reupdating this shit because i realised that this one is too different to just try bumping
Shouto vaporizes some ice
239.475526/60= 3.99125876667 tons of tnt for the vaping
421.37/1=421.37 tons of tnt for the freezing
so shoto kun was casually large building level and mcb+ by that time
Shouto vaporizes some ice
basically shouto oneshots poor fooder number 2 freezing half of the stadium they are in melting and vaping the whole thing shortly after
we know that he vaps because the ice quickly becomes vapor instead of just melting.
i'll be calcing the energy needed to perform such feat
Volume of the Ice
Mass=Density*Volume
ice density is 917 kg/m^3
M=3468.309372550955*917
M=3180439.69463 kg
we are by default assuming this ice sits at 0 celsius degrees
meaning that to fuse it we need just to use its fusion value
The heat of fusion of ice is 3.45e5 J/kg
Q=m*l*t
Fusion yeild=3180439.69463*3.45e5
FY=1.0972517e+12
the energy needed to heat water is 4.18 J/kg
we will be heating this 0 deegres ice till it arrives 100?C
Q=m*c*Δt
Heating yeild=3180439.69463*4.18*100
HY=1329423792.36 joules
now that the water is at 100 degrees we just need to apply its vaporization value
water vaporization value is 2.26e6 J/kg
Q=m*l*t
Vaporization yeild=3180439.69463*2.26e6
VY=7.1877937e+12
the total energy is the addition of the fusion yeild with the heating yeild and the vaporization yeild
TE=7.1877937e+12+1329423792.36+1.0972517e+12
TE=8.2863748e+12
Vaporization/melting
Freezing energy
NM=2848175.65464 kg
OM=989508.663261 kg
air temperature is 293 degrees kelvin
oxygen specific heat is 918 j/kgk
boiling temperature of oxygen is 90.2 k
OQ=989508.663261 x 918 x (293-90.2)
OQ=1.84217224e11 joules
Heat of vaporization of oxygen is 214000 j/kg
OV=989508.663261 x 214000
OV=2.11754854e+11
melting temperature of oxygen is 54,75 kelvin
OQ=989508.663261 x 918 x (90.2-54.75)
OQ=3.22016794e+10 joules
fusion energy of oxygen is 13875 j/kg
OS= 13875 x 989508.663261
OS=1.37294327e+10 joules
Oxygen freezing energy=441903190100 joules
boiling point of nitrogen is 77,36 K
nitrogen specific heat 1040 j/kg
NQ=2848175.65464 x 1040 x (293-77.36)
NQ=6.38747822e11 joules
nitrogen vaporization is 199000 j/kg
NV=199000 x 2848175.65464
NV=5.66786955e11
melting temperature of nitrogen is 63,15 kelvins
NQ=2848175.65464 x 1040 x (77.36-63,15)
NQ=4.20914791e10 joules
fusion of nitrogen is 25800 j/kg
NF=2848175.65464 x 25800
NF= 7.34829319e10 joules
Freezing energy is=1321109188000 joules
total energy is 1763012378100 joules
we know that he vaps because the ice quickly becomes vapor instead of just melting.
i'll be calcing the energy needed to perform such feat
Volume of the Ice
we sadly only have half shots of the ice one from inside the colliseum and the other from the outside.
i'll assume the second one starts right after the first one (a safe assumption considering how we can still see the dome above the ice in the first panel.
according to the wiki hanta is 177cm
so his head is 23.6cm
his head is 7px
meanwhile the ice length is 516px and the first part of the ice heigth is 543px making:
Ice length=17.3965714286 m
first part of the ice heigth=18.3068571429 m
now for the second part
Ice widety=7.26081184211 m
second part of the ice heigth=16.6537608553m
Total ice heigth=34.9606179982 m
plugging these values on a elliptical cylinder calculator we get
i'll assume the second one starts right after the first one (a safe assumption considering how we can still see the dome above the ice in the first panel.
according to the wiki hanta is 177cm
so his head is 23.6cm
his head is 7px
meanwhile the ice length is 516px and the first part of the ice heigth is 543px making:
Ice length=17.3965714286 m
first part of the ice heigth=18.3068571429 m
now for the second part
for this one i'll assume the size of the line that byssects the dome is equal either inside or outside
according to the wiki maiku's heigth is 185 cm but considering how his hair is actually bigger than his head i'll just add half a head and halve this by 8. instead of 7.5
making his head 23.125 cm
his head is 10 px
the line is 31px
making the line 71.6875 cm
here the line is 19px
meanwhile the ice widety is 192.44px and the heigth of the second part is 441.39px
making them
according to the wiki maiku's heigth is 185 cm but considering how his hair is actually bigger than his head i'll just add half a head and halve this by 8. instead of 7.5
making his head 23.125 cm
his head is 10 px
the line is 31px
making the line 71.6875 cm
here the line is 19px
meanwhile the ice widety is 192.44px and the heigth of the second part is 441.39px
making them
second part of the ice heigth=16.6537608553m
Total ice heigth=34.9606179982 m
plugging these values on a elliptical cylinder calculator we get
Energy
Mass=Density*Volume
i
M=3468.309372550955*917
M=3180439.69463 kg
we are by default assuming this ice sits at 0 celsius degrees
