Trigger-verse calc archive

Stocking Anarchy · Feb 7, 2022

The meteorite that wiped out the dinosaurs lands right on Garterbelt and he survives it. That at minimum would be 100 teratons, but here it and it's effects look even greater. Diameter of the Earth is 12756.2km, or 12756200m.

2135 pixels = 12756200m
1 pixel = 12756200m/2135 = 5974.80094m
5974.80094m X 677 = 4044940.24m

Timeframe is 2.96 seconds.

4044940.24m/670 = 6037.22424m
6037.22424m X 1195 = 7214482.97m
7214482.97m/2 = 3607241.48m
4044940.24m/2 = 2022470.12m

T = 3607241.48m/2.96s
= 1218662.66m/s

Volume as an ellipsoid.

V = 4/3πabc
= 4/3 X π X 2022470.12 X 3607241.48 X 3607241.48
= 1.10235419e20m^3

Weight of a dustcloud/air is 1.003kg per m^3.

M = 1.003 X 1.10235419e20
= 1.10566125e20kg

Finally, let's get our energy.

KE = (0.5)mv^2
= (0.5) X 1.10566125e20 X 1218662.66^2
= 8.21030144e31 joules
= 19.623091395793498037 zettatons

Final Results
Meteor hits Garterbelt = 19.623 zettatons

Consistent with Stocking getting jitzed on by the Moon.

Stocking Anarchy · Feb 7, 2022

Scanty and Kneesocks throw their weapons at Panty and Brief, but Stocking deflects them and flies down from Heaven. Now, to point out just how impressive this is, it's noted earlier in the series that Heaven resides beyond the entire Universe.

To further back this up, Panty and Stocking have been into space before in several occasions, such as when they went to get back Panty's tapes...

...when Stocking ran into space...

...and a couple of times from the manga (which is set in a parallel universe). Now for another note, Panty and Stocking with Garterbelt Daten Citi Paparazi says as follows...

(The relevant part)

Panty & Stocking with Garterbelt Daten City Paparazzi said:
Panty has become just a bitch. Panty was kicked out of the church and started living a healthy life on the prarie, but were told to live as she wanted and finally awakened. Panty headed for Briefs (and?) Corset. Stocking flew back to the ground from Heaven and joined the sword, and finally the two's last party began!

The Panty & Stocking guide book says that Stocking flew down from Heaven; no teleportation, no portals, she flew to the ground from Heaven. Given that Heaven resides beyond the Universe, that means that Stocking flew across the universe to save Panty (and sensed and reacted to Scanty & Kneesocks attacks). The radius of the observable universe is 46,500,000,000 lightyears. First for Stockings sword throw...

Timeframe is 3 seconds.

T = 46,500,000,000 lightyears/3s
= 1.4663819e26/299792458
= 4.89132352e17 C

Then for Stocking flying down.

Timeframe is 14 seconds.

T = 1.4663819e26/14s
= 1.04741564e25/299792458
= 3.4938025e16 C

Final Results
Stocking throws her sword = 489132352000000000 C
Stocking flies down from Heaven = 34938025000000000 C

Stocking Anarchy · Feb 7, 2022

Luluco blows up a large meteorite, which she survives the explosion of (and so does her mother). Luluco is in the top part.

A space shuttle is 184 feet (56.0832m) tall.

491 pixels = 56.0832m
1 pixel = 56.0832m/491 = 0.114222403m
0.114222403m X 132 = 15.0773572m
0.114222403m X 87 = 9.93734906m

$ac6b6294509876e4bb09d25bebf54ea34afde11c$

R = (h/2) + c^2/(8h)
= (63/2) + 1185^2/(8 X 63)
= 2817.66071

For the diameter, times that by 2.

D = 2817.66071 X 2
= 5635.32142

101 pixels = 9.93734906m
1 pixel = 9.93734906m/101 = 0.0983895947m
0.0983895947m X 2817.66071 = 277.228495m
0.0983895947m X 5635.32142 = 554.456991m

Volume as a sphere.

V = 4/3πr^3
= 4/3 X π X 277.228495^3
= 89248764.2m^3

It gets reduced to dust, so I'd say that's pulverization. Pulverization of rock is 200000000 joules/m^3.

E = 89248764.2 X 200000000
= 1.78497528e16 joules

Now for the kinetic energy. Looking at this asteroid chart chart, the smallest asteroid there (Bennu) has a diameter of 250 m and a mass of 0.00014 X 10^15kg (140000000000kg). That's about half the size of this asteroid, so we'll times that by two for our mass (140000000000kg X 2 = 280000000000kg).

158 pixels = 554.456991m
1 pixel = 554.456991m/158 = 3.50922146m
3.50922146m X 1280 = 4491.80347m

4 seconds.

T = 4491.80347m/4s
= 1122.95087m/s

KE = (0.5) X 280000000000 X 1122.95087^2
= 1.76542612e17 joules

Now, we'll add both results together for our final result.

E = 1.78497528e16 + 1.76542612e17
= 1.94392365e17 joules
= 46.4608902964 megaton

Final Results
Luluco blows up asteroid = 46.461 megatons

Stocking Anarchy · Feb 7, 2022

Violence goes berserk, and destroys the planet SVM-Z. Luluco seems to be walking around on SVM-Z fine, so it seems safe enough to assume it has an Earth-like size. The Earth has a diameter of 12,742km and a mass of 5.9722 X 10^24kg (5.9722e24kg).

Timeframe is 2 seconds.

