Trigger-verse calc archive

[Stocking Anarchy]

The detonation of the Klaxosaur Bomb causes an explosion seen all the way back on Earth. Strelizia True Apus is noted to be so far from Earth that there are no recognisable stars, and the sky and perspective is completely different (there are also noticably more stars in the sky than in space in the Solar System).

Spoiler

But a better indicator of the distance comes several episode earlier during episode 21, when the Klaxosaur Princess is talking about the initial VIRM attack.


We can see at least 6 Spiral galaxies, excluding the Milky Way (the first galaxy is a bit hard to see as it's only visible in the fade in, but you can definately see it there).

Spoiler

This could be a bit tricky to calc the distance for, but we can get a minimum distance scaling from the Milky Way, which has a diameter of 100,000 lightyears, or 9.4605284e20m.

Spoiler

object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))

= 2*atan(314/(1614/tan(70/2)))
= 0.18383961 rad
= 10.533233760357172 degrees

Enter that through the angscaler, and we can determine that the Milky Way is at least 5131600000000000000000m away. The full shot is even further away, but for now let's leave it at that. The light is clearly visible in the middle of the day and from across the Universe, which would mean if'd have to be at least comparable to the luminousity of the Sun. The apparent magnitude of the Sun is -26.74.

-26.74 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(5131600000000000000000))^2)
(146000000000/(5131600000000000000000))^2) = 8.09468809e-22
-26.74 - -26.73 = 8.09468809e-22/((L/3.846*10^26)
-0.01 = -2.5Log(8.09468809e-22/((L/3.846*10^26))
-0.01/-2.5 = (8.09468809e-22/((L/3.846*10^26))
10^(0.004) = (8.09468809e-22/((L/3.846*10^26))
1.00925289 = (8.09468809e-22/((L/3.846*10^26))
1.00925289 X (3.864*10e26) = 9.46317256e-10
3.89975317e27/8.09468809e-22 = 4.81766947e48 joules

The light lasts 3 days.

Spoiler

T = 60 X 60 X 24 X 3
= 259200s

E = 4.81766947e48 X 259200
= 1.24873993e54/10^44
= 12.487399300 GIGAFOE

Final Results
Klaxosaur Bomb = >12.487 GIGAFOE

 

[Stocking Anarchy]

Chlorophytum blasts open the way, melting a heap of rubble in the way. However, this leaves her depowered and even turns Ikuno's hair white. Given though that we previously see Chlorophytum perform a full power attack without depowering or Ikuno getting crippled though...


...I'm pretty sure this has to do with the magma energy itself and VIRMs interference, or something along those lines. Meaning outside that? Chlorophytum is more than capable of pulling this off just fine, and has done so. Previously I calced Strelizia to be 54.969m tall.

Spoiler

550 pixels = 54.969m
1 pixel = 54.969m/550 = 0.0999436364m
0.0999436364m X 50 = 4.99718182m

Scaling from Strelizia to Delpinium to the corridor.

Spoiler

364 pixels = 4.99718182m
1 pixel = 4.99718182m/364 = 0.0137285215m
0.0137285215m X 564 = 7.74288613m

Spoiler

173 pixels = 7.74288613m
1 pixel = 7.74288613m/173 = 0.0447565672m
0.0447565672m X 2662 = 119.141982m

Now to scaling the dimensions of the attack.

Spoiler

1199 pixels = 119.141982m
1 pixel = 119.141982m/1199 = 0.0993677915m
0.0993677915m X 941 = 93.5050918m
93.5050918m/2 = 46.7525459m

object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))

= 2*atan(941/(1612/tan(70/2)))
= 0.539683688 rad
= 30.9215975945318178 degrees

Enter that through the angscaler and the closer end of the melted rubble is 169.03m away.

object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))

= 2*atan(430/(1612/tan(70/2)))
= 0.251446322 rad
= 14.4068130247232382 degrees

The hole at the further end of the tunnel is 369.91m away. Now we can get the total length of the melted metal.

L = 369.91m - 169.03m
= 200.88m

Volume of the tunnel as a cylinder (obviously).

V = πr^2h
= π X 46.7525459^2 X 200.88
= 1379421.86m^3
= 1379421860000cm^3

Energy to melt steel is 7309.87 joules/cm^3.

E = 1379421860000 X 7309.87
= 1.00833945e16 joules
= 2.4099891252390057694 megatons

Final Results
Chlorophytum blasts opens a path = 2.41 megatons

 

[Stocking Anarchy]

Strelizia Apus is one absolutely colossal mecha, and given there are a few calcs I have in mind for it, I'll scale it's size and mass here. Nisigoori has said Strelizia True Apus is around 10km tall, but given her size next to the 3km Plantations, that size seems way off. Machine scaling is never easy, and in the case of Strelizia Apus & True Apus this is very much so. Strelizia Apus was formed from Star Entity, which we can scale from Plantation 13. Plantations have a height of 1200m.

Spoiler

Star Entity's crushes Plantation 13 between its index and middle finger.

Spoiler

181 pixels = 1200m
1 pixel = 1200m/181 = 6.62983425m
6.62983425m X 358 = 2373.48066m

That's the easy part done, now to scale the dimensions of Strelizia Apus, starting with all the pointy armour...

Spoiler

6 pixels = 2373.48066m
1 pixel = 2373.48066m/6 = 395.58011m
395.58011m X 74 = 29272.9281m
395.58011m X 126 = 49843.0939m
395.58011m X 135 = 53403.3148m
395.58011m X 91 = 35997.79m
35997.79m/2 = 17998.895m
395.58011m X 147 = 58150.2762m
395.58011m X 70 =
58150.2762m + 27690.6077m = 85840.8839m

Spoiler

395.58011m X 9 = 3560.22099m
395.58011m X 154 = 60919.3369m
395.58011m X 119 = 47074.0331m
395.58011m X 371 = 146760.221m
395.58011m X 207 = 81885.0828m
81885.0828m/2 = 40942.5414m
395.58011m X 667 = 263851.933m
395.58011m X 102 = 40349.1712m
395.58011m X 117 = 46282.8729m
46282.8729m/2 = 23141.4365m

Spoiler

395.58011m X 201 = 79511.6021m
395.58011m X 74 = 29272.9281m
29272.9281m/2 = 14636.4641m
395.58011m X 130 = 51425.4143m
51425.4143m/2 = 25712.7071m
395.58011m X 198 = 78324.8618m
395.58011m X 169 = 66853.0386m
66853.0386m/2 = 33426.5193m
395.58011m X 352 = 139244.199m

Shall we begin? Volume of her knee protectors and leg protectors as triangles added together.

A = hbb/2
= 29272.9281 X 49843.0939/2
= 729526652m^2

Then we times that by the depth to get the volume, and times it by two for both knees.

