General Adiane (in Sayrune) sends a giant tidal wave crashing into Dai-Gurren. Unfortunately, as all the old calcs with Gurren Lagann's size in them have crashed, we're going to need to rescale. Kamina is 184cm tall.
1 pixel = 1.84m/52 = 0.0353846154m
0.0353846154m X 544 = 19.2492308m
0.0353846154m X 298 = 10.5446154m
Now scaling Gurren Lagann to Dai-Gunzan/Dai-Gurren...
1 pixel = 19.2492308m/142 = 0.135557963m
0.135557963m X 2162 = 293.076316m
At last we can get the height of the wave.
1 pixel = 293.076316m/470 = 0.62356663m
0.62356663m X 381 = 237.578886m
0.62356663m X 2076 = 1294.52432m
Next we need the distance it travelled and the width of the area it covered.
1 pixel = 237.578886m/257 = 0.924431463m
0.924431463m X 2880 = 2662.36261m
= 2*atan(257/(1612/tan(70/2)))
= 0.150793492 rad
= 8.63983066966117619 degrees
When we enter this into the angscaler, we get a distance of 1572.5m of the wave to Dai-Gurren. To add the minimum distance it travelled after passing Dai-Gurren...
L = 1572.5m + 1294.52432m
= 2867.02432m
With length, height and width, we can add all of those together for our volume, and from volume, our mass. Volume as a rectangular prism.
V = lhw
= 237.578886 X 2662.36261 X 2867.02432
= 1.8134535e9m^3
Water weighs 1000kg/m^3.
M = 1.8134535e9 X 1000kg
= 1813453500000kg
So that's all the dimensions required for size, all we need now is the speed. How fast did the wave traverse the screen?
T = 1s/24
= 41.6666667ms X 23
= 0.958333334s
T = 1294.52432m/0.958333334s
= 1350.80799m/s
With everything we need, let's get our kinetic energy!
KE = (0.5)mv^2
= (0.5) X 1813453500000 X 1350.80799^2
= 1.65448818e18 joules
= 395.43216539196941994 megatons
Final Results
Gurren Lagann height = 19.249m
Dai-Gurren length = 293.076m
Sayrune creates a giant tidal wave = 395.432 megatons
