Trigger-verse calc archive

Stocking Anarchy · Feb 7, 2022

Recalcing an old calc that the images are unfortunately no longer with us for.

Dai-Gunkai explodes, causing a colossal explosion that Dai-Gurren, Gurren Lagann, Team Dai-Gurren and Viral all survive. Dai-Gurren is 293.076316m long.

21 pixels = 293.076316m
1 pixel = 293.076316m/21 = 13.956015m
13.956015m X 1107 = 15449.3086m
15449.3086m/2 = 7724.6543m
13.956015m X 656 = 9155.14584m
13.956015m X 461 = 6433.72292m
13.956015m X 1470 = 20515.342m
20515.342m/2 = 10257.671m
13.956015m X 1361 = 18994.1364m

The cap and the column overlap a bit, but given there's more to the cap cut off above, it should balance out. Volume as an ellipsoid for the top part and a cylinder for the bottom part.

V = 4/3πabc
= 4/3 X π X 6433.72292 X 10257.671 X 10257.671
= 2.83562302e12m^3

V = πr^2h
= π X 7724.6543^2 X 9155.14584
= 1.71622113e12m^3

As for the mass, for the vaporous looking cap we'll use the mass of air (1.003kg/m^3) and the mass of the column as water (1000kg/m^3).

M = 2.83562302e12 X 1.003
= 2844129889060kg

M = 1.71622113e12 X 1000
= 1.71622113e15kg

M = 2844129889060kg + 1.71622113e15kg
= 1.71906526e15kg

Next we need the timeframe.

Timeframe is 7 seconds and 15 frames.

T = 1s/24
= 41.6666667ms X 15
= 0.625000001 + 7
= 18994.1364m/7.62500s
= 2491.03428m/s

Finally, we'll get our kinetic energy.

KE = (0.5)mv^2
= (0.5) X 1.71906526e15 X 2491.03428^2
= 5.33361639e21 joules
= 1.2747649115678776344 teratons

Final Results
Dai-Gunkai explodes = 1.275 teratons

Stocking Anarchy · Feb 7, 2022

Because the website that hosted the images in the old calc crashed, unfortunately, and there are a few calcs I want up again for future use, which relate to just how enormous the final muganns are. Arc Gurren is roughly 5km long, or 5000m.

(Rough translation)

We'll start with the blue one...

101 pixels = 5000m
1 pixel = 5000m/101 = 49.5049505m
49.5049505m X 16 = 792.079208m

8 pixels = 792.079208m
1 pixel = 792.079208m/8 = 99.009901m
99.009901m X 7 = 693.069307m
99.009901m X 78 = 7722.77228m
99.009901m X 4 = 396.039604m
99.009901m X 286 = 28316.8317m
99.009901m X 12 = 1188.11881m
99.009901m X 40 = 3960.39604m
99.009901m X 21 = 2079.20792m

Volume of the top segments as trapezoidal prisms.

V = LH(A + B)/2
= 7722.77228 X 1188.11881 (396.039604 + 792.079208)/2
= 5.45083426e9m^3

Volume of the lower ones also, as trapezoidal prisms.

V = LH(A + B)/2
= 28316.8317 X 693.069307 (2079.20792 + 3960.39604)/2
= 5.92652051e10m^3

= 8.6607698e11m^3

Next for the purple one.

99.009901m X 99 = 9801.9802m
99.009901m X 13 = 1287.12871m
99.009901m X 16 = 1584.15842m
99.009901m X 200 = 19801.9802m
99.009901m X 14 = 1386.13861m
99.009901m X 9 = 891.089109m

Once again, volumes of the top parts are trapezoidal prisms, but given it's a trapezoidal prism on both sides, times by two.

V = LH(A + B)/2
= 9801.9802 X 891.089109 (1287.12871 + 1584.15842)/2
= 1.25395394e10m^3

Volume of the bottom segments as rectangles, assuming they're as thick as the ones the blue mugann is comprised of.

V = lhw
= 1386.13861 X 19801.9802 X 693.069307
= 1.90235669e10 X 2
= 38047133800m^3
Because the website that hosted the images in the old calc crashed, unfortunately, and there are a few calcs I want up again for future use, which relate to just how enormous the final muganns are. Arc Gurren is roughly 5km long, or 5000m.

(Rough translation)

We'll start with the blue one...

101 pixels = 5000m
1 pixel = 5000m/101 = 49.5049505m
49.5049505m X 16 = 792.079208m

8 pixels = 792.079208m
1 pixel = 792.079208m/8 = 99.009901m
99.009901m X 7 = 693.069307m
99.009901m X 78 = 7722.77228m
99.009901m X 4 = 396.039604m
99.009901m X 286 = 28316.8317m
99.009901m X 12 = 1188.11881m
99.009901m X 40 = 3960.39604m

Volume of the top segments as trapezoidal prisms.

V = LH(A + B)/2
= 7722.77228 X 1188.11881 (396.039604 + 792.079208)/2
= 5.45083426e9m^3

Volume of the lower ones as rectangular prisms.

V = lhw
= 3960.39604 X 28316.831 X 7722.77228
= 8.6607698e11m^3

Next for the purple one.

99.009901m X 99 = 9801.9802m
99.009901m X 13 = 1287.12871m
99.009901m X 16 = 1584.15842m
99.009901m X 200 = 19801.9802m
99.009901m X 14 = 1386.13861m
99.009901m X 9 = 891.089109m

Once again, volumes of the top parts are trapezoidal prisms, but given it's a trapezoidal prism on both sides, times by two.

V = LH(A + B)/2
= 9801.9802 X 891.089109 (1287.12871 + 1584.15842)/2
= 1.25395394e10m^3

Volume of the bottom segments as rectangles, assuming they're as thick as the ones the blue mugann is comprised of.

V = lhw
= 1386.13861 X 19801.9802 X 693.069307
= 1.90235669e10 X 2
= 38047133800m^3

Not going to bother with the antannae on top. Now we have the volume of each component block, how many blocks?