V = 729526652 X 3560.22099
= 2.5972761e12 X 2
= 5.1945522e12m^3

A = hbb/2
= 29272.9281m^2

V = 29272.9281 X 53403.3148/2
= 781635697 X 3560.22099
= 2.78279581e12 X 2
= 5.56559162e12m^3

Next, for the interior parts, as two pyramids, with the above volumes subtracted.

V = 1/3AH
= 1/3 X 729526652 X 29272.9281
= 7.11846041e12 X 2
= 1.42369208e13 - 5.1945522e12
= 9.0423686e12m^3

V = 1/3AH
= 1/3 X 781635697 X 29272.9281
= 7.62692185e12 X 2
= 1.52538437e13 - 5.56559162e12
= 9.68825208e12m^3

V = 9.0423686e12 + 9.68825208e12
= 1.87306207e13m^3

In order to get the surface area of a cone I entered the values (17998.895m in radius and 58150.2762m high) into a calculator and got 4460000000m^2.

V = 4460000000 X 3560.22099
= 1.58785856e13 X 2
= 3.17571712e13m^3

Interior part as a cone (with the above subtracted, and again times by two for both of them).

V = πr^2h/3
= π X 17998.895^2 X 58150.2762/3
= 1.97275016e13 X 2
= 3.94550032e13 - 3.17571712e13
= 7.697832e12m^3

Volume of her leg protectors as triangles. Note of the upper two triangles she has two on each leg, which gives us a total of four.

A = hbb/2
= 60919.3369 X 47074.0331/2
= 1.43385944e9 X 4
= 5735437760m^2

V = 5735437760 X 3560.22099
= 2.04194259e13m^3

Now for the lower leg triangles.

A = hbb/2
= 146760.221 X 60919.3369
= 8.94053535e9 X 4
= 35762141400m^2

V = 35762141400 X 3560.22099
= 1.27321126e14m^3

The interior parts as triangular pyramids.

V = 1/3AH
= 1/3 X 8.94053535e9 X 60919.3369
= 1.81550495e14 X 2
= 3.6310099e14 - 1.27321126e14
= 2.35779864e14m^3

For the huge thing on the back we'll use a cone for the back end, which for the surface area we'll once again enter the values (a radius of 40942.5414m and 263851.933m long) through a calcuator, which reveals a surface area of 39600000000m^2.

V = 39600000000 X 3560.22099
= 1.40984751e14m^3

For the interior parts, we'll use a cone (subtracting the above, of course).

V = πr^2h/3
= π X 40942.5414^2 X 263851.933/3
= 4.63167942e14 - 1.40984751e14
= 3.22183191e14m^3

For the front end, we'll use a frustrated conical frustrum. Using this calculator here, we can determine it has a total surface area of 15827400000m^2.

V = 15827400000 X 3560.22099
= 5.63490417e13m^3

Next, of course, its interior dimensions.

V = (1/3)π(r^2+rR+R^2)h
= (1/3) X π X (23141.4365^2 + 23141.4365 X 40942.5414 + 40942.5414^2) X 40349.1712
= 1.33491102e14 - 5.63490417e13
= 7.71420603e13m^3

Now for the volume of the back legs as two cylinders and a cone. First segment...

A = 2πrh + 2πr^2
= 2 X π X 14636.4641 X 79511.6021 + 2 X π X 14636.4641^2
= 8.65819662e9m^2

V = 8.65819662e9 X 3560.22099
= 3.08250933e13m^3

V = πr^2h
= π X 14636.4641^2 X 79511.6021
= 5.35121895e13 - 3.08250933e13
= 2.26870962e13m^3

Second segment...

A = 2πrh + 2πr^2
= 2 X π X 25712.7071 X 78324.8618 + 2 X π X 25712.7071^2
= 1.68080707e10m^2

V = 1.68080707e10 X 3560.22099
= 5.98404461e13m^3

V = πr^2h
= π X 25712.7071^2 X 78324.8618
= 1.62684102e14m^3

V = 1.62684102e14 - 5.98404461e13
= 1.02843656e14m^3

Third segment, as a cone. Once again using the calculator (for a radius of 33426.5193m and a length of 139244.199m) we get a surface of area 18500000000m^2.

V = 18500000000 X 3560.22099
= 6.58640883e13m^3

V = πr^2h/3
= π X 33426.5193^2 X 139244.199/3
= 1.62925117e14m^3

V = 1.62925117e14 - 6.58640883e13
= 9.70610287e13m^3

Now to add the exterior and interior parts together.

V = 3.08250933e13 + 5.98404461e13 + 6.58640883e13
= 1.56529628e14m^3

V = 2.26870962e13 + 1.02843656e14 + 9.70610287e13
= 2.22591781e14 X 2
= 4.45183562e14m^3

Last but not least, we need the values of the humanoid part of Stelitzia Apus.

Spoiler

315 + 195 + 329 = 839
395.58011m X 839 = 331891.712m = 331.891712km

To find the surface area of her body, we'll scale up from a female body using square-law. Zero-Two is 170cm (or 1.7m) and the average mass of a 16 year old girl is 53.5kg.

M2 = (H2/H1)^3*M1
= (331891.712/1.7)^3*53.5
= 3.98103724e17kg

Entering the heigh and mass into this calculator, we get a variable number of surface areas, so let's get an average (ignoring the Biyd and Schlich formula's, as both are outliers on both end of the scale).

A = 16217846544.78 + 17874819076.91 + 18581529949.17 + 18728961353.28 + 22526536559.03 + 27694900835.94
= 1.21624594e11/8
= 15203074250m^2

V = 15203074250 X 3560.22099
= 5.41263041e13m^3

For our volume for the interior, we'll be using this forumla...

V = m/d
V = volume
m = mass
d = density

The average density of the human body (from the above link) is 1010 kg/m^3.

V = 3.98103724e17/1010
= 3.94162103e14m^3

V = 1.43796025e15 - 5.41263041e13
= 1.38383395e15m^3

At last, we can add everything together for our mass. First for the exterior...

V = 5.1945522e12 + 5.56559162e12 + 3.17571712e13 + 2.04194259e13 + 1.27321126e14 + 1.40984751e14 + 5.63490417e13 + 4.45183562e14 + 5.41263041e13
= 886901525720000m^3

...then for the interior.

V = 1.87306207e13 + 7.697832e12 + 2.35779864e14 + 3.22183191e14 + 7.71420603e13 + 4.45183562e14 + 1.38383395e15
= 2490551080000000m^3

For our exterior armour, we'll steel, which weighs 7850kg/m^3 (usually I go with titanium, but given the interior part below seems a lot lighter than it should I think steel is a good choice).

M = 886901525720000 X 7850
= 6.96217698e18kg

Now for the mechanical unseen interior, which is somewhat harder. The light ship mass of container vessel 2700TEU is 102.56kg/m^3 (or 0.10256g/cm^3). I've a feeling this is a colossal low end, but it's the best I've got for now, so I'll take it.

