now that i'm done with yet another university exam i may as well dump a bunch of calc requests as my brazilian's children's day present to you fuckers
1.Laxus the god of the bit feats (fairy fail)
feats requested by brightsteel
Ajeel brings damn sand tsunami and laxus disperses it before it reaches grandpa
he then procceds to nuke everything in its surrounds
i'll be calcing a bunch of things out this feat because i can
legit af
2.A Baddass also does bit feats (Saint Seiya Lost canvas)
feats requested by dark lord dragon
3.let's see if i can give someone what they asked for (Gash bell)
requested by patrick
1.Laxus the god of the bit feats (fairy fail)
feats requested by brightsteel
Ajeel brings damn sand tsunami and laxus disperses it before it reaches grandpa
he then procceds to nuke everything in its surrounds
i'll be calcing a bunch of things out this feat because i can
sand tsunami volume
i'll be assuming both the tree beneath the tsunami and the tree at ajeel size have the same size
i'll be using 180 for ajeel because he has that huge spiky hair on spite of having an average man height
and i'll assume the tsunami's deepth is equal to its height
ajeel is 29px
tree next to ajeel is 66px
makarov's head is 43px
tsunami's height is 241px
tsunami's lenght is 745px
tree next to the tsunami 11px
T=4.09 meters
MH=2.67 meters
TH=89.60 meters
TL=277 meters
shapping the tsunami as a rectangular prism
V=277 x 89.6 x 89.6
travelled distances
Energy
first off i'll assume the tsunami is moving on an average tsunami speed at ground (because its not particularly fast and slowly arrives at its prey) which is 80 km/h (22.22m/s)
dry sand density is 1602 kg/M^3
m=vxd
M=2223800.32x 1602
Mass=3562528112.64kg
E=m*v^2 x 0.5
E=3562528112.64*22.22^2 x 0.5
E=8.79460653 10^11 joules
E= m x g x hcom
a prism com is 1/2 its height
E=3562528112.64 x 10 x 89.60 x 0.5
E=1.5960126e+12 joules
now for the speed of the dispersion
it happened before the tsunami could cross 6.18 meters
T=6.18/22.22
T=0.27812781278 seconds
i'll use the tsunami lenght to get the speed of the dispersion
S=277/0.278
s=996.40 m/s
E=m x v^2 x 0.5
E=3562528112.64 x 996.40^2 x 0.5
according to mike we should be able to use sand vaporization value
we have no vaporization value for sand
but i may as well do a rough one
Vaporization and melting value of sand
Energy
then we can get the speed of laxus lighting
timeframe=0.27812781278 seconds
distance=646.71 meters
speed=646.71/0.27812781278
[
and finally the lighting nuke
it is pretty straightforward
from this panel we can it spreads much abovecloud height
so at least 1 km of radius
with the nuke calculator is either 2.89(widespread destruction)-54,8 kilotons of tnt (near total fatalities)
i'll be assuming both the tree beneath the tsunami and the tree at ajeel size have the same size
i'll be using 180 for ajeel because he has that huge spiky hair on spite of having an average man height
and i'll assume the tsunami's deepth is equal to its height
ajeel is 29px
tree next to ajeel is 66px
makarov's head is 43px
tsunami's height is 241px
tsunami's lenght is 745px
tree next to the tsunami 11px
T=4.09 meters
MH=2.67 meters
TH=89.60 meters
TL=277 meters
shapping the tsunami as a rectangular prism
V=277 x 89.6 x 89.6
first off i need the ship's head lenght
i'll assume the window height is 1.5 m(7px)
the horse head is 104px
making it 22.285 meters
horse head is 14 px
panel height is 385px
2*atan(14/(385/tan(70/2)))=1.97417439 degrees
using the angsize calculator i get 646.71 meters from wjere laxus throwed his lighting
now i need the distance the sand tsunami would travel
makarov's head is 2.06 meters (8px)
the distance from the tsunami is 24 px
making it 6.18 meters
i'll assume the window height is 1.5 m(7px)
the horse head is 104px
making it 22.285 meters
horse head is 14 px
panel height is 385px
2*atan(14/(385/tan(70/2)))=1.97417439 degrees