99.009901m X 59 = 5841.58416m

The blue one has 18 rectangular blocks, while there are 18 trapezoidal blocks, so that can stay the same. Meanwhile the pink one has at least 11 to the middle of rectangular blocks, while there are 14 to the middle trapezoidal blocks on the top. That should cover half the blue trapezoidal blocks, so we'll times that by 2; as well as a quarter of the purple rectangular blocks, so we'll times that by 4; and a quarter of one of two layers of the purple trapezoidal blocks, or an eighth, so we'll times that by 8. First the blue mugann...

V = 5.92652051e10 X 18
= 1066773691800m^3

V = 5.45083426e9 X 18
= 98115016680 X 2
= 196230033360m^3

V = 1066773691800 + 196230033360
= 1263003725160m^3

...Then the purple mugann.

V = 38047133800 X 11
= 418518471800 X 4
= 1674073887200m^3

V = 1.25395394e10 X 14
= 175553551600 X 8
= 1404428412800m^3

V = 1674073887200 + 1404428412800
= 3078502300000m^3

The component parts of the giant muganns are dense enough to smash apart grapearls by crashing into them...
...so they would be pretty dense. We'll use aluminium for our low end (which weighs 2600kg/m^3) and steel for a high end (which weighs 7850kg/m^3). Once again we'll start with the blue mugann...

(Low end)
M = 1263003725160 X 2600kg
= 3.28380969e15kg

(High end)
M = 1263003725160 X 7850kg
= 9.91457924e15kg

...then have the purple one...

(Low end)
M = 3078502300000 X 2600kg
= 8.00410598e15kg

(High end)
M = 3078502300000 X 7850kg
= 2.41662431e16kg

...and finally, we'll do the final mugann, that's both of the giant muganns combined together.

(Low end)
M = 3.28380969e15kg + 8.00410598e15kg
= 1.12879157e16kg

(High end)
M = 9.91457924e15kg + 2.41662431e16kg
= 3.40808223e16kg

To finish off, let's get the total height of the giant muganns.

99.009901m X 378 = 37425.7426m (37.4257426km)
99.009901m X 322 = 31881.1881m (31.8811881km)

Final Drill states the giant muganns are several dozen kilometers in size...

(Box on the upper right page)

...so this is pretty consistent with that. To finish off, let's also get the size of the final mugann.

90 pixels = 5841.58416m
1 pixel = 5841.58416m/90 = 64.9064907m
64.9064907m X 849 = 55105.6106m (55.1056106km)

Final Results
Arc Gurren's length = 5km
Giant Blue Mugann's mass (low end) = 3.28380969e15kg
Giant Blue Mugann's mass (high end) = 9.91457924e15kg
Giant Purple Mugann's mass (low end) = 8.00410598e15kg
Giant Purple Mugann's mass (high end) = 2.41662431e16kg
Final Mugann mass (low end) = 1.12879157e16kg
Final Mugann's mass (high end) = 3.40808223e16kg
Giant Blue Mugann height = 37.426km
Giant Purple Mugann height = 31.881km
Final Mugann's length = 55.106km

Stocking Anarchy · Feb 7, 2022

Having gotten the values for size and mass for the Giant Muganns again (or Kyo Muganns) previously, now we're just left with the easy part.

1. Gurren Lagann blasts a giant mugann

Gurren Lagann blasts the blue giant mugann, pushing it away from Arc Gurren noticably The bottom of the Mugann's end segments are 3960.39604m wide.

[/SPOLER]

= 2*atan(125/(570/tan(70/2)))
= 0.207070388 rad
= 11.8642592945658372 degrees

Put that through the angscaler, and the Kyo Mugann is currently 19057m away.
[SPOLER]

Timeframe is 3 seconds and 5 frames.

T = 1s/24
= 41.6666667ms X 5
= 0.208333333s + 3s
= 3.20833333s

= 2*atan(89/(570/tan(70/2)))
= 0.147694129 rad
= 8.46225025058173053 degrees

Now the Blue Kyo Mugann is 26766m away.

L = 26766m - 19057m
= 7709m

T = 7709m/3.20833333s
= 2402.8052m/s

The Blue Kyo Mugann has a low end mass of 3.28380969e15kg and a high end mass of 9.91457924e15kg.

(Low end)
KE = (0.5)mv^2
= (0.5) X 3.28380969e15 X 2402.8052^2
= 9.47949301e21 joules
= 2.2656532050669220268 teratons

(High end)
KE = (0.5)mv^2
= (0.5) X 9.91457924e15 X 2402.8052^2
= 2.86207769e22 joules
= 6.840529851816444129 teratons

2. Gurren Lagann drags Giant Mugann

Gurren Lagann is trapped by the Giant Purple Mugann, but just drags it behind it and crashes into Arc Gurren, igniting their combination into Arc Gurren Lagann. The Giant Blue Mugann's lower segments are 28316.8317m long.

Timeframe is 16 frames.

T = 1s/24
= 41.6666667ms X 16
= 0.666666667s

56 pixels = 28316.8317m
1 pixel = 28316.8317m/56 = 505.657709m
505.657709m X 49 = 24777.2277m

Let's get the speed.

T = 24777.2277m/0.666666667s
= 37165.8415/340.29
= Mach 109.218142

Now for the kinetic energy. The Giant Purple Mugann has a low end mass of 8.00410598e15kg and a high end mass of 2.41662431e16kg.

(Low end)
KE = (0.5)mv^2
= (0.5) X 8.00410598e15 X 37165.8415^2
= 5.52803489e24 joules
= 1.321232048279158855 petatons

(High end)
KE = (0.5)mv^2
= (0.5) X 2.41662431e16 X 37165.8415^2
= 1.66904131e25 joules
= 3.9891044694072657073 petatons

3. Final Mugann flies towards Arc Gurren Lagann

The Final Mugann flies towards Arc Gurren Lagann, who halts it and matches it's power for several seconds. Though it doesn't look like much, keep in mind just how massive the Final Mugann is. Given it moves in a straight line, this is more or less straightforward. The Final Mugann is 55105.6106m.

The timeframe is 2 seconds and 20 frames.

T = 1s/24
= 41.6666667ms X 20
= 0.833333334s + 2s
= 2.83333333s

Next to find the distance it travelled in the timespan.

65 pixels = 55105.6106m
1 pixel = 55105.6106m/65 = 847.778625m
324 - 184 = 140
847.778625m X 140 = 118689.008m

T = 118689.008m/2.83333333s
= 41890.2382/340.29
= Mach 123.101585

Then we get out kinetic energy. The Final Mugann has a low end mass of 1.12879157e16kg and a high end mass of 3.40808223e16kg.