M = 2490551080000000 X 102.56
= 2.55430919e17kg

Finally, to add both together for our final mass.

M = 6.96217698e18 + 2.55430919e17
= 7.2176079e18kg
= 7217607900000000 tons

Final Results
Strelizia Apus' size = 331.892km
Strelizia Apus' mass = 7217607900000000 tons

I'm not sure if the scaling is entirely accurate, but given there'd be a lot more unseen machinery (such as under the back part where we can see some engines) it would be even greater in mass, though that's the best I can do with what I've got. Strelizia True Apus would be equal in size and mass.

 

[Stocking Anarchy]

Strelizia True Apus spams a ton of beams real fast. More or less straight forward. Previously I calced Strelizia Apus' arm protectors to be 85840.8839m long.

Spoiler

144 pixels = 85840.8839m
1 pixel = 85840.8839m/144 = 596.117249m
596.117249m X 1732 = 1032475.08m

Spoiler

Timeframe is 1 frame.

T = 1s/24
= 41.6666667ms
= 1032475.08m/41.6666667ms
= 24779401.9/340.29
= Mach 72818.4839

Final Results
Strelizia True Apus' beam spam = Mach 72818.484

 

[Stocking Anarchy]

Stelitzia rams Hringhorni through the VIRM fleets and into the VIRM home planet at incredible speeds. Thankfully, we already have the dimensions for Strelizia Apus sorted, but now we need Hringhorni's dimensions. This should be much easier than Strelizia Apus's dimensions. Strelizia Apus' arm protectors are 85840.8839m long, and those on Strelizia True Apus should be a similar length.

Spoiler

505 pixels = 85840.8839m
1 pixel = 85840.8839m/505 = 169.981948m
169.981948m X 2166 = 368180.899m
169.981948m X 123 = 20907.7796m

Spoiler

36 pixels = 20907.7796m
1 pixel = 20907.7796m/36 = 580.771656m
580.771656m X 1096 = 636525.735m
580.771656m X 276 = 160292.977m

It's not a perfect triangle, but given there's also other pyramidal parts sticking out, I figures it'd even out.

Spoiler

503 pixels = 160292.977m
1 pixel = 160292.977m/503 = 318.673911m
318.673911m X 92 = 29317.9998m

With all that done, let's get our volume by adding all three triangular parts together as triangular pyramids. To get that though, we need the area of the triangle first.

A = hbb/2
= 636525.735 X 160292.977/2
= 5.10153025e10m^2

V = 1/3AH
= 1/3 X 5.10153025e10 X 29317.9998
= 4.98555543e14 X 3
= 1.49566663e15m^3

Now for the shaft.

Spoiler

812 pixels = 636525.735
1 pixel = 636525.735/812 = 783.898688m
783.898688m X 319 = 250063.681m
783.898688m X 32 = 25084.758m
25084.758m/2 = 12542.379m

Volume as a cylinder.

V = πr^2h
= π X 12542.379^2 X 250063.681
= 1.23583455e14m^3

There are other bits too, but...eh. Let's get our total volume.

V = 1.49566663e15 + 1.23583455e14
= 1.61925008e15m^3

Hringhorni is made out of Klaxosaur cores, which are composed of some form of weird goo, so we'll go with the mass of water, that being 1000kg/m^3.

M = 1.61925008e15 X 1000
= 1.61925008e18kg

As previously caclulated, Strelizia Apus weighs 7.2176079e18kg, and Strelizia True Apus should weigh the same.

M = 7.2176079e18 + 1.61925008e18
= 8.83685798e18kg

Now all that's left is the easy, fun part!

Spoiler

43 pixels = 368180.899m
1 pixel = 368180.899m/43 = 8562.34649m
8562.34649m X 1349 = 11550605.4m

Spoiler

Timeframe is 3 seconds.

852 pixels = 11550605.4m
1 pixel = 11550605.4m/852 = 13557.0486m
13557.0486m X 695 = 9422148.78m

T = 9422148.78m/3s
= 3140716.26/340.29
= Mach 9229.52852

At these velocities, we can just start to apply relativistic kinetic energy, so we enter the above values into the relativistic kinetic energy calculator and get a result of 4.359E+31 joules, or 10.418260038240916288 zettatons.

Final Results
Strelizia True Apus rams the VIRM planet (speed) = Mach 9229.529
Strelizia True Apus rams the VIRM planet (energy) = 10.418 zettatons

 

[Stocking Anarchy]

2:02

Spoiler

Gridman's fixer beam creates the planet and fires out into space. As far as I know, creating the planet in this way can't really be quantified, but the speed of the beam can be. We'll need to find the radius of the planet.

Spoiler

R = (h/2) + c^2/(8h)
= (115/2) + 1605^2/(8 X 115)
= 2857.52717 pixels

The radius of the Earth is 6378.1km.

1 pixel = 6378.1km/2857.52717 = 2.23203477km
2.23203477km X 734 = 1638.31352km

Lastly for the timeframe.

Spoiler

Timeframe is 1.02 seconds.

T = 1638.31352km/1.02s
= 1606189.73/340.29
= Mach 4720.06151

Final Results
Gridman's Fixer Beam = Mach 4720.062

 

[Stocking Anarchy]

Gridman punches Anti, sending him flying. Anti's kaiju form is 65m tall and weighs 55,000 tons (or 55,000,000kg).

Spoiler

(Relevant text)

Spoiler

(Rough translation)

Height...65m
Weight...65,000 tons

So...let's get calcing!

Spoiler

691 + 149 = 840 pixels
840 pixels = 65m
1 pixel = 65m/840 = 0.0773809524m
0.0773809524m X 166 = 12.8452381m

Spoiler

Timeframe is 5 frames.

T = 1s/24
= 41.6666667ms X 5
= 0.208333333s

0.0773809524m X 1003 = 77.6130953m

T = 77.6130953m/0.208333333s
= 372.542858/340.29
= Mach 1.0947805

With our speed, we can also get our energy.

KE = (0.5)mv^2
= (0.5) X 55,000,000 X 372.542858^2
= 3.81667498e12 joules
= 912.2072131931167 tons of TNT

Final Results
Gridman sends Anti flying (speed) = Mach 1.095
Gridman sends Anti flying (energy) = 912.207 tons of TNT

 

[Stocking Anarchy]

Gridman kicks Gonglee in the face, killing the fuck out of it! Gridman stands 70m tall weighs about 60,000 tons at his tallest (this is before he manifested smaller to allow more processing space; 60,000 tons being 60,000,000kg).

Spoiler

(Relevant text)

Spoiler

(Rough translation)

Height: 50m (adjustable between 70m and 0m)
Weight: 44,000t (adjustable between 0 and 60,0000t)

Spoiler

879 pixels = 70m
1 pixel = 70m/879 = 0.0796359499m
0.0796359499m X 435 = 34.6416382m

Spoiler

Timeframe is 2 frames.