1180 pixels = 12,742km
1 pixel = 12,742km/1180 = 10.7983051km
10.7983051km X 1954 = 21099.8882km

T = 21099.8882km/2s
= 10549944.1m/s

KE = (0.5)mv^2
= (0.5) X 5.9722e24 X 10549944.1^2
= 79.435199091778194997 ninatons

Only scales to Violence, and it's unclear if he survives in anycase, but there's also a nice speed feat of Alpha Omega Nova saving Luluco.

Timeframe is 2 seconds.

object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))

= 2*atan(2439/(1608/tan(70/2)))
= 1.24630361 rad
= 71.407936845095676 degrees

Enter those values through the anscaler, and we get a distance of 8864.9km to SVM-Z.

object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))

= 2*atan(1414/(1608/tan(70/2)))
= 0.7895547 rad
= 45.23815200483008 degrees

That's a distance of 15291km.

L = 15291km - 8864.9km
= 6426.1km

T = 6426.1km/2s
= 3213050/340.29
= Mach 9442.09351

Let's also find the kinetic energy for this. According to this link, average weight of a 13 year old boy is between 75 and 145 pounds and the average weight of a 13 year old girl is between 76 and 148 pounds. At a low end, that's 34.0194kg & 34.473kg.

M = 34.0194kg + 34.473kg
= 68.4924kg

KE = (0.5)mv^2
= (0.5) X 68.4924 X 3213050^2
= 3.53547163e14 joules
= 84.4997999521988561 kilotons

Final results
Violence destroys SVM-Z = 79.435 ninatons
Alpha Omega Nova flies Luluco into space (speed) = Mach 9442.094
Alpha Omega Nova flies Luluco into space (energy) = 84.5 kilotons

Stocking Anarchy · Feb 7, 2022

Luluco and Alpha Omega Nova spread their love aura across space, then Luluco reabsorbs her aura, then finally it explodes across space again. To give some more context on this, as Luluco absorbs her aura, she's refered to as "the being who acts as the spark-plug for the entire Universe."

The Blackholien also mentions that he plans to shoplift the entire Universe, and start a new collection of shoplifted goods in that universe.

After the banishing of the Blackholien and Alpha Omega Nova, all of the Ogikubo's of the Universe return to their original places.

On top of the Big Bangs that go off in Luluco and Alpha Omega Nova's brains, I think there's more than enough justification to say the love aura encompasses the Universe (especially given that Luluco acts as the Spark Plug for the entire Universe, whilst sucking up this exact same aura). The radius of the observable universe is 46,500,000,000 lightyears. So let's go by each example.

1. Luluco & Apha Omega Nova unleash their love aura

Timeframe is 10 seconds and 14 frames.

T = 1s/24
= 41.6666667ms X 14
= 0.583333334s + 10s
= 10.5833333s

T = 46,500,000,000LY/10.5833333s
= 4.15667312e25/299792458
= 138651691000000000 C

2. Luluco sucks up her love aura

Timeframe is 20 seconds and 8 frames (as above, one frame is 41.6666667ms).

T = 41.6666667ms X 8
= 0.333333334s + 20s
= 20.3333333s

T = 46,500,000,000LY/20.3333333s
= 2.16351429e25/299792458
= 72167068700000000 C

3. Love aura explosion

Timeframe is 4 seconds and 22 frames.

T = 41.6666667ms X 22
= 0.916666667s + 4s
= 4.91666667s

T = 46,500,000,000LY/4.91666667s
= 8.94741499e25/299792458
= 298453639000000000 C

Final Results
Luluco and Alpha Omega Nova unleash their Love Aura = 138651691000000000 C
Luluco sucks up her love aura = 72167068700000000 C
Love aura explosion = 298453639000000000 C

Stocking Anarchy · Feb 7, 2022

3:03

Earlier in the video at 1:56.

1:19

Claudia's causes a 3rd Destroy Finale and covers the world in light, turning everyone into Inferno Cop. The screen whites out and Inferno Cop notes how bright it is, and it covers the planet, so this should be pretty straight forward. The Sun has a lux of 100,000 and the Earth as a diameter of 12756.2km (12756200m).

L = -2.5 log I - 14.2
= -2.5 log 32,000 - 14.2
= -25.4628749

$fa13db5bce810b9d7667302abaefae0e83742cab$

M(star) is the apparent magnitude of the light source
m= is the apparent magnitude of the sun (-26.73)
L(star) is the Luminosity
L= Luminosity of the sun (3.486*10^26)
d= Distance to the sun from earth (0.000004731537734207877 parsecs)
d(star)= distance to the light source

--25.4628749 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(12756200))^2)

We'll go through this step by step...

146000000000/(384400000))^2) = 130997519
-25.4628749 - -26.73 = 130997519/((L/3.846*10^26)
1.2671251 = -2.5Log(130997519/((L/3.846*10^26))
1.2671251/-2.5 = (130997519/((L/3.846*10^26))
10^(-0.50685004) = (130997519/((L/3.846*10^26))
0.311279098 = (130997519/((L/3.846*10^26))
0.311279098 X (3.864*10e26) = 130997519
1.20278243e27/130997519 = 9.18171916e18 joules

Next to find the duration.

5.8 seconds.

E = 9.18171916e18 X 5.8
= 5.32539711e19 joules
= 12.728004565 gigatons

Let's also get the speed.

T = 12756200m/5.8s
= 2199344.83/340.29
= Mach 6463.14858

Final Results
3rd Destroy Finale (energy) = 12.728 gigatons
3rd Destroy Finale (speed) = Mach 6463.149

Stocking Anarchy · Feb 7, 2022

0:51

Inferno Cop participates in a race across America, which occurs in less than two minutes. From coast to coast, it would be between 2,500 miles to 3,500 miles (or 4023.36km to 5632.704km). Could not be easier.