(Low end)
KE = (0.5)mv^2
= (0.5) X 1.12879157e16 X 41890.2382^2
= 9.9039724e24 joules
= 2.3671062141491399089 petatons

(High end)
KE = (0.5)mv^2
= (0.5) X 3.40808223e16 X 41890.2382^2
= 2.99023781e25 joules
= 7.1468398900573610888 petatons

4. Final Mugann's mass energy
This is the greatest, yet easiest one. As noted by Leeron and Rossiu, when defeated, mugann's turn into energy and explode.

And something as big and heavy as the Final Mugann would create an immense amount of energy.

(Low end)
E = mc^2
= 1.12879157e16 X 299792458^2
= 1.01450727e33 joules
= 242.47305688336521712 zettatons

(High end)
E = mc^2
= 3.40808223e16 X 299792458^2
= 3.06303155e33 joules
= 732.08211042065011043 zettatons

Final Results
Gurren Lagann blasts Giant Mugann (low end) = 2.266 teratons
Gurren Lagann blasts Giant Mugann (high end) = 6.841 teratons
Gurren Lagann slams into Arc Gurren = Mach 109.218
Gurren Lagann drags Giant Mugann (low end) = 1.321 petatons
Gurren Lagann drags Giant Mugann (high end) = 3.989 petatons
Final Mugann flight speed = Mach 123.102
Final Mugann's kinetic energy (low end) = 2.367 petatons
Final Mugann's kinetic energy (high end) = 7.147 petatons
Final Muganns mass energy (low end) = 242.473 zettatons
Final Mugann's mass energy (high end) = 732.082 zettatons

Stocking Anarchy · Feb 7, 2022

An infamous feat, but I feel justified in giving it a calc (especially given the events of Kill La Kill If and all the cosmic shenanigans within). Let's go!

Ryuko and Ragyo fight across space, passing by different celestial bodies as they go. There was a lot of controversy over the past due to Kill La Kills wonky visuals, and that said visuals might not actually be a proper portrayal or not of what is happening. However, it should be noted to the contrary, that most of the wonky visuals in Kill La Kill have outright been directly noted to be canon. Gamagoori changing size is due to his emotions...

AnimeNEXT 2014 PART 2

Find out what you missed at AnimeNEXT 2014 including never before released content for Kill La Kill and details on the upcoming Kill La Kill OVA and much more!

web.archive.org

Kill La Kill If's glossary directly makes reference to Bunny Boy, a character who only appears in Mako's zany moments, and whom Mako keeps inside her.

Satsuki, Ragyo & Goku Uniforms being noted to shine and emit light.

Nui's multiple 4th wall breaks.

As such, I believe it's fair to say that if all of the other visuals are explicitly canon, so should this be too. However, even if the visuals are canon, it could still be troublesome finding a way to actually quantify it. Thankfully though, I've found a way. Take note of Ragyo's dialogue during this sequence.

Ragyo tells Ryuko to look at the shining Sun. The thing is though, the fight is taking place at night. When Ryuko blasts off into space it's night time, and when she falls back to Earth the Sun is only just beginning to rise. Even as Ryuko uses the Absolute Life Fiber Domination ability to save the world, the Sun is still not visible from Japan's side of the world, and only rises when Ryuko has fallen back down to Earth.

As such, Ragyo and Ryuko would have had to have moved a distance to allow the Sun to be visible during their fight. As such, we can confirm that they did indeed move during the fight. We'll go with a low end using the distance to the Sun, and a high end of the distance to one of the galaxies. The diameter of the Sun is 1391000km.

= 2*atan(1231/(1433/tan(70/2)))
= 0.773094324 rad
= 44.2950419308293064 degrees

Put that through the angscaler and we have a distance of 1708700km. The distance from the Earth to the Sun is 149,597,870km.

L = 149,597,870km - 1708700km
= 147889170km

Next for our timeframe.

Timeframe is 19 frames.

T = 1s/24
= 41.6666667ms X 19
= 0.791666667s

Let's get our speed.

T = 149,597,870km/0.791666667s
= 1.8896573e11/299792458
= 630.321828 C

Now for our high end using a galaxy. I can't find reference for a galaxy with an Active Galactic Nucleus like we see, so I will just go with the Andromedra Galaxy for now, as it's the closest major galaxy to the Milky Way. The Andromeda Galaxy has a diameter of 220,000 lightyears.

= 2*atan(1976/(1433/tan(70/2)))
= 1.15746043 rad
= 66.31759759256 degrees

Once again using the angscaler, we get a distance of 16836 lightyears. The distance to the Andromeda Galaxy from Earth is 2,500,000 lightyears.

L = 2,500,000 - 16,836
= 2483164 LY

The timeframe is 9 seconds and 12 frames.

T = 41.6666667ms X 12
= 0.5s + 9s
= 9.5s

T = 2483164LY/9.5s
= 2.47284669e21/299792458
= 8248528690000 C

Finally, let's also go for a result using the other galaxies we see (once again using Andromeda for scale).

= 2*atan(1094/(1433/tan(70/2)))
= 0.694165361 rad
= 39.7727454695738558 degrees

Using the angscaler one last time, we get a distance of 30410 lightyears to the galaxy.

L = 2,500,0000LY - 30,410LY
= 24969590LY

Let's get our timeframe one last time.

Timeframe is 3 seconds and 12 seconds

T = 3s + 0.5s
= 3.5s

T = 24969590LY/3.5s
= 6.74930044e22/299792458
= 225132429000000 C

Final Results
Ryuko & Ragyo fight across space (low end) = 630.322 C
Ryuko & Ragyo fight across space (mid end) = 8248528690000 C
Ryuko & Ragyo fight across space (high end) = 225132429000000 C

Stocking Anarchy · Feb 7, 2022

Honnouji Academy is huge, and there are several feats in which it's size is of relevance for scaling purposes. It's hard to know where to start from, but if in doubt, go by it's first appearence when Gamagoori threw Suzuki across it. Thankfully, we have an official height chart (of sorts, though it doesn't list the official heights).

Thankfully, some kind stranger has calced the heights, with Gamagoori's smallest form being 230cm (or 2.3m) tall.