T = 1s/24
= 41.6666667ms X 2
= 83.3333334ms

384 pixels = 34.6416382m
1 pixel = 34.6416382m/384 = 0.0902125995m
0.0902125995m X 543 = 48.9854415m

T = 48.9854415m/83.3333334ms
= 587.825298/340.29
= Mach 1.72742454

Let's get kinetic energy.

KE = (0.5)mv^2
= (0.5) X 60,000,000 X 587.825298^2
= 1.03661574e13 joules
= 2.4775710803059274 kilotons

Final Results
Super Lighting Kick (speed) = Mach 1.727
Super Lightning Kick (energy) = 2.478 kilotons

 

[Stocking Anarchy]

Gridman battles Diriver in the sky. Impressive things happen.

1. Gridman flies upwards


Gridman flies high into the sky. Gridman as of Primal fighter is 50m tall and weighs 44,000 tons (or 44,000,000kg).

Spoiler

(Relevant text)

Spoiler

(Rough translation)

Height...50m (adjustable between 70m and 0m)
Weight...44,000 tons (adjustable between 0 and 60,0000 tons)

With that, let's get to scaling.

Spoiler

5 pixels = 50m
1 pixel = 50m/5 = 10m
10m X 156 = 1560m

Spoiler

Timeframe is 1 second and 14 frames.

T = 1s/24
= 41.6666667ms X 14
= 0.583333334s + 1s
= 1.58333333s

T = 1560m/1.58333333s
= 985.26316/340.29
= Mach 2.89536325

KE = (0.5)mv^2
= (0.5) X 44,000,000 X 985.26316^2
= 2.13563569e13 joules
= 5.1042918021032504 kilotons

2. UFO attack


Diriver's UFO attacks Gridman at incredible speeds, the latter of which evades it. Diriver's UFO form has a length of 42m and a mass of 70 tons.

Spoiler

(Relevant text)
(Relevant text)

Spoiler

(Rough translation)

Height...42m Weight...70 tons
Birthday...3rd of October 2018

Spoiler

568 pixels = 42m
1 pixel = 42m/568 = 0.073943662m
0.073943662m X 394 = 29.1338028m

Spoiler

363 pixels = 29.1338028m
1 pixel = 29.1338028m/363 = 0.0802584099m
0.0802584099m X 610 = 48.95763m

Spoiler

Timeframe is 1 frame.

T = 1s/24
= 41.6666667ms

Given the UFOs main body has disappeared, I think it would be fair to also add in the length of the UFO.

L = 48.95763m + 42m
= 90.95763m

Finally, we can get our speed!

T = 90.95763m/41.6666667ms
= 2182.98312/340.29
= Mach 6.41506691

The UFO is pretty lightweight compared to other kaiju, but it's still worth getting kinetic energy.

KE = (0.5)mv^2
= (0.5) X 70,000 X 2182.98312^2
= 1.66789536e11 joules
= 39.86365583174 tons of TNT

Final Results
Gridman flies into the sky = Mach 2.895
Kinetic energy of Gridman flying = 5.104 kilotons
UFO speed = Mach 6.415
UFO kinetic energy = 39.864 tons of TNT

 

[Stocking Anarchy]

So far we've had some pretty impressive kaiju feats. But time to step up the game with a mountain-sized kaiju; Go'yavec. According the SSSS.Gridman Super Complete Works, Go'yavec stands 399m tall with a mass of 5.6 million tons (or 5,600,000,000kg).

Spoiler

(Relevant text)

Spoiler

(Rough translation)

Height...399m Weight...5,600,000 tons
Birthday...September 2018

1. Gridman throws Go'yavec


Go'yavec tries to crush Gridknight, but Gridman not only stops its claw, but throws it across the city. Obviously, we'll need the distance Go'yavec was thrown. We can see Go'yavec's teeth and mouth (which take up its whole head), so we'll scale from it's mouth.

Spoiler

942 pixels = 399m
1 pixel = 399m/942 = 0.423566879m
0.423566879m X 69 = 29.2261147m
0.423566879m X 48 = 20.3312102m

Spoiler

48 pixels = 20.3312102m
1 pixel = 20.3312102m/48 = 0.423566879m
0.423566879m X 154 = 65.2292994m

Now, to find the distance Go'yavec was thrown.

Spoiler

object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))

= 2*atan(228/(1437/tan(70/2)))
= 0.150072274 rad
= 8.59850792215220672 degrees

Entering those values into the angscaler and we can determine that Go'yavec was thrown a distance of 433.84m. Now for the timeframe.

Spoiler

Timeframe is 9 frames.

T = 1s/24
= 41.6666667ms X 9
= 0.375s

T = 433.84m/0.375s
= 1156.90667m/s

At long last, let's get our kinetic energy.

KE = (0.5)mv^2
= (0.5) X 5,600,000,000 X 1156.90667^2
= 3.74761252e15 joules
= 895.7008891013384755 kilotons

2. Last charge of the kaiju


The kaiju rush at the heroes, including Go'yavec, running quite rapidly.

Spoiler

56 pixels = 20.3312102m
1 pixel = 20.3312102m/56 = 0.363057325m
0.363057325m X 4 = 1.4522293m

Spoiler

Timeframe is 11 frames.

T = 1s/24
= 41.6666667ms X 11
= 0.458333334s

0.363057325m X 324 = 117.630573m
117.630573m - 1.4522293m = 116.178344m

T = 116.178344m/0.458333334s
= 253.480023m/s

KE = (0.5)mv^2
= (0.5) X 5,600,000,000 X 253.480023^2
= 1.79905942e14 joules
= 42.9985521032504749 kilotons

Final Results
Gridman throws Go'yavac across the city = 895.701 kilotons
Go'yovac charges (speed) = 253.480m/s
Go'yovac charges (energy) = 42.999 kilotons

It's also worth mentioning that Alexis Kerub and Zegga are both more powerful than Go'yovac.

 

[Stocking Anarchy]

Dyna Dragon carries Shalbandes up through the clouds and parts them greatly. Dyna Dragon is 50m tall and weighs 240,000 tons.

Spoiler

(Relevant text)

Spoiler

Height: 50m
Weight: 240,000 tons

For this calc we'll go with a low end of the width of the metal part of the wing and a high end of the energy part of the wing.

Spoiler

971 pixels = 50m
1 pixel = 50m/971 = 0.0514933059m
0.0514933059m X 981 = 50.5149331m
0.0514933059m X 1192 = 61.3800206m

Spoiler

(Low end)
95 pixels = 50.5149331m
1 pixel = 50.5149331m/95 = 0.531736138m

(High end)
95 pixels = 61.3800206m
1 pixel = 61.3800206m/95 = 0.64610548m

Spoiler

(Low end)
0.531736138m X 2086 = 1109.20158m

(High end)
0.64610548m X 2086 = 1347.77603m

That's our radius. For the type of cloud for our thickness, we'll use stratonimbus, which have a thickness of 200m to 500m. Volume as a cylinder.