Timeframe is a minute and 43 seconds, or 103 seconds.

(Low end)

T = 4023.36km/103s
= 39061.7476/340.29
= Mach 114.789584

(High end)

T = 5632.704km/103s
= 54686.4466/340.29
= Mach 160.705418

That's mighty fast, and I'm not one to pass up a chance of kinetic energy. As an estimate, the weight of a Formula 1 racing car is 740kg.

(Low end)

KE = (0.5)mv^2
= (0.5) X 740 X 39061.7476^2
= 5.64553446e11 joules
= 134.931511950287 tons of TNT

(High end)

KE = (0.5)mv^2
= (0.5) X 740 X 54686.4466^2
= 1.10652475e12 joules
= 264.4657624282983 tons of TNT

Final Results
Inferno Cop races across America (speed - low end) = Mach 114.79
Inferno Cop races across America (speed - high end) = Mach 160.705
Inferno Cop races across America (energy - low end) = 134.932 tons of TNT
Inferno Cop races across America (energy - high end) = 264.466 tons of TNT

Stocking Anarchy · Feb 7, 2022

Kenji punches Laomoto off the roof of his tower, who explodes in a massive explosion. There may be some other shots of the interior of the building, but for the meantime, we'll scale from the top of the tower. The average height of a Japanese man is 170.7cm.

236 pixels = 170.7cm
1 pixel = 170.7cm/236 = 0.723305085cm
0.723305085cm X 4431 = 3204.96483cm (32.0496483m)

That's still a low end, as it doesn't have the ends of the building. In anycase, to scale the top of the tower to the explosion.

183 pixels = 32.0496483m
1 pixel = 32.0496483m/183 = 0.17513469m
0.17513469m X 1066 = 186.69358m
186.69358m/2 = 93.34679m

That's our radius, so with that, we can find the energy of the explosion! Using Nukemap and working our way back (as it doesn't have anything for lower than a kiloton), we find a yield of 8460 kilotons for moderate blast damage radius and 78000 kilotons for heavy blast damage radius, with the radius for both being 9.3km (or 9300m). Given the blast radius is nowhere near that big however, we need to divide the energy by a thousand to find out how big the explosion really was, which gives us a result of 8 tons of TNT and 78 tons of TNT respectively. However, given that every single other ninja in the series has caused a fireball with their death explosion in the series, we can also assume that the same happened here, and for our high end, we get a result of of 1.5199 kilotons.

Final Results
Laomato's explosion (low end) = 78 tons of TNT
Laomoto's explosion (high end) = 1.52 kilotons

Stocking Anarchy · Feb 7, 2022

Darkninja blows up a boat. We're given a nice fireball, so this should be simple enough. The average height of a Japanese man is 170.7cm (1.707m).

43 pixels = 1.707m
1 pixel = 1.707m/43 = 0.0396976744m

0.0396976744m X 1018 = 40.4122325m
40.4122325m/2 = 20.2061163m

Using Nukemap for fireball radius, we get a yield of 16 tons of TNT. Alternately, using the MIT nuke calculator we get a yield of 141 tons of TNT for fireball radius at breakaway for contact surface burst.

Final Results
Darkninja blows up boat (low end) = 16 tons of TNT
Darkninja blows up boat (high end) = 141 tons of TNT

Stocking Anarchy · Feb 7, 2022

Michiru throws a baseball repeatedly with enough force to create small craters in concrete. A baseball is 73mm to 76mm in diameter (or 7.3cm to 7.6cm). First for the size of the crater...

16 pixels = 7.3cm
1 pixel = 7.3cm/16 = 0.45625cm
0.45625cm X 37 = 16.88125cm
16.88125cm/2 = 8.440625cm
0.45625cm X 49 = 22.35625cm
22.35625cm/2 = 11.178125cm

Then the width of the bottom of the crater...

186 pixels = 22.35625cm
1 pixel = 22.35625cm/186 = 0.120194892cm
0.120194892cm X 103 = 12.3800739cm
12.3800739cm/2 = 6.19003695cm (0.0619003695m)

Then the depth...

212 pixels = 7.3cm
1 pixel = 7.3cm/212 = 0.0344339623cm
0.0344339623cm X 111 = 3.82216982cm

Volume of the area broken as a conical frustrum.

V = (1/3)π(r^2+rR+R^2)h
= (1/3) X π X (6.19003695^2 + 6.19003695 X 8.440625 + 8.440625^2) X 3.82216982
= 647.649296cm^3

Violent fragmentation of cement is between 17 joules per cm^3 to 20 joules/cm^3.

E = 647.649296 X 17
= 11010.038 joules

That's a respectable amount of energy, but what we're really after is the speed, which we'll do using drag coefficient. For this, we need the energy of the impact, the distance the ball travelled and the surface area of the ball. The distance from a baseball mound to home base is 60 feet & 6 inches, or 18.4404m.

90 pixels = 18.4404m
1 pixel = 18.4404m/90 = 0.204893333m
0.204893333m X 143 = 29.2997466m

We'll need the surface area of the baseball.

A = 4πr^2
= 4 X π X 0.0365^2
= 0.0167415473m^2

Drag coefficient of a sphere is 0.5. Now to find our speed (using this calculator to find the square root).