With that, we can scale the diameter of the Honnouji Academy grounds.

10 pixels = 2.3m
1 pixel = 2.3m/10 = 0.23m
0.23m X 1784 = 410.32m

Now we have the width of the area, let's also get the height of Honnouji Academy (there's also the walls to take into account, but eh).

56 pixels = 410.32m
1 pixel = 410.32m/56 = 7.32714286m
7.32714286m X 414 = 3033.43714m (3.03343714km)

Final Results
Honnouji Academy height = 3.033km

Stocking Anarchy · Feb 7, 2022

Satsuki and Berserker Ryuko clash, creating a huge explosion. In a previous calc, I put Honnouji Academy's grounds at being 410.32m in diameter.

1997 pixels = 410.32m
1 pixel = 410.32m/1997 = 0.205468202m
0.205468202m X 1010 = 207.522884m
0.205468202m X 1068 = 219.44004m
219.44004m/2 = 109.72002m

Volume as a cylinder.

V = πr^2h
= π X 109.72002^2 X 219.44004
= 8299224.31m^3

Density of air is 1.003kg/m^3.

M = 8299224.31 X 1.003
= 8324121.98kg

Finally, we just need two things. Firstly, a timeframe...

Timeframe is 21 frames.

T = 1s/24
= 41.6666667ms X 21
= 0.875000001s

T = 207.522884m/0.875000001s
= 237.16901m/s

...Secondly, kinetic energy.
KE = (0.5)mv^2
= (0.5) X 8324121.98 X 237.16901^2
= 2.34112348e11 joules
= 55.9541940726577 tons of TNT

Final Results
Satsuki & Berserker Ryuko clash = 55.954 tons of TNT

Stocking Anarchy · Feb 7, 2022

Ryuko and Satsuki chase after Ragyo at great speeds. This will more or less be straight forward. Go off the official height chart...

...and the unofficial scaling...

...Ryuko is estimated to be around 164cm tall (or 1.64m).

32 pixels = 1.64m
1 pixel = 1.64m/32 = 0.05125m

Timeframe is 2 frames.

0.05125m X 492 = 25.21500m

T = 1s/24
= 41.6666667ms X 2
= 83.3333334ms

T = 25.21500m/83.3333334ms
= 302.58m/s

Final Results
Ryuko & Satsuki fly after Ragyo = 302.58m/s

Stocking Anarchy · Feb 7, 2022

Nui slashes at Ryuko, who redirects the attack into the sea, where it creates a colossal water plume. Firstly, how wide is the bridge of the S. S. Naked Sun? Once again, we'll use the offical height scale, and the unofficial scaling from it.

We'll use Uzu, who as per the above is 195cm tall.

215 pixels = 195cm
1 pixel = 195cm/215 = 0.906976744cm
0.906976744cm X 793 =719.232558cm (7.19232558m)

79 pixels = 7.19232558m
1 pixel = 7.19232558m/79 = 0.0910420959m
0.0910420959m X 517 = 47.0687636m

With all that done, we can finally get to the dimensions of the explosion.

458 pixels = 47.0687636m
1 pixel = 47.0687636m/458 = 0.102770226m
0.102770226m X 971 = 99.7898894m
0.102770226m X 239 = 24.562084m
0.102770226m X 1205 = 123.838122m
0.102770226m X 201 = 20.6568154m
20.6568154m/2 = 10.3284077m
0.102770226m X 485 = 49.8435596m
49.8435596m/2 = 24.9217798m

Volume of the top part as a cone and the bottom part as a conical frustrum.

V = πr^2/h^3
= π X 10.3284077^2 X 24.562084/3
= 2743.85133m^3

V = (1/3)π(r^2+rR+R^2)h
= (1/3) X π X (10.3284077^2 + 10.3284077 X 24.9217798 + 24.9217798^2) X 99.7898894
= 102950.354m^3

V = 2743.85133 + 102950.354
= 105694.205m^3

Water weighs 1000kg/m^3.

M = 105694.205 X 1000kg
= 105694205kg

We have the mass, so what's the speed?

16 frames.

T = 1s/24
= 41.6666667ms X 16
= 0.666666667s

T = 123.838122m/0.666666667s
= 185.757183m/s

KE = (0.5)mv^2
= (0.5) X 105694205 X 185.757183^2
= 1.8235279e12 joules
= 435.8336281070746 tons of TNT

Final Results
Ryuko deflects Nui's slice attack = 435.834 tons of TNT

Stocking Anarchy · Feb 7, 2022

This calc has been done by others, on this site and elsewhere, but I myself want to look over it...

Ryuko bursts through the Celestial Genesis Cocoon Planet's covering, creating a series of colossal holes in it (the cocoon is not one single layer, but multiple). How wide is the Celestial Genesis Cocoon Planet, and what's the distance between it and the Earth? Let's find our answer from the radius of the Earth.

$ac6b6294509876e4bb09d25bebf54ea34afde11c$

R = (h/2) + c^2/(8h)
= (170/2) + 811^2/(8 X 170)
= 568.618382 pixels

The radius of the Earth is 6,371km.

568.618382 pixels = 6,371km
1 pixel = 6,371km/568.618382 = 11.2043511km
11.2043511km X 25 = 280.108777km
11.2043511km X 1226 = 13736.5344km

Now we have the size of the Cocoon, we can scale the size of the hole.

3658 pixels = 13736.5344km
1 pixel = 13736.5344km/3658 = 3.7552035km
3.7552035km X 535 = 2009.03387km (2009033.87m)
3.7552035km X 320 = 1201.66512km
3.7552035km X 110 = 413.072385km

Let's get the distance to the Earth (for later).

= 2*atan(3658/(813/tan(70/2)))
= 2.26439376 rad
= 129.74020560408127 degrees

Put that through the angscaler and we have a distance of 3221.7km. Next for the thickness. Thankfully, there's a way to directly scale from the sheets of the cocoon.

3298 pixels = 2009.03387km
1 pixel = 2009.03387km/3298 = 0.609167335km
0.609167335km X 14 = 8.52834269km (8528.34269m)

Let's work out the volume of the area parted, going from each segment of the cocoon.

