i'm getting through some pretty amazing feats from a random arc and from the urashima arc
|Every hair commercial ever
Man Ages better than woman i guess
|Every hair commercial ever
Some ball alien covers a whole planet in an instant
now now funnily enough this planet actually isn't a proper planet
it was a random planet with no living properties that said alien ball terraformed
of course the alien ball is not to scalle on the above panel given it is way smaller than the planet
but we can still scalle based on it
window 2 px (1.5m)
chord height is 58 px
chord diameter is 325 px
ER=(58 /2)+325^2/(8 x 58 )
SR=256.64 px
SD=513.28 px (384.96 meters)
given we can't see the sphere the diameter of the explosion is at least as big
explosion diameter is 23.6px (384.96 m)
planet diameter 136px (2218.4135 m)
planet circumference= Pi x D
PC= 6969.3517 meters
the event is said to have happened in an intant and in a moment in 2 different occasions
so i will use 1 second
Speed=6969.3517 m/s
atlas is a puryfying system, and i have no idea what it is made of
but i will use human density given it is a sentient being and a lowball if anything 1062 kg/m^3
volume of atlas is an sphere with a diameter of 384.96
29875000 m^3
however when he is killed we are shown atlas has a certain hollowness inside
so i will use 0.2 for hollowness
Atlas KE is then
mass=Volume x density
KE= Mv^2 x 0.5
KE=29875000 x 1062 x 6969.3517^2 x 0.5 x 0.2
KE=1.5410516e+17 joules
now let's get the power of the dust atlas throwed away
diameter is 23.6 px (384.96 m)
height is 33.24 px (542.20 meters)
this is a cone
21035825 m^3
air density is 1.225 kg/m^3
M=21035825 x1,225
M=25768885.625 kg
now let' get the PE and KE
PE= M x G x H(com)
PE= 25768885.625 x 9.81 x 542.20 x 0.5
PE=68532119399.7 joules
i will also try the ke of the planet escape velocity out since we dont see the sand getting back to the planet
planet volume is a sphere with a diameter of 2218.4135 m
5712500000 m^3
http://www.ajdesigner.com/phpgravity/gravity_escape_velocity_equation.php#ajscroll
assuming gravity is 9.82 m/s i get mass of the planet as 7.2400152384378E+17 kg
escape velocity then becomes 208.71 m/s
Density= Mass/volume
Density=7.2400152384378E+17/5712500000
Density=126739873 kg/m^3
Atlas volume=29875000 m^3
Mass= Volume x density
Mass of the moved rock by atlas appearing= 29875000 x 126739873
MMRAA=3.78635371e15 kg
KE= mv^2 x 0.5
KE=3.78635371e15 x 208.71^2 x 0.5
KE=8.24665265e19 joules
now now funnily enough this planet actually isn't a proper planet
it was a random planet with no living properties that said alien ball terraformed
of course the alien ball is not to scalle on the above panel given it is way smaller than the planet
but we can still scalle based on it
window 2 px (1.5m)
chord height is 58 px
chord diameter is 325 px
ER=(58 /2)+325^2/(8 x 58 )
SR=256.64 px
SD=513.28 px (384.96 meters)
given we can't see the sphere the diameter of the explosion is at least as big
explosion diameter is 23.6px (384.96 m)
planet diameter 136px (2218.4135 m)
planet circumference= Pi x D
PC= 6969.3517 meters
the event is said to have happened in an intant and in a moment in 2 different occasions
so i will use 1 second
Speed=6969.3517 m/s
atlas is a puryfying system, and i have no idea what it is made of
but i will use human density given it is a sentient being and a lowball if anything 1062 kg/m^3
volume of atlas is an sphere with a diameter of 384.96
29875000 m^3
however when he is killed we are shown atlas has a certain hollowness inside