DF = ½ρCAv2 X d
11010.038 X 2 = 0.5 X 0.0167415473 X 29.2997466
V^2 = 22020.076/0.245261547
V^2 = 89782.0154
V = 299.6364720790845m/s

Final Results
Michiru throws baseball (energy) = 11010.038 joules
Michiru throws baseball (speed) = 299.636m/s

Stocking Anarchy · Feb 7, 2022

Shirou becomes Ginrou through an unknown necromantic ritual, where he absorbs the blood of thousands of his brethren. This causes a huge explosion of blood. We can scale the size of the bloodburst from the size of the pit. First the get the pits depth. The average length of a horse is 8 feet, or 2.4m.

1158 + 578 + 1282 = 3018 pixels
1111 pixels = 2.4m
1 pixel = 2.4m/1111 = 0.00216021602m
0.00216021602m X 3018 = 6.51953195m

Now we can finally get to scaling the dimensions of the blood burst.

217 pixels = 6.51953195m
1 pixel = 6.51953195m/217 = 0.030043926m

0.030043926m X 2520 = 75.7106935m
0.030043926m X 1173 = 35.2415252m

Now for the timeframe of the expansion of the blood bulb.

The timeframe is 2 seconds and 11 frames.

T = 1s/24
= 41.6666667ms X 11
= 0.458333334s + 2s
= 2.45833333s

T = 35.2415252m/2.45833333s
= 14.3355357m/s

Finally, for our mass. This is the easiest part, as we're outright given the number of bodies in the pit. The average person has 1.2 to 1.5 gallons of blood, or an average of 1.35 gallons.
https://www.livescience.com/32213-how-much-blood-is-in-the-human-body.html

The average adult has about 1.2 to 1.5 gallons (4.5 to 5.5 liters) of blood circulating inside their body, said Dr. Daniel Landau, a hematologist and oncologist at the University of Florida Cancer Center – Orlando Health.

We also have the number of fellow beastmen who's blood got absorbed by Ginrou; 2000.

1 gallon is equivalent to 3.7854kg.

M = 1.35 X 2000
= 2700 X 3.7854kg
= 10220.58kg

KE = (0.5)mv^2
= (0.5) X 10220.58 X 14.3355357^2
= 1050203.35 joules

Let's also add the GPE. First, we have to find the centre of gravity for the hemisphere.

CG = 3 X r/8
= 3 X 35.2415252/8
= 13.2155719m

E = 13.2155719 X 9.807 X 10220.58
= 1324639.43 joules

Now, to add the two together...

E = 1050203.35 + 1324639.43
= 2374842.78 joules

Final Results
Ginrou's blood bubble = >2374842.78 joules

That's it? I'm honestly surprised at how low this is, but given there's an explosion afterwards, the final result would ultimately be even higher.

Stocking Anarchy · Feb 7, 2022

Alan's attack devastates a stadium. Take a note that the poduims are solid structures, so to get them to shift as they did would take a great amount of energy. Let's scale the size of the stadium from the stepsps. An outside step is on average 11 inches tall, or 27.94cm.
https://www.hunker.com/12377641/the-average-height-of-a-stair-step

On average, American architects have used a standard stair height of 7.5 inches. On stairs built inside, the average step length is 9 inches tall, while outside steps have an average length of 11 inches tall.

22 pixels = 27.94cm
1 pixel = 27.94cm/22 = 1.27cm
1.27cm X 1009 = 1281.43cm
1.27cm X 385 = 488.95cm
1.27cm X 270 = 342.9cm

87 pixels = 1281.43cm
1 pixel = 1281.43cm/87 = 14.7290805cm
14.7290805cm X 58 = 854.286669cm
14.7290805cm X 117 = 1723.30242cm
14.7290805cm X 154 = 2268.2784cm

Volume of that area as an irregular trapezium, which we'll find by finding the area of a rectangle and a triangle.

A = lh
= 2268.2784 X 854.286669
= 1937760cm^2

H = 1281.43cm - 854.286669cm
= 427.143331cm

A = ab/2
= 2268.2784 X 427.143331/2
= 484439.996cm^2

A = 1937760 + 484439.996
= 2422200cm^2

Now we have that, to find the width of each section as well as the distance they moved.

1.27cm X 1037 = 1316.99cm
1.27cm X 794 = 1008.38cm
1.27cm X 65 = 82.55cm
1.27cm X 231 = 293.37cm

We'll find the volume of both as trapezoidal prisms.

V = Ah
= 2422200 X 1008.38
= 2442498036cm^3
= 2442.498036m^3

V = Ah
= 2422200 X 1316.99
= 3190013178cm^3
= 3190.013178m^3

There's also the seats themselves to take into acount, but given there's another podium being moved and the ground itself, it would cover that. Next up, the distance moved.

L = 488.95cm - 293.37cm
= 195.58cm

L = 342.9cm - 82.55cm
= 260.35cm

Concrete weighs about 2.4 tonnes for each cubic metre, which is 2400kg.

M = 2442.498036 X 2400kg
= 5861995.29kg

M = 3190.013178 X 2400kg
= 7656031.63kg

Now we've gotten all that out of the way, we get to the easy part; the timeframe.

Timeframe is 5 frames.

T = 1s/24
= 41.6666667ms X 5
= 0.208333333s

With all that out of the way, we can finally get to our kinetic energy!

T = 195.58cm/0.208333333s
= 9.38784002m/s

KE = (0.5)mv^2
= (0.5) X 5861995.29 X 9.38784002^2
= 258313337 joules

T = 260.35cm/0.208333333s
= 12.4968m/s

KE = (0.5)mv^2
= (0.5) X 7656031.63 X 12.4968^2
= 597821269 joules

E = 258313337 + 597821269
= 856134606 joules
= 0.20462108174 tons of TNT

Final Results
Alan devastates a stadium = >205kg of TNT

Keep in mind too there was another podium, so ultimately this would be even higher.

