Calc iwandesu calc request time: 7 (multiple verses)

Calculations
yeah i'm back with more requests

1.gildarts punches some water away (fairy fail ice trial)
requested by redfag
gildarts punches water with a magic inbued punch and mess up with it

water volume

gildarts is about 188cm (19.235px)
monster eye is 17.49px (1.7094 meters)
monster head width is 129.69px (12.6757 meters)
minor diameter of water hole is (597 + 527)/2=562px(54.9290 meters)
OajRFcP.png

monster head width=19px
height of the water is 141.41px (94.34 meters)
major diameter of the water hole is 594.7px (396.75 meters)
i'm shaping this shit as a truncated cone
which gives me a volume of

volume of dislocated water=4500518.37 m^3

Energy
KE=m x V^2 x 0.5
M= D x V
water density is 1000kg/m^3
M=1000 x 4500518.37
M=4500518370 kg
V=D/T
for my timeframe i will be using the freefall of the monster here
as you can see he hadn't even started his fall when a relevant part of the water was already dislocated
monster eye is 1.7094 m(72px)
height from the ground is 62 px( 1.4719 m)
freefall time is 0.55 seconds
speed of dispersion = 396.75/0.55
speed of dispersion=721.3636 m/s
KE=4500518370 x 721.3636^2 x 0.5
KE=1.1709571e+15 joules

Kinetic energy of the water dispersion=279.865468 kilotons of tnt
so town level+ pre BOS gildarts
legit i guess

2. Mega evolution is the shit (pokemon mega evolution special)
requested by: yours truly
[youtube]QezEFGUJ3dY[/youtube]
15-25 seconds
basically mega gayrados and mega tyranitar creates a huge explosion with their blasts
first off they generate a minor explosion that covers then, i'll calc the diameter of this explosion by using both of their lenghts

a mega gayrados height is 6.5 meters
he is 46px
his lenght is 104px(14.41 meters)
i will add two meters for tyranitar and the distance between them
sphere diamter is 16.41meters
now we get the radius of the main explosion
3VqcTf4.png

explosion diameter is 48px(16.41)
panel height is 768px
2 * atan(48/ (768 / tan(70 / 2)))= 3.39245652 degrees
or about 277.07 meters in angsizing calculator
there is no yeild like this in the nuke calculator
so i will use the equation of the airblast radius
where the radius constant is y^0.33
and the size of a 5kt nuke is 476m
277.07/476=0.58207
y^0.33=0.58207
Y=0.1940
E=y x 5000
E=0.1940 x 5000
E=970 tons of tnt
halving it by 2 each pokemon has

Each pokemon's hyperbeam yeild=485 tons of tnt

3.Clear note annihilates some rocks (gash bell)
requested by patrick and if this shit is not legit is totally his fault
clear note power is the one of total matter annihilation
he then created a crater
i'll be calcing the energy needed to do so
crater volume
4yRDdyz.png

kay let's say this tree is about 5 meters (50px)
crater deepth is 280px (28m)
crater diameter is 863px (86.3m)
for the crater second diameter i will angsize the distance from the viewer and the tree
panel height is 1400 px
tree is 50px (5 meters)
clear note head is 121px(0.236m) i'm assuming he has an average mango boy head
we have respectively
2 * atan(50/ (1400/ tan(70 / 2))) 1.93892807 degrees
2 * atan(121/ (1400/ tan(70 / 2))) 4.69003321 degrees
which gives me
2.8815 meters and 147.74 meters
which means the total distance is about 144.8585 meters
shapping the crater as a elliptical tank we get a volume of
crater volume=274917.6938836033 m^3

Energy
i'll use 2 ends one for pulverization and the other for annihilation
pulverization of rock is 214j/cc
Nuclear binding energy of granite is 2143012962432.5 J/cc
Energy low end= v x RP
ELE=274917693883.6033 x 214
ELE= 5.88323865 ? 10^13joules
Energy high end= v x NBEG
EHE=274917693883.6033 x 2143012962432.5
EHE=5.89152182 ? 10^23 joules
Energy= 14.0612778 kilotons- 140.81075 teratons of tnt
so town to country level+ seems fair enough

4.koro-sensei dead and furious (assassination classroom)
requested by xenos
korosensei dodged a laser shot from 400 km away [URL="http://www.mangapanda.com/assassination-classroom/163/18"]after it had already[/URL] entered atmosphere
i'll be calcing his speed
S=D/T
first off the laser is LS (300000 km/s)
atmosphere goes up to about 20km
timeframe is thus 20/300000=0.00006666 seconds
now we need the distance koro sensei crossed

korosensei head=50 cm and 249px (his head looks to be the double of his army companions)
panel height is 362px
it is a close up so i will use 35/2 degrees
2 * atan(249/ (362/ tan(35/2 degrees))) 24.473243 degrees
or about 1.1762 meters
now we need to get the distance from the tree to the window
vP5BOI6.jpg

i'll assume this tree is 5 meters (228px) and the window is 1.5 meters (46px)
korosensei head is about 50 cm(55px)
panel height is 267px
so lets do it
2 * atan(228/ (267/ tan(70/2))) 44.057 degrees
so distance from the viewer and the tree is about 6.1789 meters
2 * atan(46/ (267/ tan(70/2))) 9.33352 degrees
so distance from the viewer to the window is 9.1877 meters
2 * atan(55/ (267/ tan(70/2))) 11.1490 degrees
and distance from the viewer to korosensei is
about 2.5635 meters
taking this out we have the distance from the tree to the window being formed by a triangle of 3.6154 and 6.6242 meters
D^2=6.6242^2-3.6154^2
D= 5.550 meters
which is the distance koro sensei crossed before the laser had arrived
S=5.550/0.00006666
S=83258.3258 m/s

Koro sensei speed=244.877 mach
which is like 10 times his old speed
cool

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