so i will use 0.2 for hollowness
Atlas KE is then
mass=Volume x density
KE= Mv^2 x 0.5
KE=29875000 x 1062 x 6969.3517^2 x 0.5 x 0.2
KE=1.5410516e+17 joules
now let's get the power of the dust atlas throwed away
diameter is 23.6 px (384.96 m)
height is 33.24 px (542.20 meters)
this is a cone
21035825 m^3
air density is 1.225 kg/m^3
M=21035825 x1,225
M=25768885.625 kg
now let' get the PE and KE
PE= M x G x H(com)
PE= 25768885.625 x 9.81 x 542.20 x 0.5
PE=68532119399.7 joules
i will also try the ke of the planet escape velocity out since we dont see the sand getting back to the planet
planet volume is a sphere with a diameter of 2218.4135 m
5712500000 m^3
http://www.ajdesigner.com/phpgravity/gravity_escape_velocity_equation.php#ajscroll
assuming gravity is 9.82 m/s i get mass of the planet as 7.2400152384378E+17 kg
escape velocity then becomes 208.71 m/s
Density= Mass/volume
Density=7.2400152384378E+17/5712500000
Density=126739873 kg/m^3
Atlas volume=29875000 m^3
Mass= Volume x density
Mass of the moved rock by atlas appearing= 29875000 x 126739873
MMRAA=3.78635371e15 kg
KE= mv^2 x 0.5
KE=3.78635371e15 x 208.71^2 x 0.5
KE=8.24665265e19 joules
This was just a commercial but i don't doubt umibozo can do it tbh
Man Ages better than woman i guess
this shit is going to be kinda hard to do tbh
but hopefully it will be really worthy it
orihime fires a huge air cannon with a age gas and gintoki and katsura literally hit a missile so hard it blitzed the air shot making a visible from space explosion
now let's get to it
the top of Ryuugu is actually a island
shinpachi head is 5 px (1.66/7.2=0.23 m)
cave height is 62px(2.85m)
cave is 19 px
island lenght is 556px(83.4 m)
island lenght should be as big as the top of the ryugu ship given they are the same thing
it is 29.068 px
the distance from the missile and the air shot is 191.41 px (549.181024 m)
the distance the shot is feom the surrounding buildings is around 71.3 px (200.892568 m)
the shot dimensions are the ones of an ellipsoid with diameter of 44.011px(124.00397 m) and a lenght of 93.92 px (264.625946 m)
the resevoir of air on the size dimensions are the one of a prism of 27 x 18 x 18 px (77.46663 x 51.64442 x 51.6444)m
so it has 206614.741398 m^3 for air storage
well its a nigh square
so really
panel height is 412px
shot is 250 px
building window is 11px (1.5m)
2*atan(250/(412/tan((70 deg)/2))) 46.0396484 deg
145.93 meters
2*atan(11/(412/tan((70 deg)/2))) 2.1420238 deg
40.118 meters
200.892568-(145.93-40.118)=95.08 meters crossed by the air shot
which means the missile needed to cross 549.18 + 95.08= 644.26 meters
now we need to get the air shot speed
luckily i found a formula for this
http://www.iontrap.wabash.edu/adlab/papers/S2011_Buresh
v= square root (2/mass x (PoxVo log(1 + (L x A /V0))-L x A x Patm - L x F)
https://i.imgsafe.org/7ac37f7.jpg
L=17.46px (50.095 m)
H=8px (22.953 m)
now let's get to it
Mass of air is the volume of the air shot timed by air density M=2130601.48124472 x 1.225
M=2609986.81452 kg
Po can be get by PoVo=PatmV
Vo is the volume of the cannon
which is 45239.53162545396 m^3
patm=325 pascals
V is the volume of the air shot
Po x 45239.53162545396= 325 x 2130601.48124472
PO=15306.2035 pascals
f can be assumed to be nearly zero according to the paper
v= square root (2/2609986.81452 x (15306.2035x 206614.741398 log(1 + (50.095 x 22.953 /206614.741398 ))-(50.095 x 22.953 x 325))=2.356784m/s
fuck me
pathy
this is literally imposible given both context and even freefall
i'll use this one because screw this shit