Stocking Anarchy · Feb 8, 2022

Yes I have made this title for other blogs before and no I don't care that I have, I'll do it again as many times as I feel like. :cat

Anyway, to business.

Pandy and Retro are arrested and flown to the Dead Leaves prison on the remains of the Moon. The flight only takes a few seconds. This is super straight forward, but due to the wonky visuals we'll be using a low end via scaling off the Earth and a high end of the distance between the Earth and the Moon. The diameter of the Earth is 12,742km, and the distance from the Earth to the Moon is 384,400km.

(Low end)
185 pixels = 12,742km
1 pixel = 12,742km/185 = 68.8756757km
68.8756757km X 190 = 13086.3784km

(High end)
729 pixels = 384,400km
1 pixel = 384,400km/729 = 527.297668km
527.297668km X 190 = 100186.557km

Timeframe is 1 second and 7 frames.

T = 1s/24
= 41.6666667ms X 7
= 0.291666667s + 1s
= 1.29166667s

(Low end)
523 X 68.8756757km = 36021.9784km
36021.9784km - 13086.3784km = 22935.6km

T = 22935.6km/1.29166667s
= 17756593.5/340.29
= Mach 52180.7679

(High end)
527.297668km X 523 = 275776.68km
275776.68km - 100186.557km = 175590.123km

T = 175590.123km/1.29166667s
= 135940740/299792458 X 100
= 45.3449499% C

At the end of the film, we see the opposite when Pandy and Retro escape and return to Earth.

No harm doing this all over again is there?

(Low end)
181 pixels = 12,742km
1 pixel = 12,742km/181 = 70.3977901km
70.3977901km X 497 = 34987.7017km

(High end)
708 pixels = 384,400km
1 pixel = 384,400km/708 = 542.937853km
542.937853km X 497 = 269840.113km

Timeframe is 8 seconds and 22 pixels.

T = 41.6666667ms X 22
= 0.916666667s + 8s
= 8.91666667s

(Low end)
70.3977901km X 101 = 7110.1768km
34987.7017km - 7110.1768km = 27877.5249km

T = 27877.5249km/8.91666667s
= 3126451.39/340.29
= Mach 9187.60877

(High end)
542.937853km X 101 = 54836.7232km
269840.113km - 54836.7232km = 215003.39km

T = 215003.39km/8.91666667s
= 24112529.7/340.29
= Mach 70858.7666

Final Results
Pandy & Retro are flown to the Moon (low end) = Mach 52180.768
Pandy & Retro are flown to the Moon (high end) = 45.345% C
Pandy & Retro return to Earth (low end) = Mach 9187.609
Pandy & Retro return to Earth (high end) = 70858.767

Stocking Anarchy · Feb 8, 2022

Giant caterpillar brings some biggatons.

1. Size of Dead Leaves and the Giant Catepillar
The Moon was fucked up, so we'll need to find the proper dimensions of the remains of the Moon and the size of the Giant Caterpillar and Dead Leaves. To start, we'll need the radius of the Moon. The radius of the Moon is 1737.4km.

$ac6b6294509876e4bb09d25bebf54ea34afde11c$

R = (h/2) + c^2/(8h)
= (278/2) + 670^2/(8 X 278)
= 340.843525 pixels

1737.4km = 340.843525 pixels
1 pixel = 1737.4km/340.843525 = 5.09735369km
5.09735369km X 86 = 438.372417km

533 pixels = 438.372417km
1 pixel = 438.372417km/533 = 0.822462321km
0.822462321km X 210 = 172.717087km
0.822462321km X 125 = 102.80779km
0.822462321km X 24 = 19.7390957km
0.822462321km X 66 = 54.2825132km

That's not including the parts of the caterpillar still underground.

2. Giant Caterpillar emerges

The Giant Caterpillar bursts out of the ground and starts firing lasers. As per above, the giant caterpillar is over 19.7390957km long

The timeframe is 2 seconds and 9 frames.

T = 1s/24
= 41.6666667ms X 9
= 0.375s + 2s
= 2.37500s

T = 19.7390957km/2.37500s
= 8311.19819/340.29
= Mach 24.4238684

We have the speed, so let's also go for the mass using square law. A caterpillar the same length as a silkworm weighs 3 grams (or 0.003kg), and a silkworm ranges from 40mm to 50mm in length (an average of 45mm). As per above, the length of the Giant Caterpillar is 19.7390957km (or 19739095700mm)

M2 = (H2/H1)^3*M1
= (19739.095700/0.045)^3 X 0.003
= 2.53201032e14kg

KE = (0.5)mv^2
= (0.5) X 2.53201032e14 X 8311.19819^2
= 8.74505919e21 joules
= 2.0901193092734224876 teratons

The Giant Caterpillar then fires off a series of laser beams, so let's get them too.

Timeframe is 1 frame.

207 pixels = 172.717087km
1 pixel = 172.717087km/207 = 0.834382063km
0.834382063km X 725 = 604.926996km

T = 604.926996km/41.6666667ms
= 14518247.9/340.29
= Mach 42664.3389

3. Giant Caterpillar destroys Dead Leaves

The Giant Caterpillars laser blows up Dead Leaves. Remember as per above; Dead Leaves is fucking huge.

174 pixels = 54.2825132km
1 pixel = 54.2825132km/174 = 0.311968467km
0.311968467km X 776 = 242.08753km (242087.53m)

0.311968467km X 769 = 239.903751km
239.903751km/2 = 119.951875km (119951.875m)

Volume as a conical frustrum.

