Calc The Umbrella Academy - The day the Eiffel Tower went Berserk

From the very first issue of the series, a young Luther punches down the Eiffel Tower. First, we'll need the dimensions of the Eiffel Tower, which thankfully come easy, being 325m tall.
511 pixels = 325m
1 pixel = 325m/511 = 0.636007828m
0.636007828m X 11 = 6.99608611m
0.636007828m X 18 = 11.4481409m
87 pixels = 6.99608611m
1 pixel = 6.99608611m/87 = 0.0804147829m
0.0804147829m X 561 = 45.1126932m
45.1126932m/2 = 22.5563466m
0.0804147829m X 59 = 4.74447219m

Volume as a spherical cap.

V = (πh^2(3r - h))/(3)
= (π X 4.74447219^2(3 X 22.5563466 - 4.74447219))/(3)
= 1483.28522m^3

Fragmentation of rock is 8000000 joules/m^3.

E = 1483.28522 X 8000000
= 11866281760 joules
= 2.8361094072658 tons of TNT

On top of that, let's also find the speed. We'll need the distance the Eiffel Tower fell. Given the Eiffel Tower is on its side, it is a safe bet to assume it would have gone from standing up to lying over. Ergo, the arc would be between the radii of a 90 degree angle (the radii being the height of the Eiffel Tower).

For the formula, we'll need to convert the degrees to radians, that being

L = rΘ
= 325 X 1.5708
= 510.51m

A retangular has a drag coefficient of 2.1. Using the above joulage, we can find out how fast it fell. We also need the area of the square of the top part that hit the ground.

A = 6.99608611 X 11.4481409
= 80.0921795m^2

DF = ½ρCAv2 X d
11866281760 X 2 = 2.1 X 80.0921795 X 510.51
V^2 = 23732563520/85864.503
V^2 = 276395.515
V = 525.7333116704705/340.29
= Mach 1.54495669

Final Results
Luther punches over the Eiffel Tower (energy) = 2.836 tons of TNT
Luther punches over the Eiffel Tower (speed) = Mach 1.545