculous low end considering Godzilla weighs tens of thousands of tons, but it's the best we've got for now.
KE = (0.5)mv^2
= (0.5) X 158000 X 1000000^2
= 7.9e16 joules
= 18.88145315487571807 megatons
3. Kong returns to the surface
Kong returns to the surface to battle Godzilla. What's the timeframe?
1 minute and 28 seconds, or 88 seconds.
The distance from the Earth's surface to its core is 2900km.
T = 2900km/88s
= 32954.5455/340.29
= Mach 96.8425328
There's never any harm in getting kinetic energy.
KE = (0.5)mv^2
= (0.5) X 158000 X 32954.5455^2
= 8.57941635e13 joules
= 20.505297203632889 kilotons
Remember, that mass is just a low end from his younger self.
Final Results
Kong survives the planets gravitational inversion = 313.016 petatons
Hollow Earth Aerial Vechile's durability = 12.275 petatons
Kong and Monarch travel to the core = Mach 2938.67
Kinetic energy of Kong reaching the Earths core = >18.881 megatons
Kong climbs to the surface (speed) = Mach 96.8425328
Kong climbs to the surface (energy) = >20.502 kilotons
1. Gravitational inversion of the Earth
To travel to the core of the planet requires withstanding the gravitational inversion of the entire planet. Meaning? You'd have to survive the gravity of an entire planet to survive entering the core. Legendary Kong as of Godzilla vs Kong is 102m tall. The mass of the Earth is 5.97200e24kg.
H = 102m/2
= 51m
We'll caalculate the energy with GPE. Why? It's the force of pressure and mass Kong has to endure. The acceleration of gravity at the inner core is 4.3 m/s^2
GPE = 5.97200e24 X 51 X 4.3
= 1.3096596e27 joules
= 313.01615678776289542 petatons
That's not all; the Hollw Earth Aerial Vechiles also survive the journey to the core. How durable would they be? At a low end estimate, we'll put their height at 2m.
GPE = 5.97200e24 X 2 X 4.3
= 5.13592e25 joules
= 12.275143403441683532 petatons
Kong crushes one of the HOAVs with one hand, and another is destroyed by the snake monsters. They even comment on how they don't think the Hollow Earth inversion is a threat to Kong. Which brings us to our next feat...
2. Travelling to the Earth's core.
Kong and the HOAVs are launched over 2000km in 2 seconds.
T = 2000km/2s
= 1000000/340.29
= Mach 2938.66996
Kong's mass as of Godzilla vs Kong is unknown, but he is much bigger and heavier than he was in Skull Island, where he weighed 158 tons (or 158,000kg). This is a ridiculous low end considering Godzilla weighs tens of thousands of tons, but it's the best we've got for now.
KE = (0.5)mv^2
= (0.5) X 158000 X 1000000^2
= 7.9e16 joules
= 18.88145315487571807 megatons
3. Kong returns to the surface
Kong returns to the surface to battle Godzilla. What's the timeframe?
1 minute and 28 seconds, or 88 seconds.
The distance from the Earth's surface to its core is 2900km.
T = 2900km/88s
= 32954.5455/340.29
= Mach 96.8425328
There's never any harm in getting kinetic energy.
KE = (0.5)mv^2
= (0.5) X 158000 X 32954.5455^2
= 8.57941635e13 joules
= 20.505297203632889 kilotons
Remember, that mass is just a low end from his younger self.
Final Results
Kong survives the planets gravitational inversion = 313.016 petatons
Hollow Earth Aerial Vechile's durability = 12.275 petatons
Kong and Monarch travel to the core = Mach 2938.67
Kinetic energy of Kong reaching the Earths core = >18.881 megatons
Kong climbs to the surface (speed) = Mach 96.8425328
Kong climbs to the surface (energy) = >20.502 kilotons
