Always listen to technobabble, you never know when it could pay off big. On a rewatch, I noticed a few interesting pieces of technobabble that I, and everyone else, had overlooked. The first was absorbing the mass energy of the Spiral Death Fields compressed space-time, and the other is this...
The Ashtanga vanishes through the portal, and LordGemone gives this explanation of where they went.
By manipulating multidimensional space, the Ashtanga can manipulate probability and move up and down the time axis. The Schrödinger Warp backs this up, as their actions are unknown until they take them, allowing them to exist in multiple different places at the same time.
Super Galaxy Gurren Lagann responds by sending a barage into all nearby points of space-time.
Note also the number of times the single Ashtanga appears on the charts.
Tetukan comments on a planck time coefficient, and Leeron says not to worry about it, and that all of their shots will be hits thanks to the probability manipulation There's another translation where he says "we can fire randomly and still hit them!").
Simon then finishes off with this;
They fire the beams into the past, present and future and blast the dreadnaught out of it's hiding place in the probability space.
Leeron then points out the ship has built up immense energy, like a galaxy is about to be born.
So to sum up what happened; Super Galaxy Gurren Lagann fired attacks into every planck instant and hit with every one of them. If you need further confirmation of this, the Glossary in Final Drill confirms that the Mega Maelstrom Vortex Cannon fired missiles into every point in space and time in every dimension.
(The relevant part)
We'll need the width of the Ashtanga. I previously calc'd their dimensions here, but to repost said information below briefly...
Now let's scale the height of the Ashtanga to one of the craters.
1712 pixels = 32005.1399km
1 pixel = 32005.1399km/1712 = 18.6945911km
18.6945911km X 116 = 2168.57257km (2168572.57m)
2168572.57m/2 = 1084286.28m
Volume as a demi-sphere.
V = 4/3πr^3
= 4/3 X π X 1084286.28^3
= 5.33974474e18/2
= 2.66987237e18m^3
Given there's no chunks of rock floating around the craters and from the way the missiles exploded, I think it's fair enough to say the craters were violently fragmented. The violent fragmentation of rock per m^3 is 8000000.
E = 2.66987237e18 X 8000000
= 2.1358979e25 joules
We're aren't done yet though! As stated above, the missiles aim for near past -10, near future +8. As the Ashtanga Dreadnaught hasn't instantly blinked back into existence, they would be refering to a few seconds here (the innumerable number of times it pops up on the radar backs this up). There are 10^43 planck instances in a single second. Now let's work some magic!
E = 8 + 10
= 18 X 10^43
= 1.8e44 X 2.1358979e25
= 3.84461622e69 joules
That's pretty impressive, but we're not only talking every point in time, but every point in space too. We can count a minimum amount of points in space through the portals opened by Super Galaxy Gurren Lagann. This is simultaneously the easiest and hardest part...
There are at least 181 portals.
E = 3.84461622e69 X 181
= 6.95875536e71 joules
And that's not the end of it. Not only did it target every point in space and time on a planck scale, but also every dimension, of which there are at least 11.
E = 6.95875536e71 X 11
= 7.6546309e72/10^44
= 76.546309 NINAFOE
As another value, the manga says that prior to the Ashtanga appearing in realspace to battle Super Galaxy Dai-Gurren (before the Galactic Spiral Abyss), the Spiral Radar picks up 10^68 enemies.
E = 2.1358979e25 X 10^68
= 2.1358979e93/10^44
= 21.358979 TENAEXAFOE
Final Results
Maelstrom Mega Vortex Cannon (low end) = 76.546 NINAFOE
Maelstrom Mega Vortex Cannon (high end) = 21.359 TENAEXAFOE
The Ashtanga vanishes through the portal, and LordGemone gives this explanation of where they went.
By manipulating multidimensional space, the Ashtanga can manipulate probability and move up and down the time axis. The Schrödinger Warp backs this up, as their actions are unknown until they take them, allowing them to exist in multiple different places at the same time.
Leeron then points out the ship has built up immense energy, like a galaxy is about to be born.