R = 54.2825132km/2
= 27.1412566km (27141.2566m)

V = (1/3)π(r^2+rR+R^2)h
= (1/3) X π (27141.2566^2 + 27141.2566 X 119951.875 + 119951.875^2) X 242087.53
= 4.65976636e15m^3

The explosion looks super violent, so we'll go with violent fragmentation (69000000 joules/m^3).

E = 4.65976636e15 X 69000000
= 3.21523879e23 joules
= 76.846051386233270364 teratons

And incase there's any issues, we'll also go with a low end of fragmentation (8000000 joules/m^3).

E = 4.65976636e15 X 8000000
= 3.72781309e22 joules
= 8.909687117590822325 teratons

3. The Butterfly explodes

Pandy & Retro's newborn son becomes an old man and flies into the mouth of the Giant Caterpillar, causing it to turn into a butterfly and explode. Did I mention this movie makes no damn sense? It takes out a huge chunk of the Moon, so we'll be calcing it.

270 pixels = 438.372417km
1 pixel = 438.372417km/270 = 1.62360154km

Timeframe is 7 seconds and 22 frames.

T = 41.6666667ms X 22
= 0.916666667s + 7s
= 7.91666667s

1.62360154km X 532 = 863.756019km

To find the area blown out, we'll need to find the area destroyed. Thankfully, it's a pretty nice circle, but due to the wonkiness of the landscape, we'll be using the same tactic as per the start of this calc to help us find the radius.

R = (h/2) + c^2/(8h)
= (160/2) + 411^2/(8 X 160)
= 211.969531 pixels

1.62360154km X 211.969531 = 344.154057km (344154.057m, or 34415405.7cm)

Now, the distance the debris travelled in the timeframe.

863.756019km - 344.154057km = 519.601962km

T = 519.601962km/7.91666667s
= 65633.932m/s

Volume as a semi-sphere.

V = 4/3πr^3
= 4/3 X π X 34415405.7^3
= 1.70744723e23/2
= 8.53723615e22cm^3

The Moon on average has a mass of 3.34g/cm^3.

M = 8.53723615e22 X 3.34g
= 2.85143687e23g/1000
= 2.85143687e20kg

With all that, we can get our kinetic energy.

KE = (0.5)mv^2
= (0.5) X 2.85143687e20 X 65633.932^2
= 6.14172845e29 joules
= 146.79083293499043793 exatons

Final Results
Dead Leaves facility size = 102.808km
Giant Caterpillar length = >19.739km
Giant Caterpillar bursts out of the ground (speed) = Mach 24.424
Giant Caterpillar bursts out of the ground (energy) = 2.090 teratons
Giant Caterpillars laser beam = Mach 42664.339
Giant Caterpillar destroys Dead Leaves (low end) = 8.91 teratons
Giant Caterpillar destroys Dead Leaves (high end) = 76.846 teratons
Pandy & Retro's Son destroys the Giant Caterpillar = 146.791 exatons

Stocking Anarchy · Feb 8, 2022

Strelizia rips a huge worm Klaxosaur out of the ground. Zero Two is said to be around 170cm (1.7m tall).

438 pixels = 1.7m
1 pixel = 1.7m/438 = 0.00388127854m
0.00388127854m X 79 = 0.306621005m

37 pixels = 0.306621005m
1 pixel = 0.306621005m/37 = 0.00828705419m
0.00828705419m X 1001 = 8.29534124m

83 pixels = 8.29534124m
1 pixel = 8.29534124m/83 = 0.0999438704m
0.0999438704m X 71 = 7.0960148m
0.0999438704m X 550 = 54.9691287m

21 pixels = 7.0960148m
1 pixel = 7.0960148m/21 = 0.337905467m
0.337905467m X 109 = 36.8316959m

17 pixels = 36.8316959m
1 pixel = 36.8316959m/17 = 2.16657035m
2.16657035m X 1975 = 4278.97644m (4.27897644km)

Volume as a rectangle, the hold was deep enough to completely bury Strelizia.

V = lhw
= 4278.97644 X 36.8316959 X 54.9691287
= 8663242.37m^3

Now for the energy to rip up the ground like so. Violent fragmentation of rock is 69000000 joules/m^3.

E = 8663242.37 X 69000000
= 5.97763724e14 joules
= 142.868958891013392 kilotons

Strelizia also destroys the klaxosaur by plowing through its entire body from the inside (above video at 3:45).

5 seconds.

T = 4278.97644m/5s
= 855.795288/340.29
= Mach 2.5148999

Final Results
Strelizia's height = 54.969m
Worm Klaxosaur length = >4.279km
Strelizia rips up worm klaxosaur = 142.869 kilotons
Strelizia destroys worm klaxosaur = Mach 2.515

Stocking Anarchy · Feb 8, 2022

(Episode 22)

Zero-Two's mind's connected to Strelitzia Apus, which is in Mars orbit, and cuts on her appear whenever she's attacked by VIRM ships. Lot's of scaling, so let's get to calcing!

The distance from Earth to Mars at their closest is 54600000km, or 54600000000m. Mars at it's furtherst is 401000000km away, or 401000000000m. The average distance to Mars from Earth is 225000000km, or 225000000000m, so we'll use those as our low end, mid end and high end.
https://www.space.com/24701-how-long-does-it-take-to-get-to-mars.html
Given the light is bright enough to visibly light up the Earth even through dark clouds during the day, then the apparent magnitude should be comparable to that of the Sun, that being −26.74 (though really it's likely even higher given it shone through the clouds easier than the sunlight did).
(Low end)
-26.74 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(54600000000))^2)

Breaking this down bit by bit...

