Calc GaiGaiGar - Gai smashes Pizza into Pasdars lair

Calculations
7HkLaXN.gif

Gai smashes Pizza into the exterior of Pasdars lair with enough force to destroy the outer shell. We'll scale the beams width to Gai's width (this is the best we have, and from the looks of it, the beam is actually thicker than Gai). Gai is 200cm tall.
7HLfaiS.png
1068 pixels = 200cm (2m)
1 pixel = 2m/1068 = 0.00187265918m
0.00187265918m X 388 = 0.726591762m
TI53EhQ.png
17 pixels = 0.726591762m
1 pixel = 0.726591762m/17 = 0.0427406919m
0.0427406919m X 176 = 7.52236177m
0.0427406919m X 296 = 12.6512448m

That's our thickness, but the area is filled with holes, making the scaling just a bit tricky...
XXdi64V.png
214 pixels = 12.6512448m
1 pixel = 12.6512448m/214 = 0.0591179664m
0.0591179664m X 2188 = 129.35011m
0.0591179664m X 1637 = 96.776111m
0.0591179664m X 358 = 21.164232m
21.164232m/2 = 10.582116m
0.0591179664m X 1008 = 59.5909101m
59.5909101m/2 = 29.7954551m
0.0591179664m X 1038 = 61.3644491m
61.3644491m/2 = 30.6822246m
0.0591179664m X 710 = 41.9737561m
0.0591179664m X 282 = 16.6712665m
0.0591179664m X 106 = 6.26650444m
0.0591179664m X 697 = 41.2052226m
41.2052226m/2 = 20.6026113m
0.0591179664m X 195 = 11.5280034m

As there are several hole, we'll have to subtract the area for those. Volume of the main area as a rectangular prism.

V = lhw
= 129.35011 X 96.776111 X 7.52236177
= 94164.9292m^3

Volumes of the brown, yellow and red holes as cylinders).

V = πr^2h
= π X 10.582116^2 X 7.52236177
= 2646.36122m^3

V = πr^2h
= π X 29.7954551^2 X 7.52236177
= 20979.9348m^3

V = πr^2h
= π X 30.6822246^2 X 7.52236177
= 20979.9348m^3

Volume of the purple one as a semi-cylinder.

V = πr^2h
= π X 41.9737561^2 X 7.52236177
= 41635.114/2
= 20817.557m^3

Volume of the blue one as a quarter of an ellipsoid.

V = 4/3πabc
= 4/3 X π X 16.6712665 X 6.26650444 X 7.52236177
= 3291.82524/4
= 822.95631m^3

Volume of the pink one as a spherical cap (first though, we'll need the radius of the circle as a whole)....

ac6b6294509876e4bb09d25bebf54ea34afde11c


R = (h/2) + c^2/(8h)
= (195/2) + 697^2/(8 X 195)
= 408.916026 pixels

V = (1/3)πh^2(3R - h)
= (1/3) X π X 11.5280034^2 X (3 X 20.6026113 - 11.5280034)
= 6997.30194m^3

Now we have all the hollow areas, we'll had them up for our total hollow factor.

V = 2646.36122 + 20979.9348 + 22247.3239 + 20817.557 + 822.95631 + 6997.30194
= 74511.4352m^3

At last, let's get the amount of the ground that was destroyed.

V = 94164.9292 - 74511.4352
= 19653.494m^3

The section of the lair is destroyed pretty violently (they're sent flying), so I think violent fragmentation is justified.

E = 19653.494 X 69000000
= 1356091086000 joules
= 324.1135482791587 tons of TNT

Alternatively, we can use violent fragmentation for concrete, that being 17 joules/cm^3, or 17000000 joules/m^3.

E = 19653.494 X 17000000
= 334109398000 joules
= 79.8540626195029 tons of TNT

Final Results
Gai smashes Pizza into Pasdars lair (low end) = 79.854 tons of TNT
Gai smashes Pizza into Pasdars lair (high end) = 324.114 tons of TNT

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