Dynazenon carries an enemy kaiju up into space in seconds. How far above the Earth are they? We'll need to find the radius of the Earth.
R = (h/2) + c^2/(8h)
= (115/2) + 2827^2/(8 X 115)
= 8744.37935 pixels
The above is for the radius, so for the diameter of the Earth (12756km) we'll double the number of pixels, to get 17488.7587 pixels.
= 2*atan(17488.7587/(1619/tan(70/2)))
= 2.75569468 rad
= 157.88967479104562 degrees
Put that through this angscaler calculator and we get a distance of 1246.1km. How quickly did Dynazenon fly that distance?
13 seconds and 3 frames.
T = 1s/24
= 41.6666667ms
= 0.125s + 13s
= 13.125s
T = 1246.1km/13.125s
= 94940.9524/340.29
= Mach 279.000125
A big heavy thing moving at high velocities? What's stopping us from getting kinetic energy? Nothing I say! Dynazenon weighs 240,000 tons (or 240,000,000kg).
Burnaddon weighs 72,000 tons, or 72,000,000kg.
M = 240,000,000kg + 72,000,000kg
= 312000000kg
KE = (0.5)mv^2
= (0.5) X 312000000 X 94940.9524^2
= 1.40615037e18 joules
= 336.07800430210323839 megatons
Final Results
Dynazenon flies into space (speed) = Mach 279
Dynazenon flies into space (energy) = 336.078 megatons