(Low end)

V = πr^2h
= π X 1109.20158^2 X 200
= 773037972m^3

(High end)

V = πr^2h
= π X 1347.77603^2 X 200
= 1.14134075e9m^3

Weight of air is is 1.003kg per m^3.

(Low end)

M = 773037972 X 1.003kg
= 775357086kg

(High end)

M = 1.14134075e9 X 1.003kg
= 1.14476477e9kg

What's the timeframe in which the clouds were parted?

Spoiler

Timeframe is 11 frames.

T = 1s/24
= 41.6666667ms X 11
= 0.458333334s

Let's find out our parting speed.

(Low end)

T = 1109.20158m/0.458333334s
= 2420.07617m/s

(High end)

T = 1347.77603m/0.458333334s
= 2940.60224m/s

Which with thus, we find our kinetic energy.

(Low end)
KE = (0.5)mv^2
= (0.5) X 775357086 X 2420.07617^2
= 2.27054354e15 joules
= 542.6729302103250347 kilotons

(High end)
KE = (0.5)mv^2
= (0.5) X 1.14476477e9 X 2940.60224^2
= 4.94947149e15 joules
= 1.182952076959846943 megatons

Given I like to get kinetic energy, why not get the kinetic energy of this? Dyna Dragon weighs 240,000 tons in the original series (or 240,000,000kg). What's our timeframe?

Spoiler

1 second and 3 frames.

T = 41.6666667ms X 3
= 0.125s + 1s
= 1.125s

Once again using the floating height of stratonimbus clouds, we have a distance of 2000m.

T = 2000m/1.125s
= 1777.77778/340.29
= Mach 5.22430215

Of course, whenever I come across something moving at great speeds I go for kinetic energy where I can. Dyna Dragon has a mass of 240,000 tons, or 240,000,000kg. Shalbandes has a mass of 76,000 tons, or 76,000,000kg.

Spoiler

(Relevant text)

Spoiler

Height: 73m
Weight: 76,000 tons
Birthday: May 27, 2020

M = 240,000,000kg + 76,000,000kg
= 316000000kg

KE = (0.5)mv^2
= (0.5) X 316000000 X 1777.77778^2
= 4.99358026e14 joules
= 119.349432600382414 kilotons

Final Results
Dyna Dragon parts clouds (low end) = 542.673 kilotons
Dyna Dragon parts clouds (high end) = 1.183 megatons
Dyna Dragon carries Shalbandes into the sky (speed) = Mach 5.224
Dyna Dragon carries Shalbandes into the sky (energy) = 119.349 kilotons

 

[Stocking Anarchy]

Dynazenon carries an enemy kaiju up into space in seconds. How far above the Earth are they? We'll need to find the radius of the Earth.

Spoiler

R = (h/2) + c^2/(8h)
= (115/2) + 2827^2/(8 X 115)
= 8744.37935 pixels

The above is for the radius, so for the diameter of the Earth (12756km) we'll double the number of pixels, to get 17488.7587 pixels.

object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))

= 2*atan(17488.7587/(1619/tan(70/2)))
= 2.75569468 rad
= 157.88967479104562 degrees

Put that through this angscaler calculator and we get a distance of 1246.1km. How quickly did Dynazenon fly that distance?

Spoiler

13 seconds and 3 frames.

T = 1s/24
= 41.6666667ms
= 0.125s + 13s
= 13.125s

T = 1246.1km/13.125s
= 94940.9524/340.29
= Mach 279.000125

A big heavy thing moving at high velocities? What's stopping us from getting kinetic energy? Nothing I say! Dynazenon weighs 240,000 tons (or 240,000,000kg).

Spoiler

(Relevant text)

Spoiler

Height: 50m
Weight: 240,000 tons

Burnaddon weighs 72,000 tons, or 72,000,000kg.

Spoiler

(Relevant text)

Spoiler

Height: 74m
Weight: 72,000 tons
Birthday: May 3, 2020

M = 240,000,000kg + 72,000,000kg
= 312000000kg

KE = (0.5)mv^2
= (0.5) X 312000000 X 94940.9524^2
= 1.40615037e18 joules
= 336.07800430210323839 megatons

Final Results
Dynazenon flies into space (speed) = Mach 279
Dynazenon flies into space (energy) = 336.078 megatons

 

[Stocking Anarchy]

Spoiler

With the help of his X-Wing, Karre cuts a Star Destroying in half, and Am is able to halt him before he goes into hyperspace. First up, let's get the width of the area melted. Using the average height of a man (which globally is 171cm, or 1.71m) for Karre until we find something else.

Spoiler

374 pixels = 1.71m
1 pixel = 1.71m/374 = 0.00457219251m
0.00457219251m X 51 = 0.233181818m

Spoiler

96 pixels = 0.233181818m
1 pixel = 0.233181818m/96 = 0.00242897727m
0.00242897727m X 104 = 0.252613636m

Next, let's find the dimensions of the Gemini-Star Destroyer. An X-wing is 11.76m across.

Spoiler

303 pixels = 11.76m
1 pixel = 11.76m/303 = 0.0388118812m
0.0388118812m X 1322 = 51.3093069m

Spoiler

29 pixels = 51.3093069m
1 pixel = 51.3093069m/29 = 1.76928644m
1.76928644m X 78 = 138.004342m
1.76928644m X 44 =77.8486034 meters
1.76928644m X 241 = 426.398032m
1.76928644m X 801 = 1417.19844m
1.76928644m X 786 = 1390.65914m
1.76928644m X 765 = 1353.50413m
1.76928644m X 790 = 1397.73629m

With that in our hands, let's now find the volume of the section melted. We can see the exact point at which Am managed to block it...

Spoiler

...so we'll scale up to there.

Spoiler

27 pixels = 138.004342m
1 pixel = 138.004342m/27 = 5.11127193m
5.11127193m X 979 = 5003.93522m (5.00393522km)
5.11127193m X 4 = 20.4450877m
5.11127193m X 707 = 3613.66925m
5.11127193m X 41 = 209.562149m
5.11127193m X 39 = 199.339605m
5.11127193m X 33 = 168.671974m
5.11127193m X 13 = 66.4465351m
5.11127193m X 128 = 654.242807m
5.11127193m X 410 = 2095.62149m
5.11127193m X 34 = 173.783246m
5.11127193m X 41 = 209.562149m
5.11127193m X 524 = 2678.30649m
5.11127193m X 19 = 97.1141667m
5.11127193m X 249 = 1272.70671m
2095.62149m - 1272.70671m - 209.562149m = 613.352631m

Firstly, we'll go for the total energy to melt the segment of the Star Destroyer cut. Volume of all the sections as rectangles (with a width and height of 0.252613636m and 20.4450877m respectively).

