Calc iwandesu calc request time:11.5 (multiple verses) the alelluia edition

first off lets get the robot height

fucker head is 30px (average 1.7 manga man head is 23.6cm)
robot head 164px (1.25m)
robot height 436px(3.34m)
now the crater shenanigans

robot head is 1.25m (183.65px)
crater width is 690.79px(4.70m)
crater deepth is 633px (4.31m)
now to get crater lenght i will angsize the crater, given the crater starts before the panel it is actually quite a low end
crater width far away 18.68px
panel height is 867px
panel lenght is 1200px
2*atan(tan(70/2 deg))*(867/1200) the fov is 50.57500 deg
2*atan(18.36/(867/tan(50.575/2 deg)))=1.14638385 deg
which gives me about 234.9 meters
shaping this as a quadrangular prism
v=234.9 x 4.31 x 4.70

i can either use pulverization of the rock because to move this much of rock on such way a similar volume would need to be destroyed (which is shown by the dust all around the crater)
or i can get ke because this much of volume is being dislocated
i will do both
rock pulverization=214j/cc
E=v x RP
E=4758369300 x 214
E= 1.018291e+12 joules
ke=m x v^2x 0.5
Mass=density x volume
density of rock=2700 kg/m^3
M=2700 x 4758.3693
M=12847597.11 kg
S=D/T
to get timeframe i will use freefall of the robot
body height above the ground 99.36px (0.67m)
total height above the ground 1.92m
total height freefalled 3.34-1.92
THF=1.42m
freefall of such distance gives me a timeframe of
0.54seconds
now there are 2 distances we can visualize here
the diameter of the crater(the speed of the separation) and the lenght of the crater (the speed of the attack in itself)
i will do both
S1=4.70/0.54
S1=8.70 m/s
S2=234.9/0.54
S2=435 m/s
E=mv^2 x 0.5
KE1=12847597.11 x 8.7^2 x 0.5
KE1=486217312.628 joules
KE2=12847597.11 x 435^2 x 0.5
KE2=1018291030200 joules

this feat is quite tricky because the only thing to scalle in the panel that isnt fucked by background perspective is the water deepth (as yaiba is way into the background)
so first we need to get yaiba (?) head size
sayaka mine is an average japanese girl 158cm
her head as an manga girl is 1/6 of her body
1.58/6=0.263 (38px)
yaiba(?) head is 357px(2.44m)
now i will need to calc the size of yaiba sword to compare it to the deepth of the ocean

yaiba head is 44px
yaiba sword is 143.125 (7.936m)
now we will use this to compare

yaiba head 21 px
sword part that is not inside the water 50.32px(5.84m)
this makes the deepth of the ocean 7.936-5.84=2.096 m
now we finally can scalle

water deepth 2px(2.098)
crater lenght 807px (846.543 m)
crater width is 454.42px(476.686 m)
for crater deepth i will go with width size
i will shape this as half of an ellipsoid which gives me
on a similar manner i can get the volume of the vaped water
which is basically a rerun of this only shaped as a elliptical tank and with the water deepth

we cant really proff the crater was vaped given vaping of water happens at 100 degrees celsius
so i will just use pulverization of rock there
E=V x PR
E=50359619935200 x 214
E=1.0776959e+16 joules
now water vaporization is 2,260j/cc
E=v x WV
E=664931313006 x 2260
E=1.5027448e+15 joules
or

to get the volume of the fragmented part of the moon i will use the intersection of 2 spheres method
moon diameter is 3474000 meters (1305px)
distance between intersections=784.149px (2087458.72 m)
moon radius=653px (1737000 m)
outer crater radius=314 px(835889.65517 m)
volume=
volume=pi*(1737000+ 835889.65517- 2087458.72 )^2 *(2087458.72 ^2 + 2*835889.65517*2087458.72 - 3*835889.65517^2 + 2*1737000*2087458.72 + 6* 1737000*835889.65517- 3*1737000^2)/(12*2087458.72 )
which gives me 3.7423568e+17 m^3
now lets play a bit with the moon deebris shall we
moon deebri lenght is 215px (572344.827586m)
moon deebri width is 83px (220951.724138m)
shaping this like a ellipsoid we have a volume of
14630230694665574m^3

Now first lets calc the fragmentation of the whole thing
rock fragmentation is 8 j/cc
E=V x RF
E=3.7423568e+23 x 8
E=2.99388544 � 10^24 joules
but we can do some other shenanigans
like getting the pe of the throwed debbri
lunar rock densities varies from 2340 kg/m^3 to 3460kg/m^3
an average for that would be 2910kg/m^3
Mass= volume x density
M=2910 x 14630230694665574
M=4.2573971e+19 kg
Pe=m x g x h
gravity in the moon is 1,622 m/s�
the height of the deebri is 161px (428593m)
PE=428593 x 1,622 x 4.2573971e+19
PE=2.95964815 � 10^25 joules

to get the distance the beam travelled i will pick the distance moon is from pov and add earth to moon distance earth is from fov


moon diameter 1305px
panel height is 1105 px
panel lenght is 3957.08 px
earth chord is 438.223 px
chord height is 32.202 px
chord formula is
Earth radius=(h/2)+c^2/(8h)
ER=(32.202/2)+438.223 ^2/(8 x 32.202)
ER=761.549 px
Er=6371000 m
2*atan(tan(70/2 deg))*(1105/3957.08)=19.54724 deg for fov
2*atan(1305/(3957.08/tan(19.54/2 deg))) is 6.500281 deg
putting this on the calculator i get
56096000 meters

2*atan(1305/(1105/tan(19.5472419/2 deg)))=22.9979 deg
inputting this on a angsize calculator i get
8538400 meters till the moon
add this to the earth moon distance and you have
380000000 + 8538400=388538400 meters crossed
now i will assume it took 60 seconds to arrive the shields (quite low balled but there is nothing proving it took less )
S=56096000/60=934933.333333 m/s