using the angsize calculator i get 646.71 meters from wjere laxus throwed his lighting
now i need the distance the sand tsunami would travel
makarov's head is 2.06 meters (8px)
the distance from the tsunami is 24 px
making it 6.18 meters
Energy
dry sand density is 1602 kg/M^3
m=vxd
M=2223800.32x 1602
Mass=3562528112.64kg
E=3562528112.64*22.22^2 x 0.5
E=8.79460653 10^11 joules
E= m x g x hcom
a prism com is 1/2 its height
E=3562528112.64 x 10 x 89.60 x 0.5
E=1.5960126e+12 joules
it happened before the tsunami could cross 6.18 meters
T=6.18/22.22
T=0.27812781278 seconds
i'll use the tsunami lenght to get the speed of the dispersion
S=277/0.278
s=996.40 m/s
E=m x v^2 x 0.5
E=3562528112.64 x 996.40^2 x 0.5
according to mike we should be able to use sand vaporization value
we have no vaporization value for sand
but i may as well do a rough one
Vaporization and melting value of sand
i will just assume we are dealing with 100 m^3 of sand for the sake of simplicity
sand is made roughly of 85% of silica and 15% of alumina
85% (SiO2) = 85 m^3
Density = 2203.233 kg/m^3
Mass = 187274805 g
Molar mass = 60.0843 g/mol = 3116867.551 mol
Latent Heat of Fusion = 50.21 kJ mol-1
Latent Energy Q2= 156497919740 J
15% (Al2O3)= 15 m^3
density=3940 kg/m^3
Mass=59100000 g
molar mass=101.96 g/mol= 579639.074147mol
latent heat of fusion=620 kj/mol
Latent energy 2=359376225971 joules
Total energy= 359376225971+ 156497919740
TE=515874145711 joules
as for vaporization
boiling point of sand is 2230 C
specific heat of sand is 830 j/kg
mass of 100 m^3 of sand is 160000 kg
Q=160000 x(2230-20)x 830
Q= 293488000000 j
latent heat of vaporization of Sio2=18000 kj/kg
latent heat of vaporization of al2o3=1816000 j/mol or
109113.0888 j/kg
energy of silica=0.85 x 18000000 x 160000
energy of alumina=0.15 x 1816000 x 160000
ES=2.448e+12 joules
EA=43584000000 joules
total energy= 2.491584e+12 joules
or
sand is made roughly of 85% of silica and 15% of alumina
85% (SiO2) = 85 m^3
Density = 2203.233 kg/m^3
Mass = 187274805 g
Molar mass = 60.0843 g/mol = 3116867.551 mol
Latent Heat of Fusion = 50.21 kJ mol-1
Latent Energy Q2= 156497919740 J
15% (Al2O3)= 15 m^3
density=3940 kg/m^3
Mass=59100000 g
molar mass=101.96 g/mol= 579639.074147mol
latent heat of fusion=620 kj/mol
Latent energy 2=359376225971 joules
Total energy= 359376225971+ 156497919740
TE=515874145711 joules
as for vaporization
boiling point of sand is 2230 C
specific heat of sand is 830 j/kg
mass of 100 m^3 of sand is 160000 kg
Q=160000 x(2230-20)x 830
Q= 293488000000 j
latent heat of vaporization of Sio2=18000 kj/kg
latent heat of vaporization of al2o3=1816000 j/mol or
109113.0888 j/kg
energy of silica=0.85 x 18000000 x 160000
energy of alumina=0.15 x 1816000 x 160000
ES=2.448e+12 joules
EA=43584000000 joules
total energy= 2.491584e+12 joules
or
now for the actual energy
Energy
E= V x VS
E=5158.7414 x 2223800320000
E=1.1472011e+16 joules
E=24915.84 x2223800320000
E=5158.7414 x 2223800320000
E=1.1472011e+16 joules
E=24915.84 x2223800320000
timeframe=0.27812781278 seconds
distance=646.71 meters
speed=646.71/0.27812781278
and finally the lighting nuke
it is pretty straightforward
from this panel we can it spreads much above
so at least 1 km of radius
with the nuke calculator is either 2.89(widespread destruction)-54,8 kilotons of tnt (near total fatalities)
so we have a mcb level top tier a city level attack which was hyped to merk him and a slowest than taurus current laxus
legit af
2.A Baddass also does bit feats (Saint Seiya Lost canvas)
feats requested by dark lord dragon
defteros byssects a hill without a cloth
volume of the bissected hill
gemini becomes extremely tall so i suppose he should be at least with 1.70 (166.15px) on his teens days
he opened a crater with a width of 343px
or 3.51 meters
now i'll assume this is the same width of all this byssection borders to get its measurements