V = lhw
= 3613.66925 X 20.4450877 X 0.252613636
= 18663.5463m^3

V = lhw
= 66.4465351 X 20.4450877 X 0.252613636
= 343.176948m^3

V = lhw
= 654.242807 X 20.4450877 X 0.252613636
= 3378.97302m^3

V = lhw
= 613.352631 X 20.4450877 X 0.252613636
= 3167.7872m^3

We'll add the volumes together, then convert it to cm^3.

V = 18663.5463 + 343.176948 + 3378.97302 + 3167.7872
= 25553.4835m^3
= 25553483500cm^3

We'll go with a low end of aluminum (2836.11219 joules/cm^3) and a high end of steel (7309.87 joules/cm^3).

(Low end)
E = 2836.11219 X 25553483500
= 7.24725461e13 joules
= 17.321354230401528 kilotons

(High end)
E = 7309.87 X 25553483500
= 1.86792642e14 joules
= 44.6445129063097497 kilotons

With that all done, let's find the energy per second.

Spoiler

Timeframe is 10 seconds and 8 frames.

T = 1s/24
= 41.6666667ms X 8
= 0.333333334s + 10s
= 10.3333333s

(Low end)
E = 7.24725461e13/10.3333333
= 7.01347223e12 joules
= 1.676260093212237 kilotons

(High end)
E = 1.86792642e14/10.3333333
= 1.80767073e13 joules
= 4.3204367351816444 kilotons

That's also the minimum energy for Am stopping Karre's attack. Karre wins out though when R-DUO kicks into hyperdrive, and splits the Star Destroyer in half proper. Let's find the kinetic energy of the split. We'll calculate the armour larger two parts of the armour as two triangular prisms (it's not exact, but given the shape of the Star Destroyer and not taking the bridge into account, it'd be a low end in anycase).

A = hb/2
= 5003.93522 X 1417.19844/2
= 3545784.59m^2

V = bh
= 3545784.59 X 20.4450877
= 72493876.9 X 2
= 144987754m^3

Keeping consistent with what we've been working with above, we'll have a low end of aluminium (2600kg/m^3) and a high end of steel (7850kg/m^3) for our mass (both values here).

(Low end)

M = 144987754 X 2600kg
= 376968160400kg

(High end)

M = 144987754 X 7850kg
= 1138153868900kg

Now for the middle, we'll go with two triangular pyramids and a triangular prism.

A = hb/2
= 1353.50413 X 426.398032/2
= 288565.749m^2

V = 1/3hb
= 1/3 X 288565.749 X 5003.93522
= 481321438 X 2
= 962642876m^3

A = hb/2
= 5003.93522 X 1353.50413/2
= 3386423.49m^2

V = hb
= 3386423.49 + 97.1141667
= 3386520.6m^3

V = 962642876 + 3386520.6
= 966029397m^3

As per usual with vehicle and machine mass calcs, I will be using mass of the light ship mass of container vessel 2700TEU, that being 102.56kg/m^3 (this is likely a huge low end, but it's the best I've got).

M = 966029397 X 102
= 98534998494kg

Adding those to our above values...

(Low end)

M = 376968160400kg + 98534998494kg
= 475503158894kg

(High end)

M = 1138153868900kg + 98534998494kg
= 1236688867394kg

Our penultimate directive is to find the speed.

Spoiler

Timeframe is 2 seconds and 12 frames.

T = 41.6666667ms X 12
= 0.5s + 2s
= 2.5s

407 pixels = 1397.73629m
1 pixel = 1397.73629m/407 = 3.4342415m
3.4342415m X 122 = 418.977463m

T = 418.977463m/2.5s
= 167.590985m/s

At last we shall have our energy!

(Low end)

KE = (0.5)mv^2
= (0.5) X 475503158894 X 167.590985^2
= 6.67766638e15 joules
= 1.596000568833652045 megatons

(High end)

KE = (0.5)mv^2
= (0.5) X 1236688867394 X 167.590985^2
= 1.73672783e16 joules
= 4.1508791347992355369 megatons

Final Results
Gemini-class Star Destroyer length = 5.004km
Total energy of Karre slicing through Star Destroyer (low end) = >17.321 kilotons
Total energy of Karre slicing through Star Destroyer (high end) = >44.645 kilotons
Energy of Karre slicing Star Destroyer per second (low end) = >1.676 kilotons
Energy of Karre slicing Star Destroyer per second (high end) = >4.320 kilotons
Karre splits the Gemini Star Destroyer in half (low end) = >1.596 megatons
Karre splits the Gemini Star Destroyer in half (high end) = >4.151 megatons

This also involves a lot of low ends for the mass and I couldn't be bothered doing the bridge, so ultimately the final result is going to be even higher than that. It's also worth noting that about a quarter of the total mass of the Gemini Star Destroyer weighs several hundred million tons.

 

[Stocking Anarchy]

Karre's X-wing crashes into Tatooine at incredible speeds. Although it's damaged, it manages to maintain its general shape, and isn't instantly vaporized. This is important to remember as earlier Am tears the kyber-crystal right out of Karre's X-wing. The diameter of Tatooine is 10,465km.

Spoiler

Timeframe is 1 second and 2 frames.

T = 1s/24
= 41.6666667ms X 2
= 83.3333334ms + 1s
= 1.08333333s


395 pixels = 10,465km
1 pixel = 10465km/395 = 26.4936709km
26.4936709km X 258 = 6835.36709km

T = 6835.36709km/1.08333333s
= 6309569.64/340.29
= Mach 18541.7427

Now we have the speed, let's find the kinetic energy. X-wings weigh 10 metric tons (or 10,000kg).

KE = (0.5)mv^2
= (0.5) X 10,000 X 6309569.64^2
= 1.99053345e17 joules
= 47.574891252390060004 megatons

That's not all though! Karre himself is outside the X-wing cockpit. Meaning he'd have to withstand that kinetic energy too. The average global weight of a man is 136.7 pounds, or 62.006077kg.

KE = (0.5)mv^2
= (0.5) X 62.006077 X 6309569.64^2
= 1.23425171e15 joules
= 294.9932385277246567 kilotons

Final Results
Karre's X-wing crashes into Tatooine (speed) = Mach 18541.7427
Karre's X-wing crashes into Tatooine (energy) = 47.575 megatons
Karre's kinetic energy = 294.993 kilotons

 

[Stocking Anarchy]

Spoiler

B-20N shows Am a simulation of the Gemini-class Star Destroyer blowing up a planet (possibly even a star system), which draws its energy from the kyber-crystal at its core, which is also the power of the Twin's dark side suits. Not only is it confirmed that the Gemini Star Destroyer can destroy a planet, but it's more powerful than the Death Star (and that it's being powered by the Twins).

https://www.starwars.com/news/inside-star-wars-visions-meet-the-ships-and-vehicles

The Twin Star Destroyer, “The Twins”

When you first see the Twin Star Destroyer, it emerges from the shadows like the beginning of a new cinematic Star Wars adventure. But there’s something quite different about the shape of this craft. “The Twin Star Destroyer is such a playful idea,” says Rimes. “With a wink and nod, director Hiroyuki Imaishi slowly reveals a Star Destroyer coming out of shadow. But wait — the light expands revealing a second conjoined Destroyer!”