https://www.physicsforums.com/threads/air-cannon-theory-help-internal-ballistics.191299/
P=0.5 x air density x v^2
15306.2035/(0.5 x 1.225)= v^2
v=158.081 m/s
well, this is better really
timeframe=95.08/158.081
timeframe=0.6 s
Speed of the misile=644.26/0.6
Speed of the missile=1073.766 m/s
now let's do the ke of both
KE of geezer cannon=2609986.81452 x 0.5 x 158.081^2
KE of geezer cannon=32611266592.2 joules
now we need to measure the missile
gintoki head is 42 px (1.77/7.2=0.2458 m)
missile width is 78.29px (0.4565 m)
missile lenght is 204.286 px (1.1955 m)
cylinder calculator
0.19566854949264115 m^3
steel density is 8700 kg/m^3
M=0.19566854949264115 x 8700
M=1702.316 kg
KE=1702.316 x 1073.766^2 x 0.5
KE=981362552.566 joules
but that's not all the attack also generated a shockwave/explosion that throwed the vaccine gas of the missile all over japan
which is were the light comes from
earth diameter is 108px (12742000 meters)
explosion diameter is 19.2 px (2265244.444 m)
explosion height is 65.85 px (7769080.55556 m)
now we need a timeframe to see how fast the air was dissipated
luckily i have the freefall of the ship deebris thats tarted to fall before the dissipation
ryuugu top is 45px (83.4 m)
height of the deebris fall 181px (335.45 m)
which gives me a timeframe of 8.27 s
but thats just a low ball
we know for a fact what was the time it took for the missile to start dissipation
total distance of the missile till the shot is
198.17px+191.41px + the 95 meters the air shot crossed
which means
1117.7574 + 95 meters=1212.7574 meters
speed of the missile is 1073.766 m/s
T=1212.7574/1073.766
T=1.129 seconds
TT=8.27-1.129
TT=7.141 seconds
speed of the horizontal expansion=2265244.444/7.141
SHE=317216.698502 m/s
now lets get ke of the expansion
2609986.81452 x 0.5 x 317216.698502^2
KE=1.3131683e+17 joules halving it i get my result for each
31.3854763
now i will get the light enrgy of the attack which is based on 200 j/cm^2 (till cat brings a new value)
i will need the radius till the viewer
http://i.imgur.com/g2BTHsg.jpg
earth is 108 px
panel height is 338 px
panel lenght is 682 px
now lets work out with it
2*atan(tan(70/2 deg))*(682/338)=141.242604 deg pov
2*atan(108/(682/tan((141.242604)/2))) 48.4760209 deg
or about 14151 km
which is the radius of our sphere
giving a surface area of 2.52E+15 m^2
or about 2.52 � 10^19 cm^2
E= 2.52 � 10^19 x 200
E=5.04e+21 joules
now i halve this an give to gin and zura
but hopefully it will be really worthy it
orihime fires a huge air cannon with a age gas and gintoki and katsura literally hit a missile so hard it blitzed the air shot making a visible from space explosion
now let's get to it
the top of Ryuugu is actually a island
shinpachi head is 5 px (1.66/7.2=0.23 m)
cave height is 62px(2.85m)
cave is 19 px
island lenght is 556px(83.4 m)
island lenght should be as big as the top of the ryugu ship given they are the same thing
it is 29.068 px
the distance from the missile and the air shot is 191.41 px (549.181024 m)
the distance the shot is feom the surrounding buildings is around 71.3 px (200.892568 m)
the shot dimensions are the ones of an ellipsoid with diameter of 44.011px(124.00397 m) and a lenght of 93.92 px (264.625946 m)
the resevoir of air on the size dimensions are the one of a prism of 27 x 18 x 18 px (77.46663 x 51.64442 x 51.6444)m
so it has 206614.741398 m^3 for air storage
well its a nigh square
so really
panel height is 412px
shot is 250 px
building window is 11px (1.5m)
2*atan(250/(412/tan((70 deg)/2))) 46.0396484 deg
