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Calc Dat new generation part 3 (Boku no Hero Academia)

Calculations
well, this was bounded to happen
this time i will go through some trickier feats.
Kacchan explodes a building
that's about it
i'll be calcing the energy needed to bust that part of the building

volume of the building
the first part is pretty straightforward
Td6hfPK.jpg

the destruction is sectioned in 2 rectangular prisms
but how exactly big is this ?
i'll scalle here the building windows to compare
deku is 77.125px
the window is 74px
deku's heigth is 166 cm
making the window 159.274 cm
on the other picture we can see that the smaller rectangle is has a 42x12px surface while the bigger one has a 78x144px.
meanwhile the window is 42px
making these rectangles
which means the area of these rectangles are:
Smaller Rectangle Area=1.59274 x 0.455 m
SRA=0.7246967 m^2
Bigger Rectangle Area=2,95794 x 5.46082 m
BRA=16.1527779108 m^2
Total Area=0.7246967 + 16.1527779108
TA=16.8774746108 m^2
now for the deepth it will be somewhat trickier
Deepth
as you can see here the explosion messed up and destroyed the surroundings of their fight
which means just scalling a ramdom boulder thickness would be kind of unfair.
i8QSHcy.jpg

instead, i'll do an angscalling here attempting to get the deepth of the affected area
according to the wiki deku and kacchan's heigth are 166 and 172 cm respectively
by human body proportions the head equals to 7.5 of ones body.
making their heads 22.13 and 22.93 cm respectively
panel heigth is 367px
deku's head is 18px
kacchan's is 37px
to get the distance between their heads i'll individually angscalle each one from the viewer point and the deduct the value.
Kacchan distance from the viewer=2 * atan(37 / (367/ tan(70 / 2)))=5.46974186 degrees
inputting the angle and his head size on this calculator i get 2.4 meters for kacchan
Deku's distance from the viewer=2 * atan(18 / (367/ tan(70 / 2)))=2.66249902 degrees
doing the same i did with kacchan i get 4.7614 meters for deku
Deepth=4.7614-2.4
D=2.3614 meters
Deepth= 2.3614 meters
now that i have all the variables i just need to multiply the area by the deepth and get 10% of it for a nice lowballing
Volume= 16.8774746108 x 2.3614 x 0.1
Volume=3.98544685 m^3
Volume of the destroyed part=3.98544685 m^3
Energy
it is concrete and it is being violently wiped out so i'll use violent fragmentation of concrete(42 J/cc)
Energy=Violent Fragmentation of Concrete *Volume
E=42000000*3.98544685
E=167388768 joules
or
0.0400068756 tons of tnt
solid small building level bakugou :meh

The Rival Clash
deku and bakudou clashes shaterring the inniards of the building they are in
quite straight forward really
Holes volume
i'll be assuming all the 6 holes that can be seen here have equal volumes
bakudou head is 22.93cm tall
it is 42px on this panel
the hole deepth is 31 px
making the hole deepth 16.92 cm
the base of the cylinder can be seem here
according to the wiki ochako height is 156 cm
she is 89.31 px here
the cylinder length is 527
the cylinder widety is 181
which means
CL=9.20524017467m
CW=3.1615720524m
CD=0.1692m
plugging these values on the elliptical cylinder volume calculator we get.
volume of a single hole=3.867483309422377 m^3
multiplying by 6 holes we get
Volume of all the holes=23.2048998565 m^3
Energy
this clash just fragmentated the concrete so this is what i will be using (1.4j/cc)
Energy=Fragmentation of concrete Value* Volume
E=23.2048998565 *1400000
E=32486859.7991 joules
or
0.00776454584 tons of tnt
which is marginally small building level and even less as the value gest halved between them. :catroll
next time i'll probably try out shouto's freezing feat if i find a way to quantify it

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Zed
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