A clever visual riff on the twin siblings at the core of this short, the expansive design fits perfectly into the heightened and sprawling world in the tale.

To mirror the occupants, each Star Destroyer contains its own throne room, one for Am and one for Karre. And in the middle: a weapon capable of mass destruction. “Holding them together is a massive cannon,” says Rimes. “When powered by the twins, it can deliver planet-eradicating blasts that would put the Death Star to shame.”

So I think that justifies looking at the simulation for reference. The diameter of the Earth is 12742km.

Spoiler

251 pixels = 12742km
1 pixels = 12742km/251 = 50.7649402km

Spoiler

Timeframe is 3 seconds and 10 frames.

T = 1s/24
= 41.6666667ms X 10
= 0.416666667s + 3s
= 3.41666667s

50.7649402km X 318 = 16143.251km

T = 16143.251km/3.41666667s
= 4724853.95m/s

The mass of the Earth is 6.0e24kg.

KE = (0.5)mv^2
= (0.5) X 6.0e24 X 4724853.95^2
= 6.69727345e37 joules
= 16.006867710325226 ninatons

Final Results
Hypothetical firepower of the Gemini-class Star Destroyer = 16.007 ninatons

Given Karre and Am are a power source for it, their power can also be figured out from that. Unfortunately though, we don't know how long it takes to charge, or the connection between the twins and the kyber-crystal as of yet.

 

[Stocking Anarchy]

Lio (in his black form) evaporates the Frozen Lake just by coming in contact with it. The average height of an American man is 5 feet 9 inches, or 1.7526m.

Spoiler

13 pixels = 1.7526m
1 pixel = 1.7526m/13 = 0.134815385m
0.134815385m X 2880 = 388.268309m
388.268309m/2 = 194.134154m

Next up is the depth. Due to the cracks that appear from the melting, we can ascertain the ice goes all the way down.

Spoiler

2829 pixels = 388.268309m
1 pixel = 388.268309m/2829 = 0.137245779m
0.137245779m X 385 = 52.8396249m

The scaling's not entirely perfect, but that's the best I could get with the shots available, and keep in mind that there's also Deus Promith's lab at the bottom. Volume as a spherical cap.

V = π/3H^2(3R = H)
= π/3 X 52.8396249^2(3 X 194.134154 - 52.8396249)
= 1548337.28m^3

Ice weighs 919kg/m^3.

M = 1548337.28 X 919
= 1.42292196e9kg

It takes 333.55 kilojoules to melt 1kg of ice.

E = 1.42292196e9 X 333.55
= 474615619758 kilojoules
= 4.7461562e14 joules

But the ice doesn't just melt; it evaporates, so let's also add the energy to vaporize the water (more information on which can be found here).

E = 1.42292196e9 X 2.26 X 10^6
= 3.21580363e15

Finally, to add the two together to get our final results.

E = 4.7461562e14 + 3.21580363e15
= 3.69041925e15 joules
= 882.0313695028680741 kilotons

Final Results
Lio melts the frozen lake = 882.031 kilotons

 

[Stocking Anarchy]

Lio Fotia gets mad. The rest is history. This is gonna take a lot of scaling, so hold on...

1. Lio's volcanic eruption
Earlier in the film, we get a shot of Lio near the volcano with the face on it. Given Promare is set in an alternate America, we'll go with the average height of an American man, that being 5 feet 9 inches, or 1.7526m.

Spoiler

15 + 12 = 27
27 pixels = 1.7526m
1 pixel = 1.7526m/27 = 0.0649111111m
0.0649111111m X 1346 = 87.3703555m
0.0649111111m X 68 = 4.41395555m

The volcano does seem to change in shape a bit with the animation style, but given that's the best we have to go with, let's go with it.

Spoiler

175 pixels = 87.3703555m
1 pixel = 87.3703555m/175 = 0.499259174m
0.499259174m X 2880 = 1437.86642m
1437.86642m/2 =
0.499259174m X 1691 = 844.247263m
844.247263m/2 = 422.123631m
0.499259174m X 442 = 220.672555m
220.672555m/2 = 110.336277m
0.499259174m X 803 = 400.905117m
0.499259174m X 1556 = 776.847275m

object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))

= 2*atan(175/(1556/tan(70/2)))
= 0.106477149 rad
= 6.10069125230074683 degrees

Once again refering to our old friend the angscaler, we can determine that the volcano peak is 819.78m.

Spoiler

0.499259174m X 1182 = 590.124344m
590.124344m/2 = 295.062172m
0.499259174m X 2659 = 1327.53014m
1327.53014m/2 = 663.76507m

Volume as an ellipsoid.

V = 4/3πabc
= 4/3 X π X 295.062172 X 663.76507 X 663.76507
= 544541437m^3

Weight of lava/magma (or the mantle) is 3300kg/m^3.

Spoiler

The timeframe is 0.57 seconds. Next for the speed and kinetic energy.

T = 663.76507m/0.57s
= 1164.50012m/s

KE = (0.5)mv^2
= (0.5) X 1796986742100 X 1164.50012^2
= 1.2184114e18 joules

Next to do the lava eruption that follows and covers everything. First, to take away the distance to the explosion.

L = 819.78m - 663.76507m
= 156.01493m

Spoiler

Timeframe is 0.45 seconds.

T = 156.01493m/0.45s
= 346.699844m/s

KE = (0.5)mv^2
= (0.5) X 1796986742100 X 346.699844^2
= 1.07999606e17 joules

Finally, let's add them all together to get our final result.

E = 1.2184114e18 + 1.07999606e17
= 1.32641101e18 joules
= 317.01983986615681488 megatons

2. Lio swims to Promepolis

Spoiler

Lio's Burnish Dragon swims through the ground to Promepolis, and gets noticably closer. We can scale the distance travelled from the Foresight Foundation tower. Once again using the average American height for Galo (1.7526m).

Spoiler

232 pixels = 1.7526m
1 pixel = 1.7526m/232 = 0.00755431034m
0.00755431034m X 1440 = 10.8782069m

Spoiler

132 pixels = 10.8782069m
1 pixel = 10.8782069m/132 = 0.0824106583m
0.0824106583m X 1042 = 85.8719059m

Spoiler

173 pixels = 85.8719059m
1 pixel = 85.8719059m/173 = 0.496369398m
0.496369398m X 409 = 203.015084m

Jeez that's a ridiculously huge tower. Anyway, onto scaling.

Spoiler

object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))

= 2*atan(9/(1617/tan(70/2)))
= 0.00527436314 rad
= 0.30219874754211817347 degrees

Promepolis is 38491m away.

