Calc tales of a dirty mod recovering obd data part 4

Spoiler

Input 10.70267519001337382952546615m on both the length and width axis radius.
and 7.1351167933422492196836441m on the Height Axis Radius.

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Fluttershy said:

if said being was moss-like then I'd say some water got evaporated from it

that just needs 100C or so

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Spoiler

so, it's the shape of a human.
and he has a buffed body.
since his body is made of goo-like properties, i'll assume that it's water content is at least 90%.
now, his Upper Body Portion(Red Line) is 470.25312332827732px or equal to 47% of his total height.
Total Height is X(.47) = 470.25312332827732px.
x = 1000.53856027293046808511px
(someone correct me on this one if i'm wrong, as i'm not entirely sure about this.)
we perceive alibaba's height to be 89.95310782127793px.
Note that this scaling actually low-balls the Monsters height by a bit since alibaba is closer in our perspective.
back to the calc, Alibaba's Meter/Px with respect to height ratio is 0.01867639752189423433m/px.
so, we get the height of the monster to be 18.68645588764098360663494662m.

using the square cube law(v'=v(l'/l)^3),
where, V Prime = Volume of the Monster, V = Volume of the Human, L Prime = Height of The Monster, and L = Height of the Human.
human volume: 70/1000=0.07m^3
V' = 0.07*(18.68645588764098360663494662/1.7)^3
V' = 92.96770194789083420798896004953605m^3
What we need is only 90% of it so,...
Volume = 83.670931753101750787190064044582445m^3
Mass = 83670.931753101750787190064044582445kg
using this calculator, we'll know that the number of moles is 4644.442481777348.
or 188796586.8842491962J.
E = 0.045123467 tons.

However, this is only part of the energy, the water temperature must also be raised from 0(since they're inside a cave, it should be a lot cooler. by how much? idk though) to 100 degrees.
To heat water you need the weight in Kg*4200J*the amount of degrees you are heating it by.
We are heating it by 100 degrees.
E = 83670.931753101750787190064044582445*4200*100
E = 8.399089708 tons.

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E = 1707.48656549620365m^3*1000000cc*214.35J/cc
E = 87.476038555 tons worth of TNT

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the feat looks like it's melting and so, inputting it into the Star Destroyer Asteroid Calculator...

E = 2.5 kilotons. (Input 14.8293m in the Needed Diameter)

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Spoiler

first, a revision of the size of astral.
The Donut is 39px long.
The Dimension of the image is 702x352 px
using our new ang size values:
2*atan(tan(70/2)*(702/352) = 108.786461337076
2*atan(39/(702/tan(108.786461337076/2))) = 8.872220608342
i'm not really sure about this(the original blog is fucking hard to find).
so, comments are welcome, moreso if someone knows how to do this part.
with our angle already known, we can find the low end for the radius of Astral Nova.
just input 18000m as it's size, and 8.872220608342 for it's angle.
Distance turns out to be 116010m.
which is a bit larger than the original calc.
so, Astral's Diameter should be no lesser than 232020m.

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As stated by Ian, the farthest he could take Team Elmore was 40 km, so the distance between them and Astral Nova is easily 76.01 kilometers.
how's this relevant?
because, Uranus Traveled the whole distance in a short amount of time.
enough, that he has not been fucked by Frederica whilst in mid air.
so yeah, shits fast as hell.
now, i'm gonna use a range of values to get a low and higher end for this feat.
Range of 1-3 seconds.
(Low End) = 25336.67m/s ~ Mach 74.5
(Mid End) = 38005m/s ~ Mach 111.7
(High End) = 76010m/s ~ Mach 223.4

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Spoiler

so, we know that the distance is around 76.01 Kilometers.
we can use Total Fatalities as a low end then.
the Image's Dimension is 689x490 px.
The Blasts Width is 366px.
2*atan(tan(70/2)*(689/490) = 89.109509047936
2*atan(366/(689/tan(89.109509047936/2))) = 55.220228614644
so, just input 76010 as distance and 55.220228614644 as angle.
size came out to be 79508m ~ 3.4 Gigatons.
and that's still a low-end.

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