557 pixels = 1201.66512km (1201665.12m)
1 pixel = 1201665.12m/557 = 2157.38801m
2157.38801m X 629 = 1356997.06m
2157.38801m X 678 = 1462709.07m
2157.38801m X 767 = 1654716.6m
2157.38801m X 848 = 1829465.03m

Volume of each part as a cylinder.

R = 2009033.87m/2
= 1004516.94m

V = πr^2h
= π X 1004516.94^2 X 8528.34269
= 2.70351663e16m^3

R = 1201665.12m/2
= 600832.56m

V = πr^2h
= π X 600832.56^2 X 8528.34269
= 9.67211463e15m^3

R = 1356997.06m/2
= 678498.53m

V = πr^2h
= π X 678498.53^2 X 8528.34269
= 1.23342384e16m^3

R = 1462709.07m/2
= 731354.535m

V = πr^2h
= π X 731354.535^2 X 8528.34269
= 1.43307999e16m^3

R = 1654716.6m/2
= 827358.3m

V = πr^2h
= π X 827358.3^2 X 8528.34269
= 1.83401031e16m^3

R = 1829465.03m/2
= 914732.515m

V = πr^2h
= π X 914732.515^2 X 8528.34269
= 2.24183038e16m^3

V = 2.70351663e16 + 9.67211463e15 + 1.23342384e16 + 1.43307999e16 + 1.83401031e16 + 2.24183038e16
= 1.04130726e17m^3
= 1.04130726000000005e+23cm^3

The mass of Life Fibers is unknown, so I'll be using the density of silk fabric/fibre, that being 1.31g/cm^3.

M = 1.04130726000000005e+23 X 1.31g
= 1.36411251e23g
= 1.36411251000000004e+20kg

So all that's done, let's get the kinetic energy, from when right before Ryuko hits the Cocoon until we first see the hole.

11 seconds and 19 frames is our timeframe.

T = 1s/24
= 41.6666667ms X 19
= 0.791666667s + 11s
= 11.7916667s

T = 1004516.94m/11.7916667s
= 85188.7155m/s

At long last, let's get our kinetic energy!

KE = (0.5)mv^2
= (0.5) X 1.36411251000000004e+20 X 85188.7155^2
= 4.94976221e29 joules
= 118.30215607074569562 exatons

While we're at it, let's also get the speed Ryuko flies into space.

21 seconds and 12 frames.

T = 41.6666667ms X 12
= 0.5s + 21s
= 21.5s

The distance to the cocoon is 3221.7km, and given the extra distance from the cocoon to Earth being 280.108777km, that gives us a total distance of 3501.80878km.

T = 3501.80878km/21.5s
= 162874.827/340.29
= Mach 478.635361

Final Results
Ryuko parts cocoon = 118.302 exatons
Ryuko flies into space = Mach 478.635

Stocking Anarchy · Feb 7, 2022

First off, this serves as a high end to Tacocats calc, which still serves as a good low end.

The Cocoon Star Navity explodes, destroying the planet. Thing is?

The Original Life Fiber has survived being on planets that have been destroyed by Lifefiber Cocoons. Ergo, it would have an incredible endurance. So let's up and go find the energy of the Cocoon Star Navity destroying the Earth, according to the simulation. The diameter of the Earth is 12742km.

Timeframe is 10 seconds and 1 frame.

T = 1s/24
= 41.6666667ms + 10s
= 10.0416667s

Next to find the distance the mass of the Earth travelled, from its core.

354 pixels = 12742km
12742km/2 = 6371km
1 pixel = 12742km/354 = 35.9943503km
35.9943503km X 330 = 11878.1356km
11878.1356km + 6371km = 18249.1356km

T = 18249.1356km/10.0416667s
= 1817341.3m/s

Next up we need our kinetic energy of the planet exploding. The Earth has a mass of 5.9736 X 10^24kg (or 5.9736e24kg).

KE = (0.5)mv^2
= (0.5) X 5.9736e24 X 1817341.3^2
= 9.86459217e36 joules
= 2.3576941132887186541 ninatons

To find the durability of the Original Lifefiber, we'll need the surface area of the Earth that being 5.1 x 10^8km^2 (or 510000000km^2, otherwise 5.1e+14m^2). Using the values given in Tacocats calc for the Surface area of the Original Lifefiber, that being 410289.485m^3. We'll find our energy with inverse law.

E = (410289.485/5.1e+14) X 9.86459217e36
= 7.93595773e27 joules
= 1.8967394192160613784 exotons

Final results
Hypothetical detonation of the Cocoon Star Navity = 2.358 ninatons
Hypothetical durability of the Original Lifefiber = 1.897 exotons

The original calc is still good as a low end (with 38 teratons to 47 teratons for the Original Life Fibers durability and 57.3 zettatons for the Cocoon Star Navity). It's durability is, however, consistent with Ryuko creating a huge hole in the Cocoon Star Navity.

Stocking Anarchy · Feb 7, 2022

Kill La Kill has an insane speed feat in the second episode alone.

1:37

Ryuko cuts many tennis balls into string. The diameter of a tennis ball is between 6.54cm to 6.86cm, or an average of 6.7cm (or 0.067m), and the average height of a 17 year old Japanese girl is 157.9cm (or 1.579m).

445 + 574 = 1019 pixels
1019 pixels = 1.579m
1 pixel = 1.579m/1019 = 0.00154955839m
0.00154955839m X 222 = 0.344001963m
0.00154955839m X 1025 = 1.58829735m
1.58829735m + 0.344001963m = 1.93229931m

= 2*atan(22/(1438/tan(70/2)))
= 0.0144975539 rad
= 0.8306486517354871868 degrees

Enter these values through the angscaler, and we have a distance of 4.6214m to the furthest ball.

= 2*atan(1019/(1438/tan(70/2)))
= 0.647858825 rad
= 37.1195763928966684 degrees

Caclulating as above, Ryuko is 2.3514m away, which means the distance from the furthest ball to Ryuko is 2.27m. The fastest tennis ball serve is by Tilden, and was clocked at going 73.14 m/s. Given Hakodate is embued with a 2 Star Goku Uniform that grants her superhuman powers and her tennis ball attacks can shatter rock and metal, I think it's safe to assume her serves are at least this fast.