meaning that to fuse it we need just to use its fusion value
The heat of fusion of ice is 3.45e5 J/kg
Q=m*l*t
Fusion yeild=3180439.69463*3.45e5
FY=1.0972517e+12
the energy needed to heat water is 4.18 J/kg
we will be heating this 0 deegres ice till it arrives 100?C
Q=m*c*Δt
Heating yeild=3180439.69463*4.18*100
HY=1329423792.36 joules
now that the water is at 100 degrees we just need to apply its vaporization value
water vaporization value is 2.26e6 J/kg
Q=m*l*t
Vaporization yeild=3180439.69463*2.26e6
VY=7.1877937e+12
the total energy is the addition of the fusion yeild with the heating yeild and the vaporization yeild
TE=7.1877937e+12+1329423792.36+1.0972517e+12
TE=8.2863748e+12
Vaporization/melting
air is 80% nitrogen and 20% oxygen
frozen nitrogen density is 1026.5 kg/m^3
density of solid oxygen is 1426 kg/m^3
NM=3468.30937*1026.5 x 0.8
NM=2848175.65464 kg
OM=3468.30937*1426.5 x 0.2
OM=989508.663261kg
we are by default assuming this ice sits at 54,75 kelvin
which is oxygen melting point
The heat of fusion of oxygen is 13875 J/kg
Q=m*l*t
Fusion yeild1=989508.663261*13875
FYO=13729432702.7 joules
the energy needed to heat liquid nitrogen is 920 J/kgk
we will be heating this 90.18k ice till it arrives 90,18k
Q=m*c*Δt
Heating yeild=989508.663261*920*35.43
HYO=32253628584.2 joules
now that the oxygen is at 52.75k we just need to apply its vaporization value
oxygen vaporization value is 213000 J/kg
Q=m*l
Vaporization yeild=213000*989508.663261
VY=210765345275 joules
now we will deal with nytrogen
specific heat of nitrogen is 1040 j/kgk
nitrogen melting point is at 63k
HYN1=8.25 x 1040 x 2848175.65464
HYN1=24437347116.8 joules
heat of fusion of nytrogen is 25800 j/kg
FYN=25800 x 2848175.65464
FYN=73482931889.7 joules
now i just need to heat the nytrogen until it reaches 77.2 k
HNY=14.2 x 2848175.65464 x 1040
HNY=42061858067.7 joules
now it is time for nytrogen vaporization (199000)
VYN=2848175.65464 x 199000
VYN=566786955273 joules
and then we just put it at the same temperature as oxygen (90.18k)
HNY3=12.98 x 2848175.65464 x 1040
HNY3=38448092797.1 joules
TE= 1.0019656e+12 joules
frozen nitrogen density is 1026.5 kg/m^3
density of solid oxygen is 1426 kg/m^3
NM=3468.30937*1026.5 x 0.8
NM=2848175.65464 kg
OM=3468.30937*1426.5 x 0.2
OM=989508.663261kg
we are by default assuming this ice sits at 54,75 kelvin
which is oxygen melting point
The heat of fusion of oxygen is 13875 J/kg
Q=m*l*t
Fusion yeild1=989508.663261*13875
FYO=13729432702.7 joules
the energy needed to heat liquid nitrogen is 920 J/kgk
we will be heating this 90.18k ice till it arrives 90,18k
Q=m*c*Δt
Heating yeild=989508.663261*920*35.43
HYO=32253628584.2 joules
now that the oxygen is at 52.75k we just need to apply its vaporization value
oxygen vaporization value is 213000 J/kg
Q=m*l
Vaporization yeild=213000*989508.663261
VY=210765345275 joules
now we will deal with nytrogen
specific heat of nitrogen is 1040 j/kgk
nitrogen melting point is at 63k
HYN1=8.25 x 1040 x 2848175.65464
HYN1=24437347116.8 joules
heat of fusion of nytrogen is 25800 j/kg
FYN=25800 x 2848175.65464
FYN=73482931889.7 joules
now i just need to heat the nytrogen until it reaches 77.2 k
HNY=14.2 x 2848175.65464 x 1040
HNY=42061858067.7 joules
now it is time for nytrogen vaporization (199000)
VYN=2848175.65464 x 199000
VYN=566786955273 joules
and then we just put it at the same temperature as oxygen (90.18k)
HNY3=12.98 x 2848175.65464 x 1040
HNY3=38448092797.1 joules
TE= 1.0019656e+12 joules
NM=2848175.65464 kg
OM=989508.663261 kg
air temperature is 293 degrees kelvin
oxygen specific heat is 918 j/kgk
boiling temperature of oxygen is 90.2 k
OQ=989508.663261 x 918 x (293-90.2)
OQ=1.84217224e11 joules
Heat of vaporization of oxygen is 214000 j/kg
OV=989508.663261 x 214000
OV=2.11754854e+11
melting temperature of oxygen is 54,75 kelvin
OQ=989508.663261 x 918 x (90.2-54.75)
OQ=3.22016794e+10 joules
fusion energy of oxygen is 13875 j/kg
OS= 13875 x 989508.663261
OS=1.37294327e+10 joules
Oxygen freezing energy=441903190100 joules
boiling point of nitrogen is 77,36 K
nitrogen specific heat 1040 j/kg
NQ=2848175.65464 x 1040 x (293-77.36)
NQ=6.38747822e11 joules
nitrogen vaporization is 199000 j/kg
NV=199000 x 2848175.65464
NV=5.66786955e11
melting temperature of nitrogen is 63,15 kelvins
NQ=2848175.65464 x 1040 x (77.36-63,15)
NQ=4.20914791e10 joules
fusion of nitrogen is 25800 j/kg
NF=2848175.65464 x 25800
NF= 7.34829319e10 joules
Freezing energy is=1321109188000 joules
total energy is 1763012378100 joules
it took him a while to deal with the whole thing but nothing too slow because our random mook didn't die from hyportemia or anything like this so lets say 60 seconds
239.475526/60= 3.99125876667 tons of tnt for the vaping
421.37/1=421.37 tons of tnt for the freezing
so shoto kun was casually large building level and mcb+ by that time