(146000000000/(54600000000))^2) = 7.15023682
-26.74 - -26.73 = 7.15023682/((L/3.846*10^26)
-0.01 = -2.5Log(7.15023682/((L/3.846*10^26))
-0.01/-2.5 = (7.15023682/((L/3.846*10^26))
10^(0.004) = (7.15023682/((L/3.846*10^26))
1.00925289 = (7.15023682/((L/3.846*10^26))
1.00925289 X (3.864*10e26) = 7.15023682
3.89975317e27/7.15023682 = 5.45401959e26 joules

We'll hold onto that for now, let's do our mid and high ends.

(Mid end)

-26.74 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(225000000000))^2)

(146000000000/(225000000000))^2) = 0.42105679
-26.74 - -26.73 = 0.42105679/((L/3.846*10^26)
-0.01 = -2.5Log(0.42105679/((L/3.846*10^26))
-0.01/-2.5 = (0.42105679/((L/3.846*10^26))
10^(0.004) = (0.42105679/((L/3.846*10^26))
1.00925289 = (0.42105679/((L/3.846*10^26))
1.00925289 X (3.864*10e26) = 0.42105679
3.89975317e27/0.42105679 = 9.26182231e27 joules

(High end)

-26.74 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(401000000000))^2)

(146000000000/(401000000000))^2) = 0.132561365
-26.74 - -26.73 = 0.132561365/((L/3.846*10^26)
-0.01 = -2.5Log(0.132561365/((L/3.846*10^26))
-0.01/-2.5 = (0.132561365/((L/3.846*10^26))
10^(0.004) = (0.132561365/((L/3.846*10^26))
1.00925289 = (0.132561365/((L/3.846*10^26))
1.00925289 X (3.864*10e26) = 0.132561365
3.89975317e27/0.132561365 = 2.94184748e28 joules

For our final step, we'll get the timeframe to determine how long the light shone for.

3 seconds.

(Low end)
E = 5.45401959e26 X 3
= 1.63620588e27 joules
= 391.0625908221797431 petatons

(Mid end)
E = 9.26182231e27 X 3
= 2.77854669e28 joules
= 6.6408859703632888341 exotons

(High end)
E = 2.94184748e28 X 3
= 8.82554244e28 joules
= 21.093552676864244859 exotons

And on another note, given that Hiro doesn't wait around for minutes for the flashes to appear in the sky and they appear instantly, the VIRM explosions/attacks would be FTL.

4 seconds.

(Low end)
T = 54600000000m/4s
= 13650000000/299792458
= 45.531499 C

(Mid end)
T = 225000000000m/4s
= 56250000000/299792458
= 187.629804 C

(High end)
T = 4s
= 401000000000/299792458
= 1337.59202 C

Final Results
VIRM ships attack Strelitzia Apus (low end) = 391.063 petatons
VIRM ships attack Strelitzia Apus (mid end) = 6.641 exotons
VIRM ships attack Strelitzia Apus (high end) = 21.094 exotons
VIRM explosions (low end) = 45.531 C
VIRM explosions (mid end) = 187.63 C
VIRM explosions (high end) = 1337.592 C

Stocking Anarchy · Feb 8, 2022

Strelizia flies away and covers an area greater than the plantation, which has a diameter of 3km and a height of 1.2km (or 1200m).

Straight forward enough. Let's find the distance and timeframe in which Strelizia flew.

Timeframe is 2 seconds and 20 frames.

T = 1s/24
= 41.6666667ms X 20
= 0.833333334s + 2s
= 2.83333333s

230 pixels = 1200m
1 pixel = 1200m/230 = 5.2173913m
5.2173913m X 641 = 3344.34782m

T = 3344.34782/340.29
= Mach 9.82793447

Final Results
Strelizia flies away = Mach 9.828

Stocking Anarchy · Feb 8, 2022

Streliztia gets rammed by a Gutenburg class Klaxosaur with enough force to create a colossal dust cloud that dwarves the nearby plantations. Plantations have a height of 1200m.

That makes our job a lot easier. Now, to scaling!

509 pixels = 1200m
1 pixel = 1200m/509 = 2.35756385m
2.35756385m X 639 = 1506.4833m
1506.4833m/2 = 753.24165m
2.35756385m X 1459 = 3439.68566m
3439.68566m/2 = 1719.84283m
2.35756385m X 1590 = 3748.52652m
3748.52652m/2 = 1874.26326m
2.35756385m X 375 = 884.086444m
884.086444m/2 = 442.043222m

Volume of both parts as ellipsoids.

V = 4/3πabc
= 4/3 X π X 753.24165 X 1719.84283 X 753.24165
= 4.08738947e9m^3

V = 4/3πabc
= 4/3 X π X 1874.26326 X 442.043222 X 442.043222
= 1.53408235e9m^3

V = 4.08738947e9 + 1.53408235e9
= 5621471820m^3

Weight of a dust cloud/air is 1.003kg/m^3.

M = 5621471820 X 1.003
= 5.63833624e9kg

Next for our timeframe.

2 seconds and 17 frames.

T = 1s/24
= 41.6666667ms X 17
= 0.708333334s + 2s
= 2.70833333s

T = 3748.52652m/2.70833333s
= 1384.07133m/s

Now for the final step, to get our kinetic energy.