T = 2.27/73.14
= 0.0310363686s

The balls are cut so many times they're turned to string. by getting the thickness of these strings, we can determine how thinly the balls were cut, and by proxy, how many times they were cut.

985 pixels = 0.067m
0.067m/2 = 0.0335m
1 pixel = 0.067m/985 = 6.80203046e-5m
6.80203046e-5m X 8 = 0.000544162437m

Now for the number of times the ball was cut, longways and acrossways.

0.067/0.000544162437 = 123.12500

That's the number of times each individual ball was cut. Cutting 123.125 times vertically and 123.125 times horizontally means that each ball was cut 246.25 times. Next we need the distance Ryuko swings her arms with the Scissor Blade, which given how the tennis balls are coming at her would be at a 180 angle at least, so we'll find the distance slashed as half the circumference of a circle.

C = 2πr
= 2 X π X 1.93229931
= 12.1409946/2
= 6.0704973m

Now we just need to count the balls. All of them. Iwandesu already counted and got 220, but it's best to be safe, so let's recount them. (Inhales)

214 balls, which is pretty close to Iwan's count. All that's left is to find out the distance cut, and we can get our speed.

D = 6.0704973m X 246.25
= 1494.85996m X 214
= 319900.031m/0.0310363686s
= 10307263.6/340.29
= Mach 30289.6459

That's ridiculously fast! However, I've seen another way of scaling this feat, based on how far the balls flew from Hakodate before they got cut apart, so I'm going to try that out too.

535 pixels = 1.579m
1 pixel = 1.579m/535 = 0.00295140187m
0.00295140187m X 113 = 0.333508411m

89 pixels = 0.333508411m
1 pixel = 0.333508411m/89 = 0.00374728552m
0.00374728552m X 1512 = 5.66589571m

= 2*atan(48/(1433/tan(70/2)))
= 0.0317392844 rad
= 1.81852704088992434 degrees

Going through the scaling process above once more, and the distance to the largest tennis ball is 2.1108m away.
128 + 158 = 286 pixels

= 2*atan(286/(1433/tan(70/2)))
= 0.18856836 rad
= 10.804171177730332 degrees

That gets us a distance of 8.3488m to Ryuko.

D = 8.3488m - 2.1108m
= 6.23800m

D = 6.23800m - 5.66589571m
= 0.57210429m

T = 0.57210429/73.14
= 0.00782204389s

T = 319900.031m/0.00782204389s
= 40897243.2/299792458 X 100
= 13.6418519% C

Last but absolutely not least, let's go by the number of tennis balls given in the show itself...

110 Million (110,000,000).

(Low end)
T = 6.0704973m X 246.25
= 1494.85996m X 110000000
= 164434595600m/0.0310363686s
= 5.29812613e12/299792458
= 17672.6465 C

(High end)
T = 6.0704973m X 246.25
= 1494.85996m X 110000000
= 164434595600m/0.00782204389s
= 2.10219474e13/299792458
= 70121.6686 C

Final Results
Ryuko cuts up tennis balls (low end - 214 balls) = Mach 30289.646
Ryuko cuts up tennis balls (high end - 214 balls) = 13.642% C
Ryuko cuts up tennis balls (low end - 111000000 balls) = 17672.647 C
Ryuko cuts up tennis balls (high end - 111000000 balls) = 70121.669 C

Stocking Anarchy · Feb 7, 2022

(Episode 21)

Mako and Senketsu purge Ryuko of Junketsu's influence, and this causes a huge water explosion. Scaling from the S. S. Naked Sun. The standard height of a door is 6 feet 8 inches (or 2.03200m)

161 pixels = 2.03200m
1 pixel = 2.03200m/161 = 0.012621118m
0.012621118m X 735 = 9.27652173m

18 pixels = 9.27652173m
1 pixel = 9.27652173m/18 = 0.515362318m

0.515362318m X 224 = 115.441159m
0.515362318m X 999 = 514.846956m
0.515362318m X 1900 = 979.188404m
979.188404m/2 = 489.594202m
0.515362318m X 1489 = 767.374492m
767.374492m/2 = 383.687246m
0.515362318m X 1387 = 714.807535m

Volume as the bottom parts and top parts as cylinders.

V = πr^2h
= π X 489.594202^2 X 115.441159
= 86932682.9m^3

V = πr^2h
= π X 383.687246^2 X 514.846956
= 238112804m^3

V = 86932682.9 + 238112804
= 325045487m^3

Weight of water is 1000kg/m^3.

M = 325045487 X 1000
= 325045487000kg
Now for the timeframe.

0.6 seconds.

T = 714.807535m/0.6s
= 1191.34589m/s

Finally, for our energy.

KE = (0.5)mv^2
= (0.5) X 325045487000 X 1191.34589^2
= 2.30669347e17 joules
= 55.131297084130018504 megatons

Final Results
Ryuko gets purged = 55.131 megatons

Stocking Anarchy · Feb 7, 2022

Ryuko calls out to Senketsu, who sends down the scissor blades from orbit. Ryuko lost the scissor blades in the final battle with Ragyo. So, how far up were Ryuko and Ragyo?

$ac6b6294509876e4bb09d25bebf54ea34afde11c$

R = (h/2) + c^2/(8h)
= (27/2) + 873^2/(8 X 27)
= 3541.875 X 2
= 7083.75 pixels

The radius of the Earth is 6371km, and it's diameter is 12742km.

= 2*atan(7083.75/(717/tan(70/2)))
= 2.72067399 rad
= 155.88313705840463 degrees

Enter those values through the trusty angscaler, and the Earth is 1361km away. Now for our timeframe from which the scissor blades fly down from orbit to when they reach the Earth.

Timeframe is 10 seconds and 2 frames.

T = 1s/24
= 41.6666667ms X 13
= 0.541666667s + 6s
= 6.54166667s

Finally, for our speed.

T = 1361km/6.54166667s
= 208050.955/340.29
= Mach 611.393091

Final Results
Senketsu sends down the scissor blades from space = Mach 611.393

Stocking Anarchy · Feb 7, 2022

Uzu bonks Nui many times, and claims to be faster than light, the Inumuta says he isn't. So just how fast is it? For a change, we'll get the timeframe first.

Timeframe is 1 frame.

T = 1s/24
= 41.6666667ms

With that done, how many times does Nui get bonked in the timeframe?

