Calc GaoGaiGar - Good, our first catch of the day

ChoRyuJin hauls GaoGaiGar out of the deep sea, of a depth of 10,000m (or 10km).

最新型の深海探査艇の進水式にゾンダーが現れた。しかも、探査艇と融合したゾンダーロボEI-11の内部に護と華が囚われてしまったのだ。ＧＧＧ機動部隊はＧＧＧ諜報部と合同で救出作戦を開始する。まず多次元諜報潜水艦から潜行艇マリン1が発進するが、深度6千メートルで水圧に耐えきれずに圧壊してしまう。しかし、その中に潜んでいたガオガイガーは、ディバイディングドライバーで湾曲空間フィールドをつくり、深海への追跡を続行する。深海において湾曲空間フィールドの消滅する30分間がタイムリミットなのだ。ついに深海1万メートルでEI-11を撃破するが、タイムリミットを越えてしまう。しかし、護の未知の力が働き、全員無事に救出されるのだった。

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Sonder appeared at the launching ceremony of the latest deep-sea research vessel. Moreover, Mamoru and Hana were trapped inside the Zonder Robo EI-11, which was fused with the exploration boat. The GGG task force begins a joint rescue operation with the GGG intelligence department. First, the submarine Marine 1 launches from the multi-dimensional intelligence submarine, but it collapses at a depth of 6,000 meters because it cannot withstand the water pressure. However, the GaoGaiGar lurking within it creates a curved space field with the Dividing Driver and continues its pursuit into the deep sea. The time limit is 30 minutes when the curved space field disappears in the deep sea. EI-11 is finally defeated at a depth of 10,000 meters, but the time limit is exceeded. However, Mamoru's unknown power worked and everyone was safely rescued.

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Firstly, ChoRyuJins hooks reach 10,000m deep at astoundingly fast speeds, finding and rescuing his fellow Braves in just a few seconds.
Timeframe is 4 seconds and 2 frames (with a framerate of 30 frames per second).

T = 1s/30
= 33.3333333ms X 2
= 66.6666666ms + 4s
= 4.06666667s

T = 10,000m/4.06666667s
= 2459.01639/340.29
= Mach 7.22623759

It takes longer hauling GaoGaiGar up as it's a heavy machine, but even that is done in short time.
Timeframe is 27 seconds and 11 frames.

T = 33.3333333ms X 11
= 0.366666666s + 27s
=27.3666667s

T = 10,000m/27.3666667s
= 365.408039/340.29
= Mach 1.07381363

Of course, being a huge heavy machine, GaoGaiGar would weigh quite a bit. And it does, having a mass of 264.2 tons (or 264200kg)!

KE = (0.5)mv^2
= (0.5) X 264200 X 365.408039^2
= 1.76383929e10 joules
= 4.2156770793499 tons of TNT

If that's not enough, it's possible to go for an even higher yield, as GaoGaiGar is being pulled through water, which is far more viscous that air. The viscosity of water is 8.90e-4 Pa*S (or kg per m^2), while the viscosity of air is while the viscosity of air is 1.81e-5 kg/m^2.

8.90e-4/1.81e-5 = 49.1712707

Ergo, water is 49.1712707 times more viscous than air, and it would take 49.1712707 times more energy to move through water at such speeds (you can see this with bullets, which quickly loose momentum underwater).

E = 1.76383929e10 X 49.1712707
= 8.67302192e11 joules
= 207.290198852772 tons of TNT

This isn't the only impressive feat in this episode!


GaoGaiGar and EI-10 sink at incredibly fast speeds, and we even have the distances measured (about 1000m)!
Timeframe is 3 seconds and 6 frames.

T = 33.3333333ms X 6
= 0.2s + 3s
= 3.2s

T = 1000m/3.2s
= 312.5m/s

Final Results
ChoRyuJin's hooks find GaoGaiGar = Mach 7.226
ChoRyuJin hauls GaoGaiGar to the surface (speed) = Mach 1.074
ChoRyuJin hauls GaoGaiGar to the surface (energy - low end) = 4.216 tons of TNT
ChoRyuJin hauls GaoGaiGar to the surface (energy - high end) = 207.290 tons of TNT
GaoGaiGar sinks to the bottom of the Marina Trench = 312.5m/s