panel height 594px
distance of the hill from the viewer is
2*atan(343/(594/tan(70/2)))=30.6033092 degrees
or with the angsizing calculator 6.41 meters
now we need the distance of the top of the hill (55px) from the viewer to generate a pytagoric triangle
2*atan(55/(594/tan(70/2))) 5.02410863 degrees
or in the calculator
40.004 meters
40.004^2=6.41^2 + h^2
Height of the hill=39.48 meters
now to get the deepth i will need to create yet another triangle using the distance from the viewer and the border (16px)
2*atan(16/(594/tan(70/2)))=1.4624167 degrees
which gives me 137.51 meters
137.51^2=39.48^2 + D^2
Deepth=131.72-6.41=125.31 meters
i'm shaping it as a retangular prism
volume=125.31 x 39.48 x 3.51
V=17364.808188 m^3
volume of the bissected hill
gemini becomes extremely tall so i suppose he should be at least with 1.70 (166.15px) on his teens days
he opened a crater with a width of 343px
or 3.51 meters
now i'll assume this is the same width of all this byssection borders to get its measurements
panel height 594px
distance of the hill from the viewer is
2*atan(343/(594/tan(70/2)))=30.6033092 degrees
or with the angsizing calculator 6.41 meters
now we need the distance of the top of the hill (55px) from the viewer to generate a pytagoric triangle
2*atan(55/(594/tan(70/2))) 5.02410863 degrees
or in the calculator
40.004 meters
40.004^2=6.41^2 + h^2
Height of the hill=39.48 meters
now to get the deepth i will need to create yet another triangle using the distance from the viewer and the border (16px)
2*atan(16/(594/tan(70/2)))=1.4624167 degrees
which gives me 137.51 meters
137.51^2=39.48^2 + D^2
Deepth=131.72-6.41=125.31 meters
i'm shaping it as a retangular prism
volume=125.31 x 39.48 x 3.51
V=17364.808188 m^3
energy
saint seiya characters can atomize shit
atomization of rock=30852.2j/cc
Nuclear Binding Energy of rock is 2143012962432.5 Joules/cc
E=AR x V
E=30852.2 x 17364808188
E=5.35742535 10^14 joules
E=17364808188 x 2143012962432.5
E=3.7213009e22 joules
atomization of rock=30852.2j/cc
Nuclear Binding Energy of rock is 2143012962432.5 Joules/cc
E=AR x V
E=30852.2 x 17364808188
E=5.35742535 10^14 joules
E=17364808188 x 2143012962432.5
E=3.7213009e22 joules
so a country level bit feat for defteros without a cloth
3.let's see if i can give someone what they asked for (Gash bell)
requested by patrick
this fucker flies into outer space in the time it takes to zatch and kyo briefly explain what he is doing
distance crossed
distance crossed
first we need the size of the sphere in his head
i'll assume the torso + head on his head represents 1meter (36px)
the black sphere is 96px
black sphere=2.66 meters
panel height 879px
sphere is 4px
distance of the sphere from the viewer is
2*atan(4/(879/tan(70/2)))=0.247076602 degrees
on the calculator 619.35 meters
so pretty much irrelevant to the shit we are dealing with but oh well.
distance of earth from the viewer
2*atan(1697/(879/tan(70/2)))=84.9013135 degrees
or 6950.2 km in the calculator
6950.2-0.61935=6949.58 kilometers
i'll assume the torso + head on his head represents 1meter (36px)
the black sphere is 96px
black sphere=2.66 meters
panel height 879px
sphere is 4px
distance of the sphere from the viewer is
2*atan(4/(879/tan(70/2)))=0.247076602 degrees
on the calculator 619.35 meters
so pretty much irrelevant to the shit we are dealing with but oh well.
distance of earth from the viewer
2*atan(1697/(879/tan(70/2)))=84.9013135 degrees
or 6950.2 km in the calculator
6950.2-0.61935=6949.58 kilometers
Speed
i will pick many timeframes considering how he did so while zatch and kyon changed few words
S=D/T
S (LE)=6949580/60
S=115826.333333 m/s
S(ME)=6949580/30
S=231652.666667 m/s
S(HE)=6949580/15
S=463305.333333 m/s
S=D/T
S (LE)=6949580/60
S=115826.333333 m/s
S(ME)=6949580/30
S=231652.666667 m/s
S(HE)=6949580/15
S=463305.333333 m/s
well this is still pretty neat i gues[/SPOILER]
