Calc Feel the lols: 9 (gintama) the renho edition

Some dumbass thought it was a good idea try putting a bomb on kagura bed while she was sleeping but she sonambulously exploded it while together with him
http://i5.[Blocked Domain]/gintama/320/gintama-1722408.jpg
http://i1.[Blocked Domain]/gintama/320/gintama-1722409.jpg

really straight forward
kagura 70.71px(1.55m)
crater deepth is 41.03px (0.899398953 m)
crater lenght 424px (9.2943 m)
shaping it like half an ellipsoid i get 40.680321 m^3
wow this sounds underhelming
i will use both rock pulverization (214j/cc) and rock vaporization(27005 j/cc) (as this shit is a heat based bomb and there is schorch everywhere)
E(LE)=V x RP
E(LE)=40680321 x 214
E(LE)=8705588694 joules
E(HE)= V x RV
E(HE)=40680321 x 27005
E(HE)=1098572068605 joules
or

sachan uses her special glasses to get an armor and throw glasses so fast that they start flaming themselves
http://i6.[Blocked Domain]/gintama/321/gintama-1726373.jpg
http://i10.[Blocked Domain]/gintama/321/gintama-1726375.jpg
so to get the speed she needed to achieve i will need to compare the heat energy to the work of the drag force on the glasses because thats the only way i can think that relates energy with speed and heat
first let's get Q
Q=mct
butyl acetate is commonly used on glasses
its autoignition temperature is 421c
http://www.engineeringtoolbox.com/fuels-ignition-temperatures-d_171.html
average temperature is 20 degrees
specific heat of glass is 840 j/kg

sacchan height is 219.559 px (1.69 m)
sacchan arm lenght is 113.416 px ( 0.873 m)
glasses lenght is 44.94 px (0.346 m)
glasses width 13.45 px ( 0.103 m)
glasses deepth is 3 px (0.0231 m)
now now i will shape the glasses as a rectanguar prims
V=0.346 x 0.103 x 0.0231
V=0.0008232378 m^3
now we need to get the mass of the glasses
glass density is 2400 kg/m^3
M=0.0008232378 x 2400
M=1.97577 kg
well thats actually surprising i guess sacchan glasses were indeed thick as all fuck compared to normal ones
Q=1.97577 x 840 x (421-20)
Q=665518.367 joules
now now, let's bust my head with drag coefficient method
http://physics.info/drag/
work of Drag force= ½ρCAv2 x d
p being density of air (1.225kg/m^3)
C drag coeficient of glasses
v^2 being speed
A being surface area
D being the distance crossed by sacchan arms
this needs to be= Q
so lets work
drag coeficient of rectangles is 2.1
sacchan arm distance is her arm lenght x around 120 degrees (0.873 x 2.0943951)
surface area of a rectangular prism like this is 0.0920198 m^2
665518.367 x 2= 1.225 x 2.1 x 0.0920198 x v2 x 1.82840692
V^2=1331036.73/(0.432822197)
V^2=3075250.62
V=1753.63925 m/s
or

The renho people have a tec that allows them to plant seeds on a planet and when time comes sagi can activate them and then begin the plan which is basically cover the whole world with transfigurating clouds within less than a day
http://i10.[Blocked Domain]/gintama/354/gintama-3153491.jpg
http://i8.[Blocked Domain]/gintama/354/gintama-3153493.jpg
http://i2.[Blocked Domain]/gintama/354/gintama-3153495.jpg
http://i1.[Blocked Domain]/gintama/355/gintama-3153515.jpg
so we got something pretty straight forward really
earth circumference is 40075000 m
cloud thickness is around 2000 meters
earth surface area is 5.100656e14 m^2
thus volume is 5.100656e14 x 2000=1.0201312e18 m^3
density of air is 1.225 kg/m^3
Mass=1.0201312e18 x 1.225
Mass=1.2496607e+18 kg
a day has 24 hours or about 86400 seconds
S=40075000/86400
S=463.831019 m/s
KE= m x v^2 x 0.5
KE=1.2496607e+18 x 463.831019^2 x 0.5
KE=1.3442551e23 joules
halving by 3 for each of their seeds
individual kinetic energy for renho's seeds=4.48085033e22
or about

katsura steals a gundam but it gets destroyed by bombs planted by bitch do m number xxxx
http://i2.[Blocked Domain]/gintama/356/gintama-3153573.jpg
http://i4.[Blocked Domain]/gintama/356/gintama-3153575.jpg

katsura height is 1.75 m (39px)
gunman width is (145px) 6.506 m
then on the panel below gunman width becomes 41px
while gunman height is 150.863 px (23.941 m)
now we need to do an cubic square law
V2=(H2/H1)^3 x V1
http://www.narutoforums.com/xfa-blog-entry/human-body-destruction-values.22383/
volume of a human is 65913.4 cc
V2=(23.941/1.7)^3 x 65913.4
V2=184100009 cc
gunmans are high tech steel so its violent fragmentation is 1000 j/cc
the hollowness will be assumed as 80%
E= 184100009 x 1000 x 0.2
E=36820001800 joules
or