KE = (0.5)mv^2
= (0.5) X 5.63833624e9 X 1384.07133^2
= 5.40054913e15 joules
= 1.290762220363288693 megatons

Final Results
Gutenburg-class Klaxosaur rams Strelitzia = 1.291 megatons

Stocking Anarchy · Feb 8, 2022

(Episode 15)

Strelizia bursts open the ~~giant stone hynem~~ seal to the Gran Crevasse (with help from the 9s). To make our work easier, the official diameter of a plantation is 3km, with a height of 1.2km.

There's a brief shot of different plantations being dwarved by the Grand Crevasse, and we can also get the thickness of the seal here too.

108 pixels = 3km (3000m)
1 pixel = 3000m/108 = 27.7777778m
27.7777778m X 67 = 1861.11111m
27.7777778m X 1193 = 33138.8889m
33138.8889m/2 = 16569.4444m

2038 pixels = 33138.8889m
1 pixel = 33138.8889m/2038 = 16.260495m
16.260495m X 359 = 5837.5177m

Volume as a spherical cap. This is the formula we will be using...
https://byjus.com/spherical-cap-volume-formulas/

V = π/3H^2(3R = H)
Where,
H = height
S = sphere radius
A = base radius
R = sphere radius

V = π/3H^2(3R = H)
= π/3 X 5837.5177^2(3 X 16569.4444 - 5837.5177)
= 1565527663653m^3

The 9s fragment the seal so that Strelizia can break through. Fragmentation of rock is 8000000 joules/m^3, divided by 4 for each of them.

E = 1565527663653 X 8000000
= 1.25242213e19/4
= 3.13105532e18 joules
= 748.34018164435951803 megatons

For our mass, we'll go with a low end of sandstone (2323kg/m^3) and a high end of basalt (3011 kg/m^3)

(Low end)
M = 1565527663653 X 2323
= 3.63672076e15kg

(High end)
M = 1565527663653 X 3011)
= 4.7138038e15kg

Next up we need the distance the fragments travelled (it's a direct continuation of the same scene from the last shot taken, so one pixel would still be 16.260495m).

327 + 988 + 989 = 2304 pixels
16.260495m X 2304 = 37464.1805m

Lastly, we get ourselves the timeframe.

0.97 seconds. Red Strelizia also flew that distance, so we can get the speed of this as well.

T = 37464.1805m/0.97s
= 38622.8665/340.29
= Mach 113.499857

Now, let's get our energy.

(Low end)
KE = (0.5)mv^2
= (0.5) X 3.63672076e15 X 38622.8665^2
= 2.71249512e24 joules
= 648.30189292543025203 teratons

(High end)
KE = (0.5)mv^2
= (0.5) X 4.7138038e15 X 38622.8665^2
= 3.51585141e24 joules
= 840.30865439770559533 teratons

Final Results
The 9s fragment the seal (individual energy) = 748.340 megatons
Strelizia XX breaks through the Grand Crevasse (speed) = Mach 113.5
Strelizia XX breaks through the Grand Crevasse (energy - low end) = 648.302 teratons
Strelizia X breaks through the Grand Crevasse (energy - high end) = 840.309 teratons

From the looks of it Strelizia did the work actually upthrowing the seal into the sky, but even if the 9s were involved in sending it flying upwards, divided between the five of them thats still going to be over a hundred teratons each.

Stocking Anarchy · Feb 8, 2022

The detonation of the Klaxosaur Bomb causes an explosion seen all the way back on Earth. Strelizia True Apus is noted to be so far from Earth that there are no recognisable stars, and the sky and perspective is completely different (there are also noticably more stars in the sky than in space in the Solar System).

But a better indicator of the distance comes several episode earlier during episode 21, when the Klaxosaur Princess is talking about the initial VIRM attack.

We can see at least 6 Spiral galaxies, excluding the Milky Way (the first galaxy is a bit hard to see as it's only visible in the fade in, but you can definately see it there).

This could be a bit tricky to calc the distance for, but we can get a minimum distance scaling from the Milky Way, which has a diameter of 100,000 lightyears, or 9.4605284e20m.

object degree size = 2*atan(Object_Size/(Panel_Height/tan(70/2)))

= 2*atan(314/(1614/tan(70/2)))
= 0.18383961 rad
= 10.533233760357172 degrees

Enter that through the angscaler, and we can determine that the Milky Way is at least 5131600000000000000000m away. The full shot is even further away, but for now let's leave it at that. The light is clearly visible in the middle of the day and from across the Universe, which would mean if'd have to be at least comparable to the luminousity of the Sun. The apparent magnitude of the Sun is -26.74.

-26.74 = -26.73 - 2.5log((L/3.846*10^26)(146000000000/(5131600000000000000000))^2)
(146000000000/(5131600000000000000000))^2) = 8.09468809e-22
-26.74 - -26.73 = 8.09468809e-22/((L/3.846*10^26)
-0.01 = -2.5Log(8.09468809e-22/((L/3.846*10^26))
-0.01/-2.5 = (8.09468809e-22/((L/3.846*10^26))
10^(0.004) = (8.09468809e-22/((L/3.846*10^26))
1.00925289 = (8.09468809e-22/((L/3.846*10^26))
1.00925289 X (3.864*10e26) = 9.46317256e-10
3.89975317e27/8.09468809e-22 = 4.81766947e48 joules

The light lasts 3 days.

T = 60 X 60 X 24 X 3
= 259200s

E = 4.81766947e48 X 259200
= 1.24873993e54/10^44
= 12.487399300 GIGAFOE

Final Results
Klaxosaur Bomb = >12.487 GIGAFOE

Trigger-verse calc archive

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