(Episode 11)
Fine uses Kadingir to destroy the Moon, Chris blocks most of it but a large chunk of the Moon is still taken out. Diameter of the Moon is 3474.8km, or 3474800m.
443 pixels = 3474800m
1 pixel = 3474800m/443 = 7843.79233m
7843.79233m X 144 = 1129506.1m
1129506.1m/2 = 564753.05m
7843.79233m X 230 = 1804072.24m
1804072.24m/2 = 902036.12m
I...can't be bothered scaling all the swiggily part in detail, so I'm just going with the volume of an ellipsoid for now.
V = 4/3πabc
= 4/3 X π X 564753.05 X 564753.05 X 902036.12
= 1.20511837e18m^3
The mean density of the Moon is 3344kg/m^3.
M = 1.20511837e18 X 3344
= 4.02991583e21kg
Next up for the timeframe and the distance moved.
Timeframe is 3 seconds.
1021 pixels = 1129506.1m
1 pixel = 1129506.1m/1021 = 1106.27434m
1106.27434m X 936 = 1035472.78m
T = 1035472.78m/3s
= 345157.593m/s
Now for our energy.
KE = (0.5)mv^2
= (0.5) X 4.02991583e21 X 345157.593^2
= 2.40049521e32 joules
= 57.373212476099425317 zettatons
A dying Fine later drags this chunk down to Earth, so let's get that too.
Unfortunately, I can't find anything to scale from in that initial shot, but we get later shots of the distance travelled so we'll go with that.
The timeframe for the Nehushtan Armor reaching the moon is 3 seconds, and the timeframe for the Moon chunk falling is 142 seconds. Distance to the Moon is 384,400km away.
T = 384,400km/3s
= 128133333/299792458 X 100
= 42.7406793% C
= 0.161510163 rad
= 9.25385068839294256 degrees
Enter that through the angscaler and we get a distance of 11146000m from the Earth to the Moon chunk, or 11,146km.
T = 11,146km/142s
= 78492.9577/s
KE = (0.5)mv^2
= (0.5) X 4.02991583e21 X 78492.9577^2
= 1.24144467e31 joules
= 2.9671239722753344203 zettatons
Finally, for the Nehushtan Armor's return to Earth.
...Also three seconds, which means it will be the same.
Final Results
Kadingir's remaining power hits the Moon = 57.373 zettatons
Nehushtan Armor reaches/returns from the Moon = 42.741% C
Fine drags down Moon chunk = 2.967 zettatons
1 pixel = 3474800m/443 = 7843.79233m
7843.79233m X 144 = 1129506.1m
1129506.1m/2 = 564753.05m
7843.79233m X 230 = 1804072.24m
1804072.24m/2 = 902036.12m
I...can't be bothered scaling all the swiggily part in detail, so I'm just going with the volume of an ellipsoid for now.
V = 4/3πabc
= 4/3 X π X 564753.05 X 564753.05 X 902036.12
= 1.20511837e18m^3
The mean density of the Moon is 3344kg/m^3.
M = 1.20511837e18 X 3344
= 4.02991583e21kg
Next up for the timeframe and the distance moved.
1021 pixels = 1129506.1m
1 pixel = 1129506.1m/1021 = 1106.27434m
1106.27434m X 936 = 1035472.78m
T = 1035472.78m/3s
= 345157.593m/s
Now for our energy.
KE = (0.5)mv^2
= (0.5) X 4.02991583e21 X 345157.593^2
= 2.40049521e32 joules
= 57.373212476099425317 zettatons
A dying Fine later drags this chunk down to Earth, so let's get that too.
T = 384,400km/3s
= 128133333/299792458 X 100
= 42.7406793% C
= 2*atan(275/(1610/tan(70/2))
= 0.161510163 rad
= 9.25385068839294256 degrees
Enter that through the angscaler and we get a distance of 11146000m from the Earth to the Moon chunk, or 11,146km.
T = 11,146km/142s
= 78492.9577/s
KE = (0.5)mv^2
= (0.5) X 4.02991583e21 X 78492.9577^2
= 1.24144467e31 joules
= 2.9671239722753344203 zettatons
Finally, for the Nehushtan Armor's return to Earth.
Final Results
Kadingir's remaining power hits the Moon = 57.373 zettatons
Nehushtan Armor reaches/returns from the Moon = 42.741% C
Fine drags down Moon chunk = 2.967 zettatons
