First time using Square-Cubic Law 
roll
Disclaimer: This was a request made by Tom Servo, I?m not aware of the verse and thus might be missing some context.
The feat by itself is quite straightforward
Jio flips a hugeass turtle with a kick
I will be calcing the rotational kinetic energy needed to perform such feat.
This will likely be a quite big calc and I doubt it will be worthy jackish, but meh.
Turtle Size
As you can see, The turtle is pretty big (not limb of beast big but, wathever)
To calc its length, I?ll be scalling it from this pillars width
according to satan wiki, this little girl called ruby is 1.55m
She is 13px
Pillar width is 23 px
Making it 2.74 meters.
now to the pillars
pillars width=13px=2.74
turtle length= 519px= 109.389230769 meters
Making the whole turtle roughly 109.39 meters Average Turtle volume
Total volume of an average sea turtle= 53799 cc
Overral Density of sea turtle=1.263964 g/cc
Mass of the Big Turtle
Now it is only a matter to get the Rotational kinetic energy
RKE=0.5*I*w^2
Where ?I? refers to moment of inertia and ?w? to angular speed
Moment of Inertia
I?ll be first using the moment of inertia of an sphere (will upload with the one of an ellipsoid if needed)
I=(2Mr^2)*0.2
I=(2*187567665 * 54.695^2) *0.2
I=224446695979 kg*m^2
Angular Speed
W= 2pi/T
I?ll first need a timeframe which will be get using freefall
H=0.5*g*t^2
I?ll assume g as 10m/s^2 and H as the turtle?s size (it did get flipped, after all)
109.39=0.5*10*t^2
T^2=109.39/5
Timeframe= 46.7739243596 seconds
Angular Speed=2pi/46.7739243596
Angular Speed=0.13433094172 rad/s
Rotacional Kinetic Energy of the Turtle
RKE=(2*I*w^2)*0.2
RKE=(2*224446695979*0.13433094172^2)*0.2
RKE=1620038466.72 joules
Or
Credits to cat, regi and Bang
rollDisclaimer: This was a request made by Tom Servo, I?m not aware of the verse and thus might be missing some context.
The feat by itself is quite straightforward
Jio flips a hugeass turtle with a kick
I will be calcing the rotational kinetic energy needed to perform such feat.
This will likely be a quite big calc and I doubt it will be worthy jackish, but meh.
Turtle Size
As you can see, The turtle is pretty big (
To calc its length, I?ll be scalling it from this pillars width
according to satan wiki, this little girl called ruby is 1.55m
She is 13px
Pillar width is 23 px
Making it 2.74 meters.
now to the pillars
pillars width=13px=2.74
turtle length= 519px= 109.389230769 meters
Making the whole turtle roughly 109.39 meters
i'm gonna base myself on a calc done by bang a while ago to get turtle's body proportions.
there?s no rock, so let?s assume 40% of her body is the shell and the remaining body parts will be low balled with human body proportions.
the proportions of human bodyaccording to this blog are 4/5 water and 1/5 carbon
making it 48% water and 12% of carbon.
according to this site adult sea turtles are around 78-112cm and weigth 68-186 kg
I?ll pick the smaller ones.
water density= 1g/cc
v=d*M
V=(48% x 68000)/1
Volume of water = 32640 cc
calcium density= 1.55g/cc
V=M/d
V= (40% x 68000)/ 1.55
Volume of calcium= 17548.387 cc
carbon= 2.26 g/cc
V= M/D
V=(12% x 68000)/ 2.26
Volume of carbon=3610.619
Overral Density of sea turtle= D=m/v
D=68000/53799
D= 1.263964 g/cc
there?s no rock, so let?s assume 40% of her body is the shell and the remaining body parts will be low balled with human body proportions.
the proportions of human bodyaccording to this blog are 4/5 water and 1/5 carbon
making it 48% water and 12% of carbon.
according to this site adult sea turtles are around 78-112cm and weigth 68-186 kg
I?ll pick the smaller ones.
water density= 1g/cc
v=d*M
V=(48% x 68000)/1
Volume of water = 32640 cc
calcium density= 1.55g/cc
V=M/d
V= (40% x 68000)/ 1.55
Volume of calcium= 17548.387 cc
carbon= 2.26 g/cc
V= M/D
V=(12% x 68000)/ 2.26
Volume of carbon=3610.619
Overral Density of sea turtle= D=m/v
D=68000/53799
D= 1.263964 g/cc
Overral Density of sea turtle=1.263964 g/cc
Mass of the Big Turtle
according to this site adult sea turtles are around 78-112cm and weigth 68-186 kg
i'll just pick the smaller one and apply in the square law
M2=(H2/H1)^3*M1
M2=(10939/78)^3*68
M2=187567665 kg
Or roughly 187567.665 tons.
i'll just pick the smaller one and apply in the square law
M2=(H2/H1)^3*M1
M2=(10939/78)^3*68
M2=187567665 kg
Or roughly 187567.665 tons.
RKE=0.5*I*w^2
Where ?I? refers to moment of inertia and ?w? to angular speed
Moment of Inertia
I?ll be first using the moment of inertia of an sphere (will upload with the one of an ellipsoid if needed)
I=(2Mr^2)*0.2
I=(2*187567665 * 54.695^2) *0.2
I=224446695979 kg*m^2
Angular Speed
W= 2pi/T
I?ll first need a timeframe which will be get using freefall
H=0.5*g*t^2
I?ll assume g as 10m/s^2 and H as the turtle?s size (it did get flipped, after all)
109.39=0.5*10*t^2
T^2=109.39/5
Timeframe= 46.7739243596 seconds
Angular Speed=2pi/46.7739243596
Angular Speed=0.13433094172 rad/s
Rotacional Kinetic Energy of the Turtle
RKE=(2*I*w^2)*0.2
RKE=(2*224446695979*0.13433094172^2)*0.2
RKE=1620038466.72 joules
Or
Solid Small building level
Credits to cat, regi and Bang