Spoiler

Timeframe is 2 seconds.

object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))

= 2*atan(8/(1617/tan(70/2)))
= 0.00468832507 rad
= 0.26862123949704258541 degrees

The Foresight Foundation tower is now 43302m away.

D = 43302m - 38491m
= 4811m/340.29
= Mach 14.1379412

Final Results
Lio's volcanic eruption = >317.0198 megatons
Burnish Dragon swims towards Promepolis = Mach 14.138

 

[Stocking Anarchy]

From Lio-Hen, one of the two prequels to Promare.


Vulcan shoots Lio with an ice rocket launcher, but Lio just melts his way out, without even wearing his Burnish Armour either. Once again using the height of 5 feet 9 inches (or 1.7526m) for Lio.

Spoiler

1347 pixels = 1.7526m
1 pixel = 1.7526m/1347 = 0.00130111359m
0.00130111359m X 201 pixels = 0.261523832m

Spoiler

66 pixels = 0.261523832m
1 pixel = 0.261523832m/66 = 0.0039624823m
0.0039624823m X 286 = 1.13326994m
0.0039624823m X 1075 = 4.25966847m
4.25966847m/2 = 2.12983424m

Said ice burst is also thick enough to contain Lio's bike from front to back.

Spoiler

58 pixels = 1.13326994m
1 pixel = 1.13326994m/58 = 0.0195391369m
0.0195391369m X 2126 = 41.540205m
41.540205m/2 = 20.7701025m
0.0195391369m X 1235 = 24.1308341m
24.1308341m/2 = 12.0654171m

Volume as an ellipsoid.

V = 4/3πabc
= 4/3 X π X 12.0654171 X 20.7701025 X 2.12983424
= 2235.70961m^3

Once again using the mass of solid air, as it's too hard and dense to be the 1.003kg's of air in it's gaseous form. Ice has a density of 919kg/m^3.

M = 2235.70961 X 919
= 2054617.13kg

Keep in mind that this isn't just ordinary ice, but ice that can freeze Burnish Flames (somehow).

Given said fires can evaporate a frozen lake and worse, they should be at least 100°C. Specific heat of air at this temperature is 1.005 kilojoules.

E = 2054617.13 X 1.005 X 100
= 206489022 kilojoules
= 206489022000 joules

And of course we'll add the heat fusion of oxygen of 13800 joules/kg.

E = 9311452.37 X 13800
= 128498042706 joules

E = 206489022000 + 128498042706
= 334987064706 joules
= 80.0638299966539 tons of TNT

Lio then melts his way out, evaporating the ice.

Spoiler

279 pixels = 1.13326994m
1 pixel = 1.13326994m/279 = 0.00406189943m
0.00406189943m X 1431 = 5.81257808m

Volume of the area melted as an equilateral triangular prism.

V = √3/4w^2h
= √3/4 X 5.81257808^2 X 4.25966847
= 62.3180758m^3

M = 62.3180758 X 919
= 57270.3117kg

The heat fusion of ice is 3.33 X 10^5 joules/kg (or 333000 joules/kg), as well as the the heat of vaporization, that being 2.26 X 10^6 joules/kg (or 2260000kg).

E = 57270.3117 X 333000
= 1.90710138e10 joules

E = 57270.3117 X 2260000
= 129430904442 joules

The specific heat of water is 4.18 joules/kg.

E = 57270.3117 X 4.18 X 100
= 23938990.3 joules

E = 1.90710138e10 + 129430904442 + 23938990.3
= 1.48525857e11 joules
= 35.4985317877629 tons of TNT

Final Results
Vulcan freezes Lio = 80.064 tons of TNT
Lio escapes ice = 35.499 tons of TNT

 

[Stocking Anarchy]

Given this will be relevant in future calcs, it's time to calc the size of the Promare mechs.

1. Deus Ex Machina/Lio de Galon height
Until I become aware of Lio's official height, I'll use the height I used in the other calcs, that being 5 feet 9 inches, or 1.7526m.

Spoiler

1347 pixels = 1.7526m
1 pixel = 1.7526m/1347 = 0.00130111359m
0.00130111359m X 201 pixels = 0.261523832m

Spoiler

139 pixels = 0.261523832m
1 pixel = 0.261523832m/139 = 0.00188146642m
0.00188146642m X 1704 = 3.20601878m

Spoiler

95 pixels = 3.20601878m
1 pixel = 3.20601878m/95 = 0.0337475661m
0.0337475661m X 1483 = 50.0476405m

2. Krazor X height
Krazor X is even bigger than Lio de Galon, and we can see this in their fights, when both of them dwarf cars they send flying up. The average length of a compact sedan is 177.2 inches, or 4.50088m.

Spoiler

50 pixels = 4.50088m
1 pixel = 4.50088m/50 = 0.0900176m
461 + 319 + 186 + 281 = 1247 pixels
0.0900176m X 1247 = 112.251947m
0.0900176m X 213 = 19.1737488m

Spoiler

122 pixels = 19.1737488m
1 pixel = 19.1737488m/122 = 0.157161875m
0.157161875m X 233 = 36.6187169m
36.6187169m + 112.251947m = 148.870664m

Final Results
Deus Ex Machina/Lio de Galon height = 50.048m
Krazor X height (main body) = 112.252m
Krazor X height (total) = 148.871m

 

[Stocking Anarchy]

Given the size of the mechas in this movie, it comes at not surprise that they'd be really fast.

1. Krazor X punch
1:11

Lio de Galo catches Krazor X's punch. To note how impressive this is, I'll point out the timeframe;

Spoiler

The punch happens in the span of 1 frame. Take notice also Lio de Galo reacts to and catches this punch in said frame.

T = 1s/24
= 41.6666667ms

Given Krazor X is over 148m tall, this is going to be super fast. Reminder that the average length of a compact sedan is 177.2 inches, or 4.50088m.

Spoiler

50 pixels = 4.50088m
1 pixel = 4.50088m/50 = 0.0900176m
0.0900176m X 925 = 83.26628m

T = 83.26628m/41.6666667ms
= 1998.39072/340.29
= Mach 5.87261077

It would also be possible to get kinetic energy for this, but given that would take a lot of fiddling around...maybe another time.

2. Lio de Galon's kick
1:43

Krazor X punches Lio de Galon across the city, but then Lio de Galon leaps back in the span of about a second and kicks Krazor X in the face. Krazor X's shoulder blade is 36.6187169m tall.

Spoiler

object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))

= 2*atan(45/(1664/tan(70/2)))
= 0.0256255957 rad
= 1.468238481122232653 degrees

Entering the values of size and degrees into the angscaler, we get a distance of 1428.9m to Krazor X. Now for the timeframe.

Spoiler

Timeframe is 1.02 seconds.

T = 1428.9m/1.02s
= 1400.88235/340.29
= Mach 4.11673088

Final Results
Krazor X's punch = Mach 5.873
Lio de Galon's kick = Mach 4.117