The 11 Planetary Masters of Sol fly back to their crafts around the replica Moon in less than a second. We'll need to find the size in relation to the Moon (which has a radius of 1737.4km).
T = 1s/30
= 33.3333333ms X 6
= 0.2s
R = (h/2) + c^2/(8h)
= (19/2) + 806^2/(8 X 19)
= 4283.42105 pixels
4283.42105 pixels = 1737.4km
1 pixel = 1737.4km/4283.42105 = 0.405610371km
0.405610371km X 474 = 192.259316km
T = 192.259316km/0.2s
= 961296.58/340.29
= Mach 2824.93338
If this isn't enough, we can also get kinetic energy! The average weight of a man globally is 136.7 pounds (or 62.006077kg), which would fit with Palparepa and Pei La Cain at least.
KE = (0.5)mv^2
= (0.5) X 62.006077 X 961296.58^2
= 2.86496324e13 joules
= 6.8474264818355639
Final Results
11 Planetary Masters of Sol leave the replica Moon = Mach 2824.933
Kinetic energy of the 11 Planetary Masters of Sol leaving the replica Moon = 6.847 kilotons