That's 40 bonks. Now, we'll get the distance Uzu has to thrust his sword. For that, we'll need Nui's height. TO get that, we'll scale her height from the official "height chart"...

...and the unofficial scaling from it.

Nui isn't on this chart, but we can find her height scaled from Ryuko, who according to the above is 164cm tall.

537 pixels = 164cm
1 pixel = 164cm/537 = 0.305400372cm
0.305400372cm X 315 = 96.2011172cm

265 pixels = 96.2011172cm
1 pixel = 96.2011172cm/265 = 0.363023084cm
0.363023084cm X 154 = 55.9055549cm

Now let's find Nui's full height.

383 pixels = 55.9055549cm
1 pixel = 55.9055549cm/383 = 0.145967506cm
0.145967506cm X 963 = 140.566708cm

Now we have Nui's height, let's get scaling her to Blade Regalia.

69 + 49 = 118 pixels
118 pixels = 140.566708cm
1 pixel = 140.566708cm/118 = 1.19124329cm
1.19124329cm X 59 = 70.2833541cm

At last, we get to the distance between Nui and Uzu. We'll go with a low end and a high end. Firstly, for the low end.

169 + 141 = 310 pixels
310 pixels = 140.566708cm
1 pixel = 140.566708cm/310 = 0.453440994cm
0.453440994cm X 839 = 380.436994cm

Now, we multiply that distance by the number of thrusts Uzu made in the timeframe (that being 40).

D = 380.436994cm X 40
= 15217.4798cm (152.174798m)

T = 152.174798m/41.6666667ms
= 3652.19515/340.29
= Mach 10.7325962

= 2*atan(113/(1439/tan(70/2)))
= 0.0743799542 rad
= 4.261657456046933135 degrees

Good ol' angscaler, same straight busta. Distance to Uzu's leg is 944.49cm. Once again we times by the number of thrusts Uzu made.

D = 944.49cm X 40
= 37779.6cm (377.79600m)

T = 377.79600m/41.6666667ms
= 9067.10399/340.29
= Mach 26.6452261

Final Results
Nui Harime's height = 140.567cm
Uzu bonks Nui (low end) = Mach 10.733
Uzu bonks Nui (high end) = Mach 26.645

Nowhere near the speed of light (you'd need to have at least tens of thousands of attacks for that), or even near the best speed feat in the series, but it's still good for consistencies sake.

Stocking Anarchy · Feb 7, 2022

Satsuki sets off a trap that destroys the Great Cultural and Sport Festival Stadium, which she survives in her underwear. Previously, I calced the diameter of the Honnouji Academy grounds to be 410.32m across.

757 pixels = 410.32m
1 pixel = 410.32m/757 = 0.542034346m
0.542034346m X 1453 = 787.575905m

792 pixels = 787.575905m
1 pixel = 787.575905m/792 = 0.994414021m

0.994414021m X 1022 = 1016.29113m
1016.29113m/2 = 508.145565m

Given our radius, we can find the energy of the fireball. Entering that into Nukemap and we have a yield of 98 kilotons. Alternatively, using the MIT nuclear explosion calculator gets us a yield of 448.1 kilotons.

Final Results
Grand Cultural and Sport Festival Stadium explodes (low end) = 98 kilotons
Grand Cultural and Sport Festival Stadium explodes (high end) = 448.1 kilotons

Stocking Anarchy · Feb 7, 2022

First off an NSFW warning...

Stocking goes up the Moons nose with divine boogers and the Moon "sneezes" her out with a mass off...what is clearly not snot. First off of note, we see the Moon in scale with the Earth a few times. So it should be comparable to the IRL Moon.

The initial sneeze may be a bit difficult to calc due to perspective (but I'll still try it) but the dribble that follows can easily be calced. The Moon has a diameter of 3474.8km.

297 pixels = 3474.8km
1 pixel = 3474.8km/297 = 11.6996633km (11699.6633m)
11699.6633m X 34 = 397788.552m
397788.552m/2 = 198894.276m
11699.6633m X 52 = 608382.492m
608382.492m/2 = 304191.246m
11699.6633m X 464 = 5428643.77m
5428643.77m - 608382.492m = 4820261.28m

Volume of the top part as a cone and the bottom part as half an ellipsoid.

V = πr^2h/3
= π X 198894.276^2 X 4820261.28/3
= 1.9968423e17m^3

V = 4/3πabc
= 4/3 X π X 198894.276 X 198894.276 X 304191.246
= 5.04057279e16/2
= 2.5202864e16m^3

V = 1.9968423e17 + 2.5202864e16
= 2.24887094e17m^3

I can't find what the density of...bodily fluids...are, so I'll just go with water, which weighs 1000kg/m^3.

M = 2.24887094e17 X 1000
= 2.24887094e20kg

Next up for the speed.

18 frames.

T = 1s/25
= 40ms X 18
= 0.72s

T = 5428643.77m/0.72s
= 7539783.01m/s

Let's have our energy!

E = (0.5) X 2.24887094e20 X 7539783.01^2
= 6.39222762e33 joules
= 1.5277790678776288491 yottatons

Now to attempt the initial sneeze. it's hard due to the perspective, but I'll give it a try.

11699.6633m X 72 = 842375.758m
11699.6633m X 574 = 6715606.73m
11699.6633m X 119 = 1392259.93m
1392259.93m/2 = 696129.965m

We'll be using this arc calculator to help us.

The arc is 6993922.75089m long. Volume as a cone.

V = πr^2h/3
= π X 696129.965^2 X 6993922.75089/3
= 3.549197e18m^3

M = 3.549197e18 X 1000
= 3.549197e21kg

Almost done, we just need our timeframe.

16 frames.

T = 40ms X 16
= 0.64s

T = 6993922.75089m/0.64s
= 10928004.3m/s

E = (0.5) X 3.549197e21 X 10928004.3^2
= 2.11924821e35 joules

As a final result, we can also add the above dribble to that.

E = 6.39222762e33 + 2.11924821e35
= 2.18317049e35 joules
= 52.179027007648180359 yottatons

Final Results
Stocking gets "sneezed" on (low end) = 1.528 yottatons
Stocking gets "sneezed" on (high end) = 52.179 yottatons

Not 100% sure about the high end due to the perspective, but the low end is fine. Stocking is hit by both and is at best annoyed.