145.93 meters
2*atan(11/(412/tan((70 deg)/2))) 2.1420238 deg
40.118 meters
200.892568-(145.93-40.118)=95.08 meters crossed by the air shot
which means the missile needed to cross 549.18 + 95.08= 644.26 meters
now we need to get the air shot speed
http://www.iontrap.wabash.edu/adlab/papers/S2011_Buresh
v= square root (2/mass x (PoxVo log(1 + (L x A /V0))-L x A x Patm - L x F)
https://i.imgsafe.org/7ac37f7.jpg
L=17.46px (50.095 m)
H=8px (22.953 m)
now let's get to it
Mass of air is the volume of the air shot timed by air density M=2130601.48124472 x 1.225
M=2609986.81452 kg
Po can be get by PoVo=PatmV
Vo is the volume of the cannon
which is 45239.53162545396 m^3
patm=325 pascals
V is the volume of the air shot
Po x 45239.53162545396= 325 x 2130601.48124472
PO=15306.2035 pascals
v= square root (2/2609986.81452 x (15306.2035x 206614.741398 log(1 + (50.095 x 22.953 /206614.741398 ))-(50.095 x 22.953 x 325))=2.356784m/s
fuck me
pathythis is literally imposible given both context and even freefall
i'll use this one because screw this shit
https://www.physicsforums.com/threads/air-cannon-theory-help-internal-ballistics.191299/
P=0.5 x air density x v^2
15306.2035/(0.5 x 1.225)= v^2
v=158.081 m/s
well, this is better really
timeframe=95.08/158.081
timeframe=0.6 s
Speed of the misile=644.26/0.6
Speed of the missile=1073.766 m/s
now let's do the ke of both
KE of geezer cannon=2609986.81452 x 0.5 x 158.081^2
KE of geezer cannon=32611266592.2 joules
now we need to measure the missile
gintoki head is 42 px (1.77/7.2=0.2458 m)
missile width is 78.29px (0.4565 m)
missile lenght is 204.286 px (1.1955 m)
cylinder calculator
0.19566854949264115 m^3
steel density is 8700 kg/m^3
M=0.19566854949264115 x 8700
M=1702.316 kg
KE=1702.316 x 1073.766^2 x 0.5
KE=981362552.566 joules
but that's not all the attack also generated a shockwave/explosion that throwed the vaccine gas of the missile all over japan
which is were the light comes from
earth diameter is 108px (12742000 meters)
explosion diameter is 19.2 px (2265244.444 m)
explosion height is 65.85 px (7769080.55556 m)
now we need a timeframe to see how fast the air was dissipated
luckily i have the freefall of the ship deebris thats tarted to fall before the dissipation
ryuugu top is 45px (83.4 m)
height of the deebris fall 181px (335.45 m)
which gives me a timeframe of 8.27 s
but thats just a low ball
we know for a fact what was the time it took for the missile to start dissipation
total distance of the missile till the shot is
198.17px+191.41px + the 95 meters the air shot crossed
which means
1117.7574 + 95 meters=1212.7574 meters
speed of the missile is 1073.766 m/s
T=1212.7574/1073.766
T=1.129 seconds
TT=8.27-1.129
TT=7.141 seconds
speed of the horizontal expansion=2265244.444/7.141
SHE=317216.698502 m/s
now lets get ke of the expansion
2609986.81452 x 0.5 x 317216.698502^2
KE=1.3131683e+17 joules halving it i get my result for each
31.3854763
now i will get the light enrgy of the attack which is based on 200 j/cm^2 (till cat brings a new value)
i will need the radius till the viewer
http://i.imgur.com/g2BTHsg.jpg
earth is 108 px
panel height is 338 px
panel lenght is 682 px
now lets work out with it
2*atan(tan(70/2 deg))*(682/338)=141.242604 deg pov
2*atan(108/(682/tan((141.242604)/2))) 48.4760209 deg
or about 14151 km
which is the radius of our sphere
giving a surface area of 2.52E+15 m^2
or about 2.52 � 10^19 cm^2
E= 2.52 � 10^19 x 200
E=5.04e+21 joules
now i halve this an give to gin and zura
City level-Island level gin and zura
