Calc Promare - Big robots are fast robots

Given the size of the mechas in this movie, it comes at not surprise that they'd be really fast.

1. Krazor X punch
1:11

Lio de Galo catches Krazor X's punch. To note how impressive this is, I'll point out the timeframe;
The punch happens in the span of 1 frame. Take notice also Lio de Galo reacts to and catches this punch in said frame.

T = 1s/24
= 41.6666667ms

Given Krazor X is over 148m tall, this is going to be super fast. Reminder that the average length of a compact sedan is 177.2 inches, or 4.50088m.
50 pixels = 4.50088m
1 pixel = 4.50088m/50 = 0.0900176m
0.0900176m X 925 = 83.26628m

T = 83.26628m/41.6666667ms
= 1998.39072/340.29
= Mach 5.87261077

It would also be possible to get kinetic energy for this, but given that would take a lot of fiddling around...maybe another time.

2. Lio de Galon's kick
1:43

Krazor X punches Lio de Galon across the city, but then Lio de Galon leaps back in the span of about a second and kicks Krazor X in the face. Krazor X's shoulder blade is 36.6187169m tall.

object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))

Click to expand...

= 2*atan(45/(1664/tan(70/2)))
= 0.0256255957 rad
= 1.468238481122232653 degrees

Entering the values of size and degrees into the angscaler, we get a distance of 1428.9m to Krazor X. Now for the timeframe.
Timeframe is 1.02 seconds.

T = 1428.9m/1.02s
= 1400.88235/340.29
= Mach 4.11673088

Final Results
Krazor X's punch = Mach 5.873
Lio de Galon's kick = Mach 4.117