Stocking Anarchy · Feb 7, 2022

The Trans-Homers asteroids fly down to Earth. The Earth is also elecrified on their arrival, but I'm not sure how to calc that. Still, the speed is legitimate. Diameter of the Earth is 12756.2km.

= 2*atan(431/(1592/tan(70/2)))
= 0.255157025 rad
= 14.6194206456502975 degrees

Enter that through the angscaler, and we have a distance of 49722km to the Earth.

3 seconds.

T = 49722km/3s
= 16574000/340.29
= Mach 48705.5159

And given they fly in a curve, it would actually be even higher.

Final Results
Trans-Homers arrive on Earth = Mach 48705.515

Stocking Anarchy · Feb 7, 2022

Stocking runs all around the planet to different countries before finally running into outer space. Even though there's a transition between each place, we can still see how fast Stockings is running in space through the movements of the Earth.

$ac6b6294509876e4bb09d25bebf54ea34afde11c$

R = (h/2) + c^2/(8h)
= (67/2) + 789^2/(8 X 67)
= 1194.91978

Radius of the Earth is 6378.1km

1194.91978 pixels = 6378.1km
1 pixel = 6378.1km/1194.91978 = 5.33768049km
5.33768049km X 264 = 1409.14765km

138 pixels = 1409.14765km
1 pixel = 1409.14765km/138 = 10.2112149km
10.2112149km X 28 = 285.914017km

The timeframe is 17 frames.

10.2112149km X 137 = 1398.93644km
1398.93644km - 285.914017km = 1113.02242km

T = 1s/25
= 40ms X 17
= 0.68s

T = 1113.02242km/0.68s
= 1636797.68/340.29
= Mach 4810.00817

Lastly for KE. Stocking has no official weight, but she takes the form of a girl between 17 and 19 according to the Panty & Stocking wiki, so we'll just go with the higher average of 120 lbs for 17 year old girls (or 54.4311kg).

E = (0.5) X 54.4311 X 1636797.68^2
= 7.29133609e13
= 17.426711496175908 kilotons

Final Results
Stocking runs into space (speed) = Mach 4810.008
Stocking runs into space (energy) = 17.427 kilotons

Stocking Anarchy · Feb 7, 2022

On my last rewatch of Panty & Stocking with Garterbelt, I noticed a few feats of note. To start, from the same episode that brought us large planet level Stocking comes another impressive feat. A ghost called Oscar H. Genius flies to the Moon by empowering himself with the nosebleeds of others. First off, despite the cartoony visuals and seeing the ship by the Moon, the Moon is definately the same size as the Moon. We can tell as there are multiple other shots throughout the series of the Moon next to the Earth, such as when Stocking running into space...

...during the We Are Angels video clip...

...and in the manga (which is canonically set in a parallel universe), where we see the Moon's scale next to the Earth.

It's pretty clearly moon-sized. So with all that out of the way, let's get to the speed.

1. Oscar flies to the Moon
Oscar flies towards the Moon. The Moon has a diameter of 3474.8km.

= 2*atan(687/(1621/tan(70/2)))
= 0.396345845 rad
= 22.7089441461026311 degrees

Entering all that into the angscaler to find our distance, we can determine that the Moon is 8652km away.

Timeframe is 3 seconds.

= 2*atan(713/(1621/tan(70/2)))
= 0.410934522 rad
= 23.5448137668842854 degrees

The Moon is now 8336.5km away.

L = 8652km - 8336.5km
= 315.5km

T = 315.5km/3s
= 105166.667/340.29
= Mach 309.050125

2. Oscar zooms towards the Moon
After absorbing more nosebleeds, Oscar flies at tremendous speeds towards the Moon.

= 2*atan(325/(495/tan(70/2)))
= 0.603200459 rad
= 34.5608405011397863 degrees

The Moon is 5584.9km away.

The timeframe is 1 second and 14 frames.

= 2*atan(658/(495/tan(70/2)))
= 1.12414233 rad
= 64.408611081162405 degrees

The Moon is now 2758.5km away.

L = 5584.9km - 2758.5km
= 2826.4km

T = 1s/24
= 41.6666667ms X 14
= 0.583333334s + 1s
= 1.58333333s

T = 2826.4km/1.58333333s
= 1785094.74/340.29
= Mach 5245.80428

Final Results
Oscar H. Genius flies towards the Moon = Mach 309.050
Boosted Oscar H. Genius flies towards the Moon = Mach 5245.804

Stocking Anarchy · Feb 7, 2022

A giant Trans-Homer (which looks familiar for some reason, can't put my finger on it) appears and approaches the Earth.

Diameter of the Earth is 12756.2km.

246 pixels = 12756.2km
1 pixel = 12756.2km/246 = 51.8544715km
51.8544715km X 433 = 22452.9862km
22452.9862km/2 = 11226.4931km (11226493.1m)

That's one huge robot. Given its colossal size, it'll also be moving pretty fast.

170 pixels = 12756.2km
1 pixel = 12756.2km/170 = 75.0364706km

Timeframe is 11 frames.

T = 1s/24
= 41.6666667ms X 11
= 0.458333334s

75.0364706km X 18 = 1350.65647km

T = 1350.65647km/0.458333334s
= 2946886.84/340.29
= Mach 8659.92783

Given we have its size and speed, we can also get its kinetic energy. Volume of its main body as a sphere (duh).

V = 4/3πr^3
= 4/3 X π X 11226493.1^3
= 5.92680926e21m^3

As per usual with machines, I'll use the mass of the light ship container vessel 2700TEUof 102.56kg/m^3 (which is probably a gargantuan low end, but the best I have for now).

M = 5.92680926e21 X 102.56
= 6.07853558e23kg

Finally, for the kinetic energy.

KE = (0.5)mv^2
= (0.5) X 5.92680926e21 X 2946886.84^2
= 2.57346268e34 joules
= 6.1507234225621409962 yottatons

Final Results
Giant Trans-Homer size (main body) = 22452.986km
Giant Trans-Homer approaches Earth (speed) = Mach 8659.928
Giant Trans-Homer approaches Earth (energy) = 6.151 yottatons

Trigger-verse calc archive

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