Calc Star Wars - Belsavis's power core

The World Razor is one of the most powerful beings in Star Wars (though still below the Ones & the Bedlam Spirits). It destroyed 100 stars and 1000 planets, took the full might of the Infinite Empire to enprison and is said to be a threat to the entire galaxy. The technology needed to enprison it within Belsavis is immensly powerful, as shown below...

14:00

The Old Republic said:

Doctor Gentrell: It's far, far worse than that. The power core derives energy from hyperspace itself. A detonation will send shock waves at lightspeed. Belsavis'sdestruction is only the beginning. The shockwaves will annihilate this entire system - and consume the ones adjacent to it. Trillions will die!

Click to expand...

Also at about the 10:30 mark or so refers to the planet being ripped apart, so it's indeed an explosion.

It refers to the nearby systems, so lets go with the second closest to the Sun, Barnards Star, 5.9630 lightyears away, or 56414300000000km (5.64143e+16m). Now we need the GBE of Barnards Star, and the radius of Barnards Star is 136,400km. In order to find the GBE, we'll need to know the size (272,800km in diameter, or 136,400km in radius, or 136400000m) and mass (2.86400e29kg) of Barnards Star.

U = 3GM^2/5R
= (3 X 6.67408e-11 X 2.86400e29^2)/(5 X 136400000)
= 2.40809888e40 joules

Next for the surface area of Barnards Star.

V = 4πr^2
= 4 X π X 136400000^3
= 3.18898866e25m^3

Now for the cross-sectional surface area of Barnards Star.

A = πr^2
= π X 136400000^2
= 5.84492057e16m^2

Then the surface area of the explosion.

A = 4πr^2
= 4 X π X 5.64143e+16^2
= 3.99933949e34m^2

Next we divide the total surface area of the explosion by the cross-sectional surface area of Barnards Star, then time sit by the GBE of Barnards Star before finally dividing by FOE (inverse square-law basically).

I = 3.99933949e34/5.84492057e16
= 6.84241889e17 X 2.40809888e40
= 1.64772213e58/10^44
= 164.772213000000 TERAFOE

Final Results
Belsavis's Power Core = 164.772 TERAFOE