Calc iwandesu calc request time: 5 (multiple verses)

i'm assuming unicorn yato is 170 cm
manga body proportions are 1/7.2 yadayada
his head is then 23.6 cm
or 15px
the pillar is 100px
making it 157.33 cm wide

pillar is 2px (157.33 cm)
crater deepth is 200px (157.33 meters)
crater width is 111px (87.318 meters)
as for the diameter i will calc the distance aiacos is from the ship
he is 186cm (60px)
panel height is 682px
2*atan(60/(682/tan(70/2)))=4.7739 degrees
giving me 22.311 meters
now it is the time to get the distance from the ship
2*atan(2/(682/tan(70/2)))=0.159223263 degrees
or 566.15 meters
566.15-22.311= 543.839
i'll shape this thing as 4 retangular prisms (which should be safe considering there is a lot of unshown craters)
volume= 4 x 543.839 x 157.33 x 87.318
V=29884477.1803 m^3

Aiacos atomizes shit
binding energy of granite=2143012962432.5 Joules/cc
E= BEG x V
E=2143012962432.5 x 29884477180300
E=6.4042822e+25 joules

first of ajeel sandstorm was big enough to cover magnolia's town
so we are at least dealing with a base area of 1355.94 x 901.1 here
but this is not taking into account the huge area it also crossed outside magnolia

cathedral is 105.06 meters (86px)
rock deepth is 93px (113.611 meters)
so lets get how far bisca is from this

panel height 394px
rock formation is 26px
2*atan(26/(394/tan(70/2)))=3.58176293 degrees
or
1807.4 meters which refers to magnolia width
now we need to get the height the sandstorm achieved
here we see it is all the way up to the ships
to get how far are them i will resort to ang scalling

panel height 829px
cathedral 59px (105.06 m)
2*atan(59/(829 tan(70/2))) 17.08 degrees
or 324 meters
assuming we are dealing with a triangle i'll will assume 405.5 (distance between the cathedral and magnolia borderline from its sides) and height will be the minor catetus
H^2=405.5^2-324^2
H=243.83 meters
i will shape the sandstorm as a elliptic cylinder and then halve by 10 to take the shallowness into account
which gives me

KE=mv^2 x 0.5
Sand density is 1600 kg/m3
but considering the sheer amount of space lacking regi sugested me this

Googling around seems to tell me that the sand in actual sandstorms adds negligible mass
So just use your full volume and density of air, I guess

Click to expand...

so I Will actually be using this
air density= 1.225 kg/m^3
Mass=v x d
M=1.225 x 46932292.695619524
M=57492058.5521 kg
as for the speed it should be safe to assume average sandstorm speed given the sandstorm in itself was just a nuisance to everyone who saw it instead of an actual danger
so 23,6 m/s
E=57492058.5521 x 23.6^2 x 0.5
Energy=16010388465.6 joules
now using gpe of the sand we get
E=m x g x h(com)
E=57492058.5521 x 10 x 243.83 x 0.5
E=70091443183.8 joules