The kanji being used for every is "あらゆる" which means that indeed yes, the missiles are being fired into every possible point in time alone the time axis. Needless to say, this is going to be incredible. Even if we go with one joule for each attach, it will be more than comparable to a supernova. We can't get the explosions themselves as each was in space, and the shots were all energy beams and FTL anyway (from Tacocats calcs), but thankfully, we can get the energy of the attacks by looking at the damaged Ashtanga. It's covered in smoldering pockmarks that weren't there before.Final Drill said:
We'll need the width of the Ashtanga. I previously calc'd their dimensions here, but to repost said information below briefly...
The diameter of the Moon is 3474.2km.
932 pixels = 3474.2km
1 pixel = 3474.2km/932 = 3.7276824km
3.7276824km X 432 = 1610.3588km
364 pixels = 1610.3588km
1 pixel = 1610.3588km/364 = 4.42406264km
4.42406264km X 878 = 3884.327km
744 + 704 = 1448 pixels
4.42406264km X 1448 = 6406.0427km
Now onto the Ashtanga.
105 pixels = 1610.3588km
1 pixel = 1610.3588km/105 = 15.3367505km
15.3367505km X 1072 = 16440.9965km
300 pixels = 16440.9965km
1 pixel = 16440.9965km/300 = 54.8033217km
54.8033217km X 1388 = 76067.0105km
54.8033217km X 584 = 32005.1399km
1 pixel = 3474.2km/932 = 3.7276824km
1 pixel = 1610.3588km/364 = 4.42406264km
4.42406264km X 878 = 3884.327km
744 + 704 = 1448 pixels
4.42406264km X 1448 = 6406.0427km
Now onto the Ashtanga.
1 pixel = 1610.3588km/105 = 15.3367505km
15.3367505km X 1072 = 16440.9965km
1 pixel = 16440.9965km/300 = 54.8033217km
54.8033217km X 1388 = 76067.0105km
54.8033217km X 584 = 32005.1399km
1 pixel = 32005.1399km/1712 = 18.6945911km
18.6945911km X 116 = 2168.57257km (2168572.57m)
2168572.57m/2 = 1084286.28m
Volume as a demi-sphere.
V = 4/3πr^3
= 4/3 X π X 1084286.28^3
= 5.33974474e18/2
= 2.66987237e18m^3
Given there's no chunks of rock floating around the craters and from the way the missiles exploded, I think it's fair enough to say the craters were violently fragmented. The violent fragmentation of rock per m^3 is 8000000.
E = 2.66987237e18 X 8000000
= 2.1358979e25 joules
We're aren't done yet though! As stated above, the missiles aim for near past -10, near future +8. As the Ashtanga Dreadnaught hasn't instantly blinked back into existence, they would be refering to a few seconds here (the innumerable number of times it pops up on the radar backs this up). There are 10^43 planck instances in a single second. Now let's work some magic!
E = 8 + 10
= 18 X 10^43
= 1.8e44 X 2.1358979e25
= 3.84461622e69 joules
That's pretty impressive, but we're not only talking every point in time, but every point in space too. We can count a minimum amount of points in space through the portals opened by Super Galaxy Gurren Lagann. This is simultaneously the easiest and hardest part...
E = 3.84461622e69 X 181
= 6.95875536e71 joules
And that's not the end of it. Not only did it target every point in space and time on a planck scale, but also every dimension, of which there are at least 11.
E = 6.95875536e71 X 11
= 7.6546309e72/10^44
= 76.546309 NINAFOE
As another value, the manga says that prior to the Ashtanga appearing in realspace to battle Super Galaxy Dai-Gurren (before the Galactic Spiral Abyss), the Spiral Radar picks up 10^68 enemies.
So let's also use the value of 10^68 for the total number of times attacked.
E = 2.1358979e25 X 10^68
= 2.1358979e93/10^44
= 21.358979 TENAEXAFOE
Final Results
Maelstrom Mega Vortex Cannon (low end) = 76.546 NINAFOE
Maelstrom Mega Vortex Cannon (high end) = 21.359 TENAEXAFOE
