so basically admirals are the top tiers of op verse who can even somehow tangle WB but without being exactly equal to his Allmighty quake, thus being forever chinjao++++++
till now
akainu was able to ignite a WB quake with his helldog
Said quake exploded on both him and WB
http://2.bp.blogspot.com/-SiBuHyWkzh4/VmY6lvNq4TI/AAAAAAAHBSE/cjo8T6vhQCQ/s16000/0568-002.jpg
WB survived the explosion with little injury and so did Akainu
http://2.bp.blogspot.com/-xvjKjbnVzcA/VmY6mN058XI/AAAAAAAHBS4/k4PdC4fN-nA/s16000/0568-003.jpg
but how much of the quake explosion did akainu who was a couple meters away tank ?
[LINKHL]34177[/LINKHL]
admirals are all around the same height
doflamingo is 3.05 m (165.85px)
kuzan is 138px (2.53783539 m)
now i need wb size
[LINKHL]34178[/LINKHL]
teach is 3.44 m and 215px
wb is 314px (5.024m)
his waist and head makes for 117px (1.872m)
now let's go back to akainu
[LINKHL]34179[/LINKHL]
panel height is 555px
panel lenght is 1056
obviously pov is obvious
2*atan(tan(70/2deg))*(1056/555) 133.189189 deg for pov
wb waist + head is 399px
2*atan(399/(555/tan(133.189189/2 deg))) =117.896927 deg
2*atan(399/(1056/tan(133.189189/2 deg))) 82.2362523 deg
which gives me around 1.0723 m till beard
now it is akainu turn
he is around 121 px tall and 2.53783539 meters
2*atan(121/(1056/tan(133.189189/2 deg))) 53.4669206 deg
4.7976 meters
making the total distance till akainu
4.7976-1.0723=3.7253 m
well this actually sounds pretty good
the surface area of a sphere with 3.7253 meters as its radius is 174 m^2
akainu surface area will be gooten via cubic law
Akainu area=(akainu height/human height)^2 x human area
Aa=(2.53783539/1.7)^2 x 1.9
Aa=4.23431 m^2
however only half of his body tanks this as he is still visible on the next panel instead of completely engulfed by the explosion
so the ratio of damage becomes 174/(4.23431/2)=82.1857634
thats how much weaker wb quake got before being meaningless against akainu
wb quake is worthy 1.17 petatons
1170 teratons/82.1857634=14.2360422 teratons
thats how strong and durable akainu can be normally
till now
akainu was able to ignite a WB quake with his helldog
Said quake exploded on both him and WB
http://2.bp.blogspot.com/-SiBuHyWkzh4/VmY6lvNq4TI/AAAAAAAHBSE/cjo8T6vhQCQ/s16000/0568-002.jpg
WB survived the explosion with little injury and so did Akainu
http://2.bp.blogspot.com/-xvjKjbnVzcA/VmY6mN058XI/AAAAAAAHBS4/k4PdC4fN-nA/s16000/0568-003.jpg
but how much of the quake explosion did akainu who was a couple meters away tank ?
[LINKHL]34177[/LINKHL]
admirals are all around the same height
doflamingo is 3.05 m (165.85px)
kuzan is 138px (2.53783539 m)
now i need wb size
[LINKHL]34178[/LINKHL]
teach is 3.44 m and 215px
wb is 314px (5.024m)
his waist and head makes for 117px (1.872m)
now let's go back to akainu
[LINKHL]34179[/LINKHL]
panel height is 555px
panel lenght is 1056
obviously pov is obvious
2*atan(tan(70/2deg))*(1056/555) 133.189189 deg for pov
wb waist + head is 399px
2*atan(399/(555/tan(133.189189/2 deg))) =117.896927 deg
2*atan(399/(1056/tan(133.189189/2 deg))) 82.2362523 deg
which gives me around 1.0723 m till beard
now it is akainu turn
he is around 121 px tall and 2.53783539 meters
2*atan(121/(1056/tan(133.189189/2 deg))) 53.4669206 deg
4.7976 meters
making the total distance till akainu
4.7976-1.0723=3.7253 m
well this actually sounds pretty good
the surface area of a sphere with 3.7253 meters as its radius is 174 m^2
akainu surface area will be gooten via cubic law
Akainu area=(akainu height/human height)^2 x human area
Aa=(2.53783539/1.7)^2 x 1.9
Aa=4.23431 m^2
however only half of his body tanks this as he is still visible on the next panel instead of completely engulfed by the explosion
so the ratio of damage becomes 174/(4.23431/2)=82.1857634
thats how much weaker wb quake got before being meaningless against akainu
wb quake is worthy 1.17 petatons
1170 teratons/82.1857634=14.2360422 teratons
thats how strong and durable